Two plates with opposite charges

Storyboard

The geometry known as parallel plates can be described as two infinite planes that are electrically charged with equal and opposite charges.

>Model

ID:(2076, 0)



Two plates with opposite charges

Storyboard

The geometry known as parallel plates can be described as two infinite planes that are electrically charged with equal and opposite charges.

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$Q$
Q
Charge
C
$\sigma$
sigma
Charge density by area
C/m^2
$\epsilon$
epsilon
Dielectric constant
-
$E_d$
E_d
Electric field, two infinite plates
V/m
$\varphi_1$
phi_1
Electric potential 1
V
$\varphi_2$
phi_2
Electric potential 2
V
$m$
m
Particle mass
kg
$z_1$
z_1
Position at 1
m
$z_2$
z_2
Position at 2
m
$v_1$
v_1
Speed 1
m/s
$v_2$
v_2
Speed 2
m/s
$S$
S
Surface of the conductor
m^2
$q$
q
Test charge
C

Calculations


First, select the equation:   to ,  then, select the variable:   to 

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

 Variable   Given   Calculate   Target :   Equation   To be used



Equations

In the case of a Gaussian surface for a plane, the electric field ($\vec{E}$) is constant in the direction of the versor normal to the section ($\hat{n}$). Therefore, using the variables the charge ($Q$), the electric field constant ($\epsilon_0$), and the dielectric constant ($\epsilon$), it can be calculated by integrating over the surface where the electric field is constant ($dS$):

equation=3213

Additionally, the charge density by area ($\sigma$) is calculated using the surface ($S$) and the charge ($Q$) according to the following equation:

equation=11460

Therefore, it follows that the electric field, two infinite plates ($E_d$) is:

equation

The reference electrical, two infinity plates ($\varphi_d$) in relation to the electric field, two infinite plates ($E_d$) and the position on the z axis ($z$) is given by:

equation=11578

Similarly, the electric field, two infinite plates ($E_d$) in relation to the electric field constant ($\epsilon_0$), the dielectric constant ($\epsilon$), and the charge density by area ($\sigma$) is defined by:

equation=11449

By integrating from the origin, we obtain:

$\varphi_d = -\displaystyle\int_0^z du \displaystyle\frac{ \sigma }{ \epsilon_0 \epsilon }= -\displaystyle\frac{ \sigma }{ \epsilon_0 \epsilon } z$



Thus, the reference electrical, two infinity plates ($\varphi_d$) is given by:

equation

The reference electrical, two infinity plates ($\varphi_d$) in relation to the electric field, two infinite plates ($E_d$) and the position on the z axis ($z$) is given by:

equation=11578

Similarly, the electric field, two infinite plates ($E_d$) in relation to the electric field constant ($\epsilon_0$), the dielectric constant ($\epsilon$), and the charge density by area ($\sigma$) is defined by:

equation=11449

By integrating from the origin, we obtain:

$\varphi_d = -\displaystyle\int_0^z du \displaystyle\frac{ \sigma }{ \epsilon_0 \epsilon }= -\displaystyle\frac{ \sigma }{ \epsilon_0 \epsilon } z$



Thus, the reference electrical, two infinity plates ($\varphi_d$) is given by:

equation


Examples


mechanisms

In the case of a Gaussian surface for a plane, the electric field ($\vec{E}$) is constant in the direction of the versor normal to the section ($\hat{n}$). Therefore, using the variables the charge ($Q$), the electric field constant ($\epsilon_0$), and the dielectric constant ($\epsilon$), it can be calculated by integrating over the surface where the electric field is constant ($dS$):

equation=3213

what is shown in the graph

image

Additionally, the charge density by area ($\sigma$) is calculated using the surface ($S$) and the charge ($Q$) according to the following equation:

equation=11460

Therefore, it follows that the electric field, two infinite plates ($E_d$) is:

equation=11449

The reference electrical, two infinity plates ($\varphi_d$) in relation to the electric field, two infinite plates ($E_d$) and the position on the z axis ($z$) is given by:

equation=11578

Similarly, the electric field, two infinite plates ($E_d$) in relation to the electric field constant ($\epsilon_0$), the dielectric constant ($\epsilon$), and the charge density by area ($\sigma$) is defined by:

equation=11449

By integrating from the origin, we obtain:

