Parallel resistance (2)

Storyboard

When the resistors are connected in parallel, they are all exposed to the same potential difference which, by Ohm's law, generates different currents. The total current is the sum of the partial currents, so the total resistance is the inverse of the sum of the inverse of the individual resistances.

>Model

ID:(1397, 0)



Mechanisms

Iframe

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Code
Concept

Mechanisms

ID:(16032, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$R_1$
R_1
Resistance 1
Ohm
$R_2$
R_2
Resistance 2
Ohm
$R_p$
R_p
Resistance in Parallel
Ohm

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$I$
I
Current
A
$I_1$
I_1
Current 1
A
$I_2$
I_2
Current 2
A
$\Delta\varphi$
Dphi
Potential difference
V

Calculations


First, select the equation: to , then, select the variable: to

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used




Equations

#
Equation

$ \Delta\varphi = R_p I $

Dphi = R * I


$ \Delta\varphi = R_1 I_1 $

Dphi = R * I


$ \Delta\varphi = R_2 I_2 $

Dphi = R * I


$ I = I_1 + I_2 $

I = I_1 + I_2


$\displaystyle\frac{1}{ R_p }=\displaystyle\frac{1}{ R_1 }+\displaystyle\frac{1}{ R_2 }$

1/ R_p =1/ R_1 + 1/ R_2

ID:(16021, 0)



Resistance in parallel (2)

Equation

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The inverse of the resistance in Parallel ($R_p$) is equal to the sum of the inverses of the resistance 1 ($R_1$) and the resistance 2 ($R_2$). This relationship is expressed as:

$\displaystyle\frac{1}{ R_p }=\displaystyle\frac{1}{ R_1 }+\displaystyle\frac{1}{ R_2 }$

$R_1$
Resistance 1
$Ohm$
5500
$R_2$
Resistance 2
$Ohm$
5501
$R_p$
Resistance in Parallel
$Ohm$
5499

ID:(16006, 0)



Sum of currents (2)

Equation

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By the principle of conservation of electric charge, the current ($I$) is equal to the sum of the current 1 ($I_1$) and the current 2 ($I_2$). This relationship is expressed as:

$ I = I_1 + I_2 $

$I$
Current
$A$
5483
$I_1$
Current 1
$A$
9677
$I_2$
Current 2
$A$
9678

ID:(16009, 0)



Ohm's law (1)

Equation

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Traditional Ohm's law establishes a relationship between the potential difference ($\Delta\varphi$) and the current ($I$) through the resistance ($R$), using the following expression:

$ \Delta\varphi = R_p I $

$ \Delta\varphi = R I $

$I$
Current
$A$
5483
$\Delta\varphi$
Potential difference
$V$
5477
$R$
$R_p$
Resistance in Parallel
$Ohm$
5499

None

ID:(3214, 1)



Ohm's law (2)

Equation

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Traditional Ohm's law establishes a relationship between the potential difference ($\Delta\varphi$) and the current ($I$) through the resistance ($R$), using the following expression:

$ \Delta\varphi = R_1 I_1 $

$ \Delta\varphi = R I $

$I$
$I_1$
Current 1
$A$
9677
$\Delta\varphi$
Potential difference
$V$
5477
$R$
$R_1$
Resistance 1
$Ohm$
5500

None

ID:(3214, 2)



Ohm's law (3)

Equation

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Traditional Ohm's law establishes a relationship between the potential difference ($\Delta\varphi$) and the current ($I$) through the resistance ($R$), using the following expression:

$ \Delta\varphi = R_2 I_2 $

$ \Delta\varphi = R I $

$I$
$I_2$
Current 2
$A$
9678
$\Delta\varphi$
Potential difference
$V$
5477
$R$
$R_2$
Resistance 2
$Ohm$
5501

None

ID:(3214, 3)