
Parallel resistance (3)
Storyboard 
When the resistors are connected in parallel, they are all exposed to the same potential difference which, by Ohm's law, generates different currents. The total current is the sum of the partial currents, so the total resistance is the inverse of the sum of the inverse of the individual resistances.
ID:(2120, 0)

Model
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Parameters

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Calculations




Calculations
Calculations







Equations
\Delta\varphi = R_p I
Dphi = R * I
\Delta\varphi = R_1 I_1
Dphi = R * I
\Delta\varphi = R_2 I_2
Dphi = R * I
\Delta\varphi = R_3 I_3
Dphi = R * I
I = I_1 + I_2 + I_3
I = I_1 + I_2 + I_3
\displaystyle\frac{1}{ R_p }=\displaystyle\frac{1}{ R_1 }+\displaystyle\frac{1}{ R_2 }+\displaystyle\frac{1}{ R_3 }
1/ R_p =1/ R_1 + 1/ R_2 + 1/ R_3
ID:(16022, 0)

Resistance in parallel (3)
Equation 
The inverse of the resistance in Parallel (R_p) is equal to the sum of the inverses of the resistance 1 (R_1), the resistance 2 (R_2) and the resistance 3 (R_3). This relationship is expressed as:
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ID:(16007, 0)

Sum of currents (3)
Equation 
By the principle of conservation of electric charge, the current (I) is equal to the sum of the current 1 (I_1), the current 2 (I_2) and the current 3 (I_3). This relationship is expressed as:
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ID:(16010, 0)

Ohm's law (1)
Equation 
Traditional Ohm's law establishes a relationship between the potential difference (\Delta\varphi) and the current (I) through the resistance (R), using the following expression:
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None
ID:(3214, 1)

Ohm's law (2)
Equation 
Traditional Ohm's law establishes a relationship between the potential difference (\Delta\varphi) and the current (I) through the resistance (R), using the following expression:
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None
ID:(3214, 2)

Ohm's law (3)
Equation 
Traditional Ohm's law establishes a relationship between the potential difference (\Delta\varphi) and the current (I) through the resistance (R), using the following expression:
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None
ID:(3214, 3)

Ohm's law (4)
Equation 
Traditional Ohm's law establishes a relationship between the potential difference (\Delta\varphi) and the current (I) through the resistance (R), using the following expression:
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![]() |
None
ID:(3214, 4)