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Series capacities (2)

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In the case of series capacitance, the applied potential difference generates the same load on all plates, alternating only the sign of these. With this, each capacitance is under a different potential difference whose sum is equal to the potential difference applied. Since the potential differences are equal to the load divided by the capacitance, the inverse of the total capacitance is equal to the sum of the inverses of each capacitance.

>Model

ID:(1393, 0)



Mechanisms

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Code
Concept

Mechanisms

ID:(16036, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
C_1
C_1
Capacity 1
pF
C_2
C_2
Capacity 2
pF
C_s
C_s
Sum capacity in serie
pF

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
Q
Q
Charge
C
\Delta\varphi_1
Dphi_1
Difference of potential 1
V
\Delta\varphi_2
Dphi_2
Difference of potential 2
V
\Delta\varphi
Dphi
Potential difference
V

Calculations


First, select the equation: to , then, select the variable: to
Dphi = Dphi_1 + Dphi_2 Dphi = Q / C_s Dphi_1 = Q / C_1 Dphi_2 = Q / C_2 1/ C_s =1/ C_1 +1/ C_2 C_1C_2QDphi_1Dphi_2DphiC_s

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used
Dphi = Dphi_1 + Dphi_2 Dphi = Q / C_s Dphi_1 = Q / C_1 Dphi_2 = Q / C_2 1/ C_s =1/ C_1 +1/ C_2 C_1C_2QDphi_1Dphi_2DphiC_s




Equations

#
Equation

\Delta\varphi = \Delta\varphi_1 + \Delta\varphi_2

Dphi = Dphi_1 + Dphi_2


\Delta\varphi =\displaystyle\frac{ Q }{ C_s }

Dphi = Q / C


\Delta\varphi_1 =\displaystyle\frac{ Q }{ C_1 }

Dphi = Q / C


\Delta\varphi_2 =\displaystyle\frac{ Q }{ C_2 }

Dphi = Q / C


\displaystyle\frac{1}{ C_s }=\displaystyle\frac{1}{ C_1 }+\displaystyle\frac{1}{ C_2 }

1/ C_s =1/ C_1 +1/ C_2

ID:(16025, 0)



Sum of potential difference (2)

Equation

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By the principle of energy conservation, the potential difference (\Delta\varphi) is equal to the sum of the difference of potential 1 (\Delta\varphi_1) and the difference of potential 2 (\Delta\varphi_2). This can be expressed through the following relationship:

\Delta\varphi = \Delta\varphi_1 + \Delta\varphi_2

\Delta\varphi_1
Difference of potential 1
V
5538
\Delta\varphi_2
Difference of potential 2
V
5539
\Delta\varphi
Potential difference
V
5477
Dphi = Q / C_s Dphi_1 = Q / C_1 Dphi_2 = Q / C_2 1/ C_s =1/ C_1 +1/ C_2 Dphi = Dphi_1 + Dphi_2 C_1C_2QDphi_1Dphi_2DphiC_s

ID:(16012, 0)



Sum of series capacities (2)

Equation

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The inverse of the sum capacity in serie (C_s) is calculated as the sum of the inverses of the capacity 1 (C_1) and the capacity 2 (C_2), according to the following relationship:

\displaystyle\frac{1}{ C_s }=\displaystyle\frac{1}{ C_1 }+\displaystyle\frac{1}{ C_2 }

C_1
Capacity 1
F
5506
C_2
Capacity 2
F
5507
C_s
Sum capacity in serie
F
5510
Dphi = Q / C_s Dphi_1 = Q / C_1 Dphi_2 = Q / C_2 1/ C_s =1/ C_1 +1/ C_2 Dphi = Dphi_1 + Dphi_2 C_1C_2QDphi_1Dphi_2DphiC_s

ID:(3869, 0)



Equation of a capacitor (1)

Equation

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The potential difference (\Delta\varphi) generates the charge in the capacitor, inducing the charge (Q) on each side (with opposite signs), depending on the capacitor capacity (C), according to the following relationship:

\Delta\varphi =\displaystyle\frac{ Q }{ C_s }

\Delta\varphi =\displaystyle\frac{ Q }{ C }

C
C_s
Sum capacity in serie
F
5510
Q
Charge
C
5459
\Delta\varphi
Potential difference
V
5477
Dphi = Q / C_s Dphi_1 = Q / C_1 Dphi_2 = Q / C_2 1/ C_s =1/ C_1 +1/ C_2 Dphi = Dphi_1 + Dphi_2 C_1C_2QDphi_1Dphi_2DphiC_s

ID:(3864, 1)



Equation of a capacitor (2)

Equation

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The potential difference (\Delta\varphi) generates the charge in the capacitor, inducing the charge (Q) on each side (with opposite signs), depending on the capacitor capacity (C), according to the following relationship:

\Delta\varphi_1 =\displaystyle\frac{ Q }{ C_1 }

\Delta\varphi =\displaystyle\frac{ Q }{ C }

C
C_1
Capacity 1
F
5506
Q
Charge
C
5459
\Delta\varphi
\Delta\varphi_1
Difference of potential 1
V
5538
Dphi = Q / C_s Dphi_1 = Q / C_1 Dphi_2 = Q / C_2 1/ C_s =1/ C_1 +1/ C_2 Dphi = Dphi_1 + Dphi_2 C_1C_2QDphi_1Dphi_2DphiC_s

ID:(3864, 2)



Equation of a capacitor (3)

Equation

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The potential difference (\Delta\varphi) generates the charge in the capacitor, inducing the charge (Q) on each side (with opposite signs), depending on the capacitor capacity (C), according to the following relationship:

\Delta\varphi_2 =\displaystyle\frac{ Q }{ C_2 }

\Delta\varphi =\displaystyle\frac{ Q }{ C }

C
C_2
Capacity 2
F
5507
Q
Charge
C
5459
\Delta\varphi
\Delta\varphi_2
Difference of potential 2
V
5539
Dphi = Q / C_s Dphi_1 = Q / C_1 Dphi_2 = Q / C_2 1/ C_s =1/ C_1 +1/ C_2 Dphi = Dphi_1 + Dphi_2 C_1C_2QDphi_1Dphi_2DphiC_s

ID:(3864, 3)