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Capacitances in parallel and in series

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In the case of parallel capacitances the potential difference applied is equal for all the capacited. As the potential differences are equal to the load divided by the capacitance, the charge of each capacitance is equal to the product of the potential difference by the capacitance . Being the total load equal to the sum of the loads in each capacitance, it is obtained that the total training is equal to the sum of the individual trainings.

>Model

ID:(2126, 0)



Mechanisms

Iframe

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Code
Concept

Mechanisms

ID:(16040, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
C_1
C_1
Capacity 1
pF
C_2
C_2
Capacity 2
pF
C_3
C_3
Capacity 3
pF
C_p
C_p
Sum capacity in parallel
pF
C_s
C_s
Sum capacity in serie
pF

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
Q
Q
Charge
C
Q_1
Q_1
Charge 1
C
Q_2
Q_2
Charge 2
C
\Delta\varphi_1
Dphi_1
Difference of potential 1
V
\Delta\varphi_3
Dphi_3
Difference of potential 3
V
\Delta\varphi
Dphi
Potential difference
V

Calculations


First, select the equation: to , then, select the variable: to
C_p = C_1 + C_2 Dphi = Dphi_1 + Dphi_3 Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s Q = Q_1 + Q_2 1/ C_s =1/ C_p +1/ C_3 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used
C_p = C_1 + C_2 Dphi = Dphi_1 + Dphi_3 Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s Q = Q_1 + Q_2 1/ C_s =1/ C_p +1/ C_3 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s




Equations

#
Equation

C_p = C_1 + C_2

C_p = C_1 + C_2


\Delta\varphi = \Delta\varphi_1 + \Delta\varphi_3

Dphi = Dphi_1 + Dphi_2


\Delta\varphi_1 =\displaystyle\frac{ Q }{ C_p }

Dphi = Q / C


\Delta\varphi_1 =\displaystyle\frac{ Q_1 }{ C_1 }

Dphi = Q / C


\Delta\varphi_1 =\displaystyle\frac{ Q_2 }{ C_2 }

Dphi = Q / C


\Delta\varphi_3 =\displaystyle\frac{ Q }{ C_3 }

Dphi = Q / C


\Delta\varphi =\displaystyle\frac{ Q }{ C_s }

Dphi = Q / C


Q = Q_1 + Q_2

Q = Q_1 + Q_2


\displaystyle\frac{1}{ C_s }=\displaystyle\frac{1}{ C_p }+\displaystyle\frac{1}{ C_3 }

1/ C_s =1/ C_1 +1/ C_2

ID:(16029, 0)



Sum of series capacities (2)

Equation

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The inverse of the sum capacity in serie (C_s) is calculated as the sum of the inverses of the capacity 1 (C_1) and the capacity 2 (C_2), according to the following relationship:

\displaystyle\frac{1}{ C_s }=\displaystyle\frac{1}{ C_p }+\displaystyle\frac{1}{ C_3 }

\displaystyle\frac{1}{ C_s }=\displaystyle\frac{1}{ C_1 }+\displaystyle\frac{1}{ C_2 }

C_1
C_p
Sum capacity in parallel
F
5511
C_2
C_3
Capacity 3
F
5508
C_s
Sum capacity in serie
F
5510
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(3869, 0)



Sum of parallel capacities (2)

Equation

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The sum capacity in parallel (C_p) is obtained by adding the capacity 1 (C_1) and the capacity 2 (C_2), which can be expressed as:

C_p = C_1 + C_2

C_1
Capacity 1
F
5506
C_2
Capacity 2
F
5507
C_p
Sum capacity in parallel
F
5511
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(3866, 0)



Sum of loads (2)

Equation

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By the principle of charge conservation, the charge (Q) is equal to the sum of the charge 1 (Q_1) and the charge 2 (Q_2). This relationship is expressed as:

Q = Q_1 + Q_2

Q
Charge
C
5459
Q_1
Charge 1
C
10502
Q_2
Charge 2
C
10503
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(16017, 0)



