Wire

Storyboard

The geometry referred to as a wire can be understood as an infinitely long cylinder where the distance to the axis is much greater than the radius of the cylinder. Essentially, this corresponds to a case where the radius approaches zero, effectively becoming an infinitely thin line of charge.

>Model

ID:(2073, 0)



Wire

Storyboard

The geometry referred to as a wire can be understood as an infinitely long cylinder where the distance to the axis is much greater than the radius of the cylinder. Essentially, this corresponds to a case where the radius approaches zero, effectively becoming an infinitely thin line of charge.

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$Q$
Q
Charge
C
$L$
L
Conductor length
m
$\epsilon$
epsilon
Dielectric constant
-
$E_{w1}$
E_w1
Electric field of an infinite wire in 1
V/m
$E_{w2}$
E_w2
Electric field of an infinite wire in 2
V/m
$\varphi_1$
phi_1
Electric potential 1
V
$\varphi_2$
phi_2
Electric potential 2
V
$\lambda$
lambda
Linear charge density
C/m
$m$
m
Particle mass
kg
$r_1$
r_1
Radius 1
m
$r_2$
r_2
Radius 2
m
$r_0$
r_0
Reference radius
m
$v_1$
v_1
Speed 1
m/s
$v_2$
v_2
Speed 2
m/s
$q$
q
Test charge
C

Calculations


First, select the equation:   to ,  then, select the variable:   to 

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

 Variable   Given   Calculate   Target :   Equation   To be used



Equations

In the case of a spherical Gaussian surface, the electric field ($\vec{E}$) is constant in the direction of the versor normal to the section ($\hat{n}$). Therefore, using the charge ($Q$), the electric field constant ($\epsilon_0$), and the dielectric constant ($\epsilon$), it can be calculated by integrating over the surface where the electric field is constant ($dS$):

equation=3213

With the surface ($S$) for a cylinder of the axle distance ($r$) and the conductor length ($L$):

equation=10464

and the linear charge density ($\lambda$) calculated with the charge ($Q$):

equation=11459

Thus,

equation

In the case of a spherical Gaussian surface, the electric field ($\vec{E}$) is constant in the direction of the versor normal to the section ($\hat{n}$). Therefore, using the charge ($Q$), the electric field constant ($\epsilon_0$), and the dielectric constant ($\epsilon$), it can be calculated by integrating over the surface where the electric field is constant ($dS$):

equation=3213

With the surface ($S$) for a cylinder of the axle distance ($r$) and the conductor length ($L$):

equation=10464

and the linear charge density ($\lambda$) calculated with the charge ($Q$):

equation=11459

Thus,

equation

The electric potential, infinite wire ($\varphi_w$) is derived from the radial integration of the electric field of an infinite wire ($E_w$) from the reference radius ($r_0$) to the axle distance ($r$), resulting in the following equation:

equation=15814

Furthermore, for the variables the charge ($Q$), the dielectric constant ($\epsilon$), and the electric field constant ($\epsilon_0$), the value of the electric field of an infinite wire ($E_w$) is given as:

equation=11444

This implies that by performing the integration

$\varphi_w = -\displaystyle\int_{r_0}^r du \displaystyle\frac{ \lambda }{ 2 \pi \epsilon_0 \epsilon u }= -\displaystyle\frac{ \lambda }{ 2 \pi \epsilon_0 \epsilon } \ln\left(\displaystyle\frac{ r }{ r_0 }\right)$



the following equation is obtained:

equation

The electric potential, infinite wire ($\varphi_w$) is derived from the radial integration of the electric field of an infinite wire ($E_w$) from the reference radius ($r_0$) to the axle distance ($r$), resulting in the following equation:

equation=15814

Furthermore, for the variables the charge ($Q$), the dielectric constant ($\epsilon$), and the electric field constant ($\epsilon_0$), the value of the electric field of an infinite wire ($E_w$) is given as:

equation=11444

This implies that by performing the integration

$\varphi_w = -\displaystyle\int_{r_0}^r du \displaystyle\frac{ \lambda }{ 2 \pi \epsilon_0 \epsilon u }= -\displaystyle\frac{ \lambda }{ 2 \pi \epsilon_0 \epsilon } \ln\left(\displaystyle\frac{ r }{ r_0 }\right)$



the following equation is obtained:

equation


Examples


mechanisms

In the case of a spherical Gaussian surface, the electric field ($\vec{E}$) is constant in the direction of the versor normal to the section ($\hat{n}$). Therefore, using the charge ($Q$), the electric field constant ($\epsilon_0$), and the dielectric constant ($\epsilon$), it can be calculated by integrating over the surface where the electric field is constant ($dS$):

equation=3213

With the surface ($S$) for a cylinder of the axle distance ($r$) and the conductor length ($L$):

equation=10464

what is shown in the graph

image

and the linear charge density ($\lambda$) calculated with the charge ($Q$):

