Parallel capacities (3)

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In the case of parallel capacitances the potential difference applied is equal for all the capacited. As the potential differences are equal to the load divided by the capacitance, the charge of each capacitance is equal to the product of the potential difference by the capacitance . Being the total load equal to the sum of the loads in each capacitance, it is obtained that the total training is equal to the sum of the individual trainings.

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ID:(2125, 0)



Mechanisms

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Code
Concept

Mechanisms

ID:(16033, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$C_1$
C_1
Capacity 1
pF
$C_2$
C_2
Capacity 2
pF
$C_3$
C_3
Capacity 3
pF
$C_p$
C_p
Sum capacity in parallel
pF

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$Q$
Q
Charge
C
$Q_1$
Q_1
Charge 1
C
$Q_2$
Q_2
Charge 2
C
$Q_3$
Q_3
Charge 3
C
$\Delta\varphi$
Dphi
Potential difference
V

Calculations


First, select the equation: to , then, select the variable: to

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used




Equations

#
Equation

$ C_p = C_1 + C_2 + C_3 $

C_p = C_1 + C_2 + C_3


$ \Delta\varphi =\displaystyle\frac{ Q }{ C_p }$

Dphi = Q / C


$ \Delta\varphi =\displaystyle\frac{ Q_1 }{ C_1 }$

Dphi = Q / C


$ \Delta\varphi =\displaystyle\frac{ Q_2 }{ C_2 }$

Dphi = Q / C


$ \Delta\varphi =\displaystyle\frac{ Q_3 }{ C_3 }$

Dphi = Q / C


$ Q = Q_1 + Q_2 + Q_3 $

Q = Q_1 + Q_2 + Q_3

ID:(16022, 0)



Sum of parallel capacities (3)

Equation

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The sum capacity in parallel ($C_p$) is obtained by adding the capacity 1 ($C_1$), the capacity 2 ($C_2$) and the capacity 3 ($C_3$), which can be expressed as:

$ C_p = C_1 + C_2 + C_3 $

$C_1$
Capacity 1
$F$
5506
$C_2$
Capacity 2
$F$
5507
$C_3$
Capacity 3
$F$
5508
$C_p$
Sum capacity in parallel
$F$
5511

ID:(3867, 0)



Sum of loads (3)

Equation

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By the principle of charge conservation, the charge ($Q$) is equal to the sum of the charge 1 ($Q_1$),the charge 2 ($Q_2$) and the charge 3 ($Q_3$). This relationship is expressed as:

$ Q = Q_1 + Q_2 + Q_3 $

$Q$
Charge
$C$
5459
$Q_1$
Charge 1
$C$
10502
$Q_2$
Charge 2
$C$
10503
$Q_3$
Charge 3
$C$
10504

ID:(16018, 0)



Equation of a capacitor (1)

Equation

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The potential difference ($\Delta\varphi$) generates the charge in the capacitor, inducing the charge ($Q$) on each side (with opposite signs), depending on the capacitor capacity ($C$), according to the following relationship:

$ \Delta\varphi =\displaystyle\frac{ Q }{ C_p }$

$ \Delta\varphi =\displaystyle\frac{ Q }{ C }$

$C$
$C_p$
Sum capacity in parallel
$F$
5511
$Q$
Charge
$C$
5459
$\Delta\varphi$
Potential difference
$V$
5477

ID:(3864, 1)



Equation of a capacitor (2)

Equation

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The potential difference ($\Delta\varphi$) generates the charge in the capacitor, inducing the charge ($Q$) on each side (with opposite signs), depending on the capacitor capacity ($C$), according to the following relationship:

$ \Delta\varphi =\displaystyle\frac{ Q_1 }{ C_1 }$

$ \Delta\varphi =\displaystyle\frac{ Q }{ C }$

$C$
$C_1$
Capacity 1
$F$
5506
$Q$
$Q_1$
Charge 1
$C$
10502
$\Delta\varphi$
Potential difference
$V$
5477

ID:(3864, 2)



Equation of a capacitor (3)

Equation

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The potential difference ($\Delta\varphi$) generates the charge in the capacitor, inducing the charge ($Q$) on each side (with opposite signs), depending on the capacitor capacity ($C$), according to the following relationship:

$ \Delta\varphi =\displaystyle\frac{ Q_2 }{ C_2 }$

$ \Delta\varphi =\displaystyle\frac{ Q }{ C }$

$C$
$C_2$
Capacity 2
$F$
5507
$Q$
$Q_2$
Charge 2
$C$
10503
$\Delta\varphi$
Potential difference
$V$
5477

ID:(3864, 3)



Equation of a capacitor (4)

Equation

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The potential difference ($\Delta\varphi$) generates the charge in the capacitor, inducing the charge ($Q$) on each side (with opposite signs), depending on the capacitor capacity ($C$), according to the following relationship:

$ \Delta\varphi =\displaystyle\frac{ Q_3 }{ C_3 }$

$ \Delta\varphi =\displaystyle\frac{ Q }{ C }$

$C$
$C_3$
Capacity 3
$F$
5508
$Q$
$Q_3$
Charge 3
$C$
10504
$\Delta\varphi$
Potential difference
$V$
5477

ID:(3864, 4)