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Resistors in series (2)

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When several resistors are connected in series, the current is the same in all resistors due to the conservation of loads. Therefore, in each resistance a potential drop equal to the electrical resistance multiplied by the current is experienced and whose sum must be the total potential difference. Therefore, the total resistance of a series of resistors is equal to the sum of these.

>Model

ID:(1396, 0)



Mechanisms

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Code
Concept

Mechanisms

ID:(16030, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
R_1
R_1
Resistance 1
Ohm
R_2
R_2
Resistance 2
Ohm
R_s
R_s
Resistance in Series
Ohm

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
I
I
Current
A
\Delta\varphi_1
Dphi_1
Difference of potential 1
V
\Delta\varphi_2
Dphi_2
Difference of potential 2
V
\Delta\varphi
Dphi
Potential difference
V

Calculations


First, select the equation: to , then, select the variable: to
Dphi = Dphi_1 + Dphi_2 Dphi = R_s * I Dphi_1 = R_1 * I Dphi_2 = R_2 * I R_s = R_1 + R_2 IDphi_1Dphi_2DphiR_1R_2R_s

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used
Dphi = Dphi_1 + Dphi_2 Dphi = R_s * I Dphi_1 = R_1 * I Dphi_2 = R_2 * I R_s = R_1 + R_2 IDphi_1Dphi_2DphiR_1R_2R_s




Equations

#
Equation

\Delta\varphi = \Delta\varphi_1 + \Delta\varphi_2

Dphi = Dphi_1 + Dphi_2


\Delta\varphi = R_s I

Dphi = R * I


\Delta\varphi_1 = R_1 I

Dphi = R * I


\Delta\varphi_2 = R_2 I

Dphi = R * I


R_s = R_1 + R_2

R_s = R_1 + R_2

ID:(16019, 0)



Series resistance (2)

Equation

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In the case of two resistors connected in series, the resistance in Series (R_s) is equal to the sum of the resistance 1 (R_1) and the resistance 2 (R_2). This relationship is expressed as:

R_s = R_1 + R_2

R_1
Resistance 1
Ohm
5500
R_2
Resistance 2
Ohm
5501
R_s
Resistance in Series
Ohm
5498
Dphi = R_s * I Dphi_1 = R_1 * I Dphi_2 = R_2 * I R_s = R_1 + R_2 Dphi = Dphi_1 + Dphi_2 IDphi_1Dphi_2DphiR_1R_2R_s

None

ID:(16004, 0)



Sum of potential difference (2)

Equation

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By the principle of energy conservation, the potential difference (\Delta\varphi) is equal to the sum of the difference of potential 1 (\Delta\varphi_1) and the difference of potential 2 (\Delta\varphi_2). This can be expressed through the following relationship:

\Delta\varphi = \Delta\varphi_1 + \Delta\varphi_2

\Delta\varphi_1
Difference of potential 1
V
5538
\Delta\varphi_2
Difference of potential 2
V
5539
\Delta\varphi
Potential difference
V
5477
Dphi = R_s * I Dphi_1 = R_1 * I Dphi_2 = R_2 * I R_s = R_1 + R_2 Dphi = Dphi_1 + Dphi_2 IDphi_1Dphi_2DphiR_1R_2R_s

ID:(16012, 0)



Ohm's law (1)

Equation

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Traditional Ohm's law establishes a relationship between the potential difference (\Delta\varphi) and the current (I) through the resistance (R), using the following expression:

\Delta\varphi = R_s I

\Delta\varphi = R I

I
Current
A
5483
\Delta\varphi
Potential difference
V
5477
R
R_s
Resistance in Series
Ohm
5498
Dphi = R_s * I Dphi_1 = R_1 * I Dphi_2 = R_2 * I R_s = R_1 + R_2 Dphi = Dphi_1 + Dphi_2 IDphi_1Dphi_2DphiR_1R_2R_s

None

ID:(3214, 1)



Ohm's law (2)

Equation

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Traditional Ohm's law establishes a relationship between the potential difference (\Delta\varphi) and the current (I) through the resistance (R), using the following expression:

\Delta\varphi_1 = R_1 I

\Delta\varphi = R I

I
Current
A
5483
\Delta\varphi
\Delta\varphi_1
Difference of potential 1
V
5538
R
R_1
Resistance 1
Ohm
5500
Dphi = R_s * I Dphi_1 = R_1 * I Dphi_2 = R_2 * I R_s = R_1 + R_2 Dphi = Dphi_1 + Dphi_2 IDphi_1Dphi_2DphiR_1R_2R_s

None

ID:(3214, 2)



Ohm's law (3)

Equation

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Traditional Ohm's law establishes a relationship between the potential difference (\Delta\varphi) and the current (I) through the resistance (R), using the following expression:

\Delta\varphi_2 = R_2 I

\Delta\varphi = R I

I
Current
A
5483
\Delta\varphi
\Delta\varphi_2
Difference of potential 2
V
5539
R
R_2
Resistance 2
Ohm
5501
Dphi = R_s * I Dphi_1 = R_1 * I Dphi_2 = R_2 * I R_s = R_1 + R_2 Dphi = Dphi_1 + Dphi_2 IDphi_1Dphi_2DphiR_1R_2R_s

None

ID:(3214, 3)