equation=11459

Thus,

equation=11444

The electric potential, infinite wire ($\varphi_w$) is derived from the radial integration of the electric field of an infinite wire ($E_w$) from the reference radius ($r_0$) to the axle distance ($r$), resulting in the following equation:

equation=15814

Furthermore, for the variables the charge ($Q$), the dielectric constant ($\epsilon$), and the electric field constant ($\epsilon_0$), the value of the electric field of an infinite wire ($E_w$) is given as:

equation=11444

This implies that by performing the integration

$\varphi_w = -\displaystyle\int_{r_0}^r du \displaystyle\frac{ \lambda }{ 2 \pi \epsilon_0 \epsilon u }= -\displaystyle\frac{ \lambda }{ 2 \pi \epsilon_0 \epsilon } \ln\left(\displaystyle\frac{ r }{ r_0 }\right)$



the following equation is obtained:

equation=15813

As illustrated in the following graph:

image

the field at two points must have the same energy. Therefore, the variables the charge ($Q$), the particle mass ($m$), the speed 1 ($v_1$), the speed 2 ($v_2$), and the electric potential 1 ($\varphi_1$) according to the equation:

equation=15813,1

and the electric potential 2 ($\varphi_2$), according to the equation:

equation=15813,2

must satisfy the following relationship:

equation=11596


model

The electric field of an infinite wire ($E_w$) is a function of the linear charge density ($\lambda$), the axle distance ($r$), the dielectric constant ($\epsilon$) and the electric field constant ($\epsilon_0$) and is calculated through:

kyon

The linear charge density ($\lambda$) is calculated as the charge ($Q$) divided by the conductor length ($L$):

kyon

The electric field of an infinite wire ($E_w$) is a function of the linear charge density ($\lambda$), the axle distance ($r$), the dielectric constant ($\epsilon$) and the electric field constant ($\epsilon_0$) and is calculated through:

kyon

The electric potential, infinite wire ($\varphi_w$) is with the pi ($\pi$), the electric field constant ($\epsilon_0$), the dielectric constant ($\epsilon$), the linear charge density ($\lambda$), the axle distance ($r$) and the reference radius ($r_0$) is equal to:

kyon

The electric potential, infinite wire ($\varphi_w$) is with the pi ($\pi$), the electric field constant ($\epsilon_0$), the dielectric constant ($\epsilon$), the linear charge density ($\lambda$), the axle distance ($r$) and the reference radius ($r_0$) is equal to:

kyon

Electric potentials, which represent potential energy per unit of charge, influence how the velocity of a particle varies. Consequently, due to the conservation of energy between two points, it follows that in the presence of variables the charge ($q$), the particle mass ($m$), the speed 1 ($v_1$), the speed 2 ($v_2$), the electric potential 1 ($\varphi_1$), and the electric potential 2 ($\varphi_2$), the following relationship must be satisfied:

kyon


>Model

ID:(2073, 0)



Mechanisms

Definition


ID:(15792, 0)



Particle in electric field of a wire

Image

In the case of a spherical Gaussian surface, the electric field ($\vec{E}$) is constant in the direction of the versor normal to the section ($\hat{n}$). Therefore, using the charge ($Q$), the electric field constant ($\epsilon_0$), and the dielectric constant ($\epsilon$), it can be calculated by integrating over the surface where the electric field is constant ($dS$):



With the surface ($S$) for a cylinder of the axle distance ($r$) and the conductor length ($L$):

$ S =2 \pi r h $



what is shown in the graph



and the linear charge density ($\lambda$) calculated with the charge ($Q$):



Thus,

ID:(11837, 0)



Particle in electric potencial of a wire

Note

The electric potential, infinite wire ($\varphi_w$) is derived from the radial integration of the electric field of an infinite wire ($E_w$) from the reference radius ($r_0$) to the axle distance ($r$), resulting in the following equation:



Furthermore, for the variables the charge ($Q$), the dielectric constant ($\epsilon$), and the electric field constant ($\epsilon_0$), the value of the electric field of an infinite wire ($E_w$) is given as:



This implies that by performing the integration

$\varphi_w = -\displaystyle\int_{r_0}^r du \displaystyle\frac{ \lambda }{ 2 \pi \epsilon_0 \epsilon u }= -\displaystyle\frac{ \lambda }{ 2 \pi \epsilon_0 \epsilon } \ln\left(\displaystyle\frac{ r }{ r_0 }\right)$



the following equation is obtained:



As illustrated in the following graph:



the field at two points must have the same energy. Therefore, the variables the charge ($Q$), the particle mass ($m$), the speed 1 ($v_1$), the speed 2 ($v_2$), and the electric potential 1 ($\varphi_1$) according to the equation:



and the electric potential 2 ($\varphi_2$), according to the equation:



must satisfy the following relationship:

ID:(11844, 0)



Model

Quote


ID:(15802, 0)