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In the case of parallel capacitances the potential difference applied is equal for all the capacited. As the potential differences are equal to the load divided by the capacitance, the charge of each capacitance is equal to the product of the potential difference by the capacitance . Being the total load equal to the sum of the loads in each capacitance, it is obtained that the total training is equal to the sum of the individual trainings.

>Model

ID:(2125, 0)

Iframe

>Top

ID:(16033, 0)

Top

>Top

Parameters

$C_1$

C_1

Capacity 1

pF

$C_2$

C_2

Capacity 2

pF

$C_3$

C_3

Capacity 3

pF

$C_p$

C_p

Sum capacity in parallel

pF

Variables

$Q$

Q

Charge

C

$Q_1$

Q_1

Charge 1

C

$Q_2$

Q_2

Charge 2

C

$Q_3$

Q_3

Charge 3

C

$\Delta\varphi$

Dphi

Potential difference

V

Calculations

• Alternative method
• Traditional method
• Strategy
• 2D
• 3D

Equation

Number

First, select the equation: to , then, select the variable: to

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Calculations

Symbol

Equation

Solved

Translated

Calculations

Symbol

Equation

Solved

Translated

Variable Given Calculate Target : Equation To be used

Equations

ID:(16022, 0)

Equation

>Top, >Model

The sum capacity in parallel ($C_p$) is obtained by adding the capacity 1 ($C_1$), the capacity 2 ($C_2$) and the capacity 3 ($C_3$), which can be expressed as:

$C_p = C_1 + C_2 + C_3$

Conditions

Variables

$C_1$

Capacity 1

$F$

5506

$C_2$

Capacity 2

$F$

5507

$C_3$

Capacity 3

$F$

5508

$C_p$

Sum capacity in parallel

$F$

5511

Relation

ID:(3867, 0)

Equation

>Top, >Model

By the principle of charge conservation, the charge ($Q$) is equal to the sum of the charge 1 ($Q_1$),the charge 2 ($Q_2$) and the charge 3 ($Q_3$). This relationship is expressed as:

$Q = Q_1 + Q_2 + Q_3$

Conditions

Variables

$Q$

Charge

$C$

5459

$Q_1$

Charge 1

$C$

10502

$Q_2$

Charge 2

$C$

10503

$Q_3$

Charge 3

$C$

10504

Relation

ID:(16018, 0)

Equation

>Top, >Model

The potential difference ($\Delta\varphi$) generates the charge in the capacitor, inducing the charge ($Q$) on each side (with opposite signs), depending on the capacitor capacity ($C$), according to the following relationship:

$\Delta\varphi =\displaystyle\frac{ Q }{ C_p }$

$\Delta\varphi =\displaystyle\frac{ Q }{ C }$

Conditions

Variables

$C$

$C_p$

Sum capacity in parallel

$F$

5511

$Q$

Charge

$C$

5459

$\Delta\varphi$

Potential difference

$V$

5477

Relation

ID:(3864, 1)

Equation

>Top, >Model

The potential difference ($\Delta\varphi$) generates the charge in the capacitor, inducing the charge ($Q$) on each side (with opposite signs), depending on the capacitor capacity ($C$), according to the following relationship:

$\Delta\varphi =\displaystyle\frac{ Q_1 }{ C_1 }$

$\Delta\varphi =\displaystyle\frac{ Q }{ C }$

Conditions

Variables

$C$

$C_1$

Capacity 1

$F$

5506

$Q$

$Q_1$

Charge 1

$C$

10502

$\Delta\varphi$

Potential difference

$V$

5477

Relation

ID:(3864, 2)

Equation

>Top, >Model

The potential difference ($\Delta\varphi$) generates the charge in the capacitor, inducing the charge ($Q$) on each side (with opposite signs), depending on the capacitor capacity ($C$), according to the following relationship:

$\Delta\varphi =\displaystyle\frac{ Q_2 }{ C_2 }$

$\Delta\varphi =\displaystyle\frac{ Q }{ C }$

Conditions

Variables

$C$

$C_2$

Capacity 2

$F$

5507

$Q$

$Q_2$

Charge 2

$C$

10503

$\Delta\varphi$

Potential difference

$V$

5477

Relation

ID:(3864, 3)

Equation

>Top, >Model

The potential difference ($\Delta\varphi$) generates the charge in the capacitor, inducing the charge ($Q$) on each side (with opposite signs), depending on the capacitor capacity ($C$), according to the following relationship:

$\Delta\varphi =\displaystyle\frac{ Q_3 }{ C_3 }$

$\Delta\varphi =\displaystyle\frac{ Q }{ C }$

Conditions

Variables

$C$

$C_3$

Capacity 3

$F$

5508

$Q$

$Q_3$

Charge 3

$C$

10504

$\Delta\varphi$

Potential difference

$V$

5477

Relation

ID:(3864, 4)