Sum of potential difference (2)

Equation

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By the principle of energy conservation, the potential difference (\Delta\varphi) is equal to the sum of the difference of potential 1 (\Delta\varphi_1) and the difference of potential 2 (\Delta\varphi_2). This can be expressed through the following relationship:

\Delta\varphi = \Delta\varphi_1 + \Delta\varphi_3

\Delta\varphi = \Delta\varphi_1 + \Delta\varphi_2

\Delta\varphi_1
Difference of potential 1
V
5538
\Delta\varphi_2
\Delta\varphi_3
Difference of potential 3
V
10486
\Delta\varphi
Potential difference
V
5477
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(16012, 0)



Equation of a capacitor (1)

Equation

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The potential difference (\Delta\varphi) generates the charge in the capacitor, inducing the charge (Q) on each side (with opposite signs), depending on the capacitor capacity (C), according to the following relationship:

\Delta\varphi_1 =\displaystyle\frac{ Q }{ C_p }

\Delta\varphi =\displaystyle\frac{ Q }{ C }

C
C_p
Sum capacity in parallel
F
5511
Q
Charge
C
5459
\Delta\varphi
\Delta\varphi_1
Difference of potential 1
V
5538
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(3864, 1)



Equation of a capacitor (2)

Equation

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The potential difference (\Delta\varphi) generates the charge in the capacitor, inducing the charge (Q) on each side (with opposite signs), depending on the capacitor capacity (C), according to the following relationship:

\Delta\varphi_1 =\displaystyle\frac{ Q_1 }{ C_1 }

\Delta\varphi =\displaystyle\frac{ Q }{ C }

C
C_1
Capacity 1
F
5506
Q
Q_1
Charge 1
C
10502
\Delta\varphi
\Delta\varphi_1
Difference of potential 1
V
5538
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(3864, 2)



Equation of a capacitor (3)

Equation

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The potential difference (\Delta\varphi) generates the charge in the capacitor, inducing the charge (Q) on each side (with opposite signs), depending on the capacitor capacity (C), according to the following relationship:

\Delta\varphi_1 =\displaystyle\frac{ Q_2 }{ C_2 }

\Delta\varphi =\displaystyle\frac{ Q }{ C }

C
C_2
Capacity 2
F
5507
Q
Q_2
Charge 2
C
10503
\Delta\varphi
\Delta\varphi_1
Difference of potential 1
V
5538
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(3864, 3)



Equation of a capacitor (4)

Equation

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The potential difference (\Delta\varphi) generates the charge in the capacitor, inducing the charge (Q) on each side (with opposite signs), depending on the capacitor capacity (C), according to the following relationship:

\Delta\varphi_3 =\displaystyle\frac{ Q }{ C_3 }

\Delta\varphi =\displaystyle\frac{ Q }{ C }

C
C_3
Capacity 3
F
5508
Q
Charge
C
5459
\Delta\varphi
\Delta\varphi_3
Difference of potential 3
V
10486
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(3864, 4)



Equation of a capacitor (5)

Equation

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The potential difference (\Delta\varphi) generates the charge in the capacitor, inducing the charge (Q) on each side (with opposite signs), depending on the capacitor capacity (C), according to the following relationship:

\Delta\varphi =\displaystyle\frac{ Q }{ C_s }

\Delta\varphi =\displaystyle\frac{ Q }{ C }

C
C_s
Sum capacity in serie
F
5510
Q
Charge
C
5459
\Delta\varphi
Potential difference
V
5477
Dphi_1 = Q / C_p Dphi_1 = Q_1 / C_1 Dphi_1 = Q_2 / C_2 Dphi_3 = Q / C_3 Dphi = Q / C_s C_p = C_1 + C_2 1/ C_s =1/ C_p +1/ C_3 Dphi = Dphi_1 + Dphi_3 Q = Q_1 + Q_2 C_1C_2C_3QQ_1Q_2Dphi_1Dphi_3DphiC_pC_s

ID:(3864, 5)