Permeability of a medium

Storyboard

When working with larger scale media rather than small samples, it is useful to work with quantities similar to densities rather than magnitudes associated with limited volumes. Therefore, the focus is not on flow through a limited volume, but rather on flow densities. Similarly, hydraulic resistances of a finite volume are not considered; instead, permeability is used, which serves a similar role to a density of hydraulic resistance.

>Model

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Flow density between columns

Concept

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As the volume flow ($J_V$), involving the cylinder radio ($R$), the viscosity ($\eta$), the pressure difference ($\Delta p$), and the tube length ($\Delta L$), is modeled using the Hagen-Poiseuille equation:

$ J_V =-\displaystyle\frac{ \pi R ^4}{8 \eta }\displaystyle\frac{ \Delta p }{ \Delta L }$



It is possible to calculate using the section Flow ($S$) and the cylinder radio ($R$) with the following equation:

$ S = \pi r ^2$



Additionally, the flux density ($j_s$) which is defined by

$ j_s = \displaystyle\frac{ J_V }{ S }$



and the definition of the hydrodynamic permeability ($k$) is

$ k = \displaystyle\frac{ R ^2}{8}$



from which it follows:

$ j_s = -\displaystyle\frac{ k }{ \eta }\displaystyle\frac{ \Delta p }{ \Delta L }$

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Volume Flow and its Speed

Equation

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A flux density ($j_s$) can be expressed in terms of the volume flow ($J_V$) using the section or Area ($S$) through the following formula:

$ j_s = \displaystyle\frac{ J_V }{ S }$

$j_s$
Flux density
$m/s$
7220
$S$
Section Flow
$m^2$
6011
$J_V$
Volume flow
$m^3/s$
5448

Flow is defined as the volume the volume element ($\Delta V$) divided by time the time elapsed ($\Delta t$), which is expressed in the following equation:

$ J_V =\displaystyle\frac{ \Delta V }{ \Delta t }$



and the volume equals the cross-sectional area the section Tube ($S$) multiplied by the distance traveled the tube element ($\Delta s$):

$ \Delta V = S \Delta s $



Since the distance traveled the tube element ($\Delta s$) per unit time the time elapsed ($\Delta t$) corresponds to the velocity, it is represented by:

$ j_s =\displaystyle\frac{ \Delta s }{ \Delta t }$



Thus, the flow is a flux density ($j_s$), which is calculated using:

$ j_s = \displaystyle\frac{ J_V }{ S }$

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Surface of a disk

Equation

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The surface of a disk ($S$) of ($$) is calculated as follows:

$ S = \pi r ^2$

$r$
Disc radius
$m$
5275
$\pi$
Pi
3.1415927
$rad$
5057
$S$
Surface of a disk
$m^2$
10361

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Hydraulic permeability

Equation

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The remaining factor is called the hydrodynamic permeability ($k$) and can be calculated using the cylinder radio ($R$) with the following formula:

$ k = \displaystyle\frac{ R ^2}{8}$

$R$
Cylinder radio
$m$
5417
$k$
Hydrodynamic permeability
$m^2$
10137

If we examine the hydraulic conductance ($G_h$), we can notice that the numerator contains the cross-sectional area of the tube, represented as $\pi R^2$. Here, the cylinder radio ($R$) corresponds to a property of the liquid, the viscosity ($\eta$) is related to the viscosity of the fluid, and the tube length ($\Delta L$) refers to the generated pressure gradient.

$ G_h =\displaystyle\frac{ \pi R ^4}{8 \eta | \Delta L | }$



Thus, the factor specific to the geometry of the pores can be defined as the hydrodynamic permeability ($k$) using the following formula:

$ k = \displaystyle\frac{ R ^2}{8}$

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Flow under hydrostatic pressure

Equation

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The Hagen Poiseuille equation can be rewritten as a function of the flux density ($j_s$) in terms of the hydrodynamic permeability ($k$), the viscosity ($\eta$) and the gradient of the pressure difference ($\Delta p$) > and the tube length ($\Delta L$):

$ j_s = -\displaystyle\frac{ k }{ \eta }\displaystyle\frac{ \Delta p }{ \Delta L }$

$j_s$
Flux density
$m/s$
7220
$k$
Hydrodynamic permeability
$m^2$
10137
$\Delta p$
Pressure difference
$Pa$
10117
$\Delta L$
Tube length
$m$
5430
$\eta$
Viscosity
$Pa s$
5422

As the volume flow ($J_V$), involving the cylinder radio ($R$), the viscosity ($\eta$), the pressure difference ($\Delta p$), and the tube length ($\Delta L$), is modeled using the Hagen-Poiseuille equation:

$ J_V =-\displaystyle\frac{ \pi R ^4}{8 \eta }\displaystyle\frac{ \Delta p }{ \Delta L }$



It is possible to calculate using the section Flow ($S$) and the cylinder radio ($R$) with the following equation:

$ S = \pi r ^2$



Additionally, the flux density ($j_s$) which is defined by

$ j_s = \displaystyle\frac{ J_V }{ S }$



and the definition of the hydrodynamic permeability ($k$) is

$ k = \displaystyle\frac{ R ^2}{8}$



from which it follows:

$ j_s = -\displaystyle\frac{ k }{ \eta }\displaystyle\frac{ \Delta p }{ \Delta L }$

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Pressure difference between columns

Equation

>Top, >Model


The height difference, denoted by the height difference ($\Delta h$), implies that the pressure in both columns is distinct. In particular, the pressure difference ($\Delta p$) is a function of the liquid density ($\rho_w$), the gravitational Acceleration ($g$), and the height difference ($\Delta h$), as follows:

$ \Delta p = \rho_w g \Delta h $

$g$
Gravitational Acceleration
9.8
$m/s^2$
5310
$\Delta h$
Height or depth difference
$m$
5819
$\rho_w$
Liquid density
$kg/m^3$
5407
$\Delta p$
Variación de la Presión
$Pa$
6673

If there is the pressure difference ($\Delta p$) between two points, as determined by the equation:

$ \Delta p = p_2 - p_1 $



we can utilize the water column pressure ($p$), which is defined as:

$ p_t = p_0 + \rho_w g h $



This results in:

$\Delta p=p_2-p_1=p_0+\rho_wh_2g-p_0-\rho_wh_1g=\rho_w(h_2-h_1)g$



As the height difference ($\Delta h$) is:

$ \Delta h = h_2 - h_1 $



the pressure difference ($\Delta p$) can be expressed as:

$ \Delta p = \rho_w g \Delta h $

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