$\varphi_d = -\displaystyle\int_0^z du \displaystyle\frac{ \sigma }{ \epsilon_0 \epsilon }= -\displaystyle\frac{ \sigma }{ \epsilon_0 \epsilon } z$



Thus, the reference electrical, two infinity plates ($\varphi_d$) is given by:

equation=11587

As illustrated in the following graph:

image

the field at two points must have the same energy. Therefore, the variables the charge ($Q$), the particle mass ($m$), the speed 1 ($v_1$), the speed 2 ($v_2$), and the electric potential 1 ($\varphi_1$) according to the equation:

equation=11587,1

and the electric potential 2 ($\varphi_2$), according to the equation:

equation=11587,2

must satisfy the following relationship:

equation=11596


model

The surface charge density is calculated by dividing the total charge by the surface area. Therefore, the relationship between the charge density by area ($\sigma$) and the charge ($Q$) with the surface of the conductor ($S$) is established as:

kyon

The electric field, two infinite plates ($E_d$) is with the electric field constant ($\epsilon_0$), the dielectric constant ($\epsilon$) and the charge density by area ($\sigma$) is equal to:

kyon

Electric potentials, which represent potential energy per unit of charge, influence how the velocity of a particle varies. Consequently, due to the conservation of energy between two points, it follows that in the presence of variables the charge ($q$), the particle mass ($m$), the speed 1 ($v_1$), the speed 2 ($v_2$), the electric potential 1 ($\varphi_1$), and the electric potential 2 ($\varphi_2$), the following relationship must be satisfied:

kyon


>Model

ID:(2076, 0)



Mechanisms

Definition


ID:(15795, 0)



Particle in a electric field of a infinite two plate

Image

In the case of a Gaussian surface for a plane, the electric field ($\vec{E}$) is constant in the direction of the versor normal to the section ($\hat{n}$). Therefore, using the variables the charge ($Q$), the electric field constant ($\epsilon_0$), and the dielectric constant ($\epsilon$), it can be calculated by integrating over the surface where the electric field is constant ($dS$):



what is shown in the graph



Additionally, the charge density by area ($\sigma$) is calculated using the surface ($S$) and the charge ($Q$) according to the following equation:



Therefore, it follows that the electric field, two infinite plates ($E_d$) is:

ID:(11836, 0)



Particle in a electric potencial of a infinite two plate

Note

The reference electrical, two infinity plates ($\varphi_d$) in relation to the electric field, two infinite plates ($E_d$) and the position on the z axis ($z$) is given by:



Similarly, the electric field, two infinite plates ($E_d$) in relation to the electric field constant ($\epsilon_0$), the dielectric constant ($\epsilon$), and the charge density by area ($\sigma$) is defined by:



By integrating from the origin, we obtain:

$\varphi_d = -\displaystyle\int_0^z du \displaystyle\frac{ \sigma }{ \epsilon_0 \epsilon }= -\displaystyle\frac{ \sigma }{ \epsilon_0 \epsilon } z$



Thus, the reference electrical, two infinity plates ($\varphi_d$) is given by:



As illustrated in the following graph:



the field at two points must have the same energy. Therefore, the variables the charge ($Q$), the particle mass ($m$), the speed 1 ($v_1$), the speed 2 ($v_2$), and the electric potential 1 ($\varphi_1$) according to the equation:



and the electric potential 2 ($\varphi_2$), according to the equation:



must satisfy the following relationship:

ID:(11843, 0)



Model

Quote


ID:(15805, 0)