Landing

Storyboard

The key to landing is to modify the wing in a way that achieves sufficient lift at lower speeds, allowing for a controlled descent to reach the runway and bring the aircraft to a stop on the available runway.

>Model

ID:(1968, 0)



Landing

Storyboard

The key to landing is to modify the wing in a way that achieves sufficient lift at lower speeds, allowing for a controlled descent to reach the runway and bring the aircraft to a stop on the available runway.

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$m$
m
Body mass
kg
$C_W$
C_W
Coefficient of resistance
-
$\rho$
rho
Density
kg/m^3
$s_L$
s_L
Landing Distance
m
$v_L$
v_L
Landing speed
m/s
$t_L$
t_L
Landing time
s
$a_p$
a_p
Maximum acceleration
m/s^2
$v_p$
v_p
Maximum speed
m/s
$s$
s
Path taken on the strip
m
$F_p$
F_p
Propulsion force
N
$F_W$
F_W
Resistance force
N
$v$
v
Speed with respect to the medium
m/s
$\tau_p$
tau_p
Takeoff/landing propulsion time
s
$t$
t
Time
s
$S_p$
S_p
Total object profile
m^2

Calculations


First, select the equation:   to ,  then, select the variable:   to 

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

 Variable   Given   Calculate   Target :   Equation   To be used



Equations

Similarly to how the equation for the lift force ($F_L$) was derived using the density ($\rho$), the coefficient of lift ($C_L$), the surface that generates lift ($S_w$), and the speed with respect to the medium ($v$)

equation=4417

in this analogy, what corresponds to the surface that generates lift ($S_w$) will be equivalent to the total object profile ($S_p$) and the coefficient of lift ($C_L$) to the coefficient of resistance ($C_W$), thus the resistance force ($F_W$) is calculated:

equation

The drag coefficient is measured and, in turbulent flows over aerodynamic bodies, values are generally found around 0.4.

If we equate the propulsion force ($F_p$) with the resistance force ($F_W$) with the total object profile ($S_p$), the coefficient of resistance ($C_W$), the density ($\rho$), and the speed with respect to the medium ($v$) in

equation=4418

we obtain, for a the maximum speed ($v_p$),

$F_p = \displaystyle\frac{1}{2} \rho S_w C_L v_p ^2$



which, when solved for the maximum velocity, results in

equation

With the equation for the speed with respect to the medium ($v$) in the takeoff time ($t$) with the maximum acceleration ($a_p$) and the maximum speed ($v_p$):

equation=15159

it can be integrated from an initial value of the landing speed ($v_L$)

$\displaystyle\int_{v_L}^v \displaystyle\frac{dv}{1 - v^2/v_p^2} = -\displaystyle\int_0^t dt a_p$



and with the definition of the takeoff/landing propulsion time ($\tau_p$)

equation=14510

the result is

equation

With the equation ERROR:6110,0 using the landing speed ($v_L$), the maximum speed ($v_p$), the takeoff/landing propulsion time ($\tau_p$), and the takeoff time ($t$) as follows:

equation=14511

where in the takeoff time ($t$) is equal to the landing time ($t_L$), we have:

$v = v_L - v_p \tan\left(\displaystyle\frac{t_L}{\tau_p}\right)=0$



If we solve this equation for time, we obtain:

equation

Since the speed with respect to the medium ($v$) during landing varies with respect to the takeoff time ($t$) with the landing speed ($v_L$), the maximum speed ($v_p$), and the takeoff/landing propulsion time ($\tau_p$) according to the equation:

equation=14511

it is equal to the path taken on the strip ($s$) as a function of the takeoff time ($t$).

We can integrate the equation:

$\displaystyle\frac{ds}{dt}=v_0-v_p\tan\left(\displaystyle\frac{t}{\tau_p}\right)$



Obtaining the path as:

$s = v_L t + \log(|\cos( t / \tau_p)|) v_p \tau_p$



If the takeoff time ($t$), the logarithmic factor can be expanded up to the third order, resulting in the landing path being equal to:

equation


Examples


mechanisms

Airplanes use three mechanisms to brake during landing:

• Thrust reversal, which involves redirecting the engine thrust forward instead of backward.
• Wing spoilers, which increase the coefficient of drag by exposing a surface to the airflow.
• Conventional wheel brakes.

image

The image below shows two types of thrust reversers: the first one uses a deflector that is moved into the airflow exiting the engine, while the second one directly deflects the flow forward.


model

The resistance force ($F_W$) kann mit the density ($\rho$), the coefficient of resistance ($C_W$), the total object profile ($S_p$) und the speed with respect to the medium ($v$) entsprechend berechnet werden folgende Formel:

kyon

At the beginning of takeoff, aerodynamic resistance, which depends on velocity, is minimal. Therefore, the maximum acceleration ($a_p$) is determined solely by the propulsion force ($F_p$) and the body mass ($m$):

kyon

As aerodynamic resistance starts to reduce the propulsion force, this initial acceleration will be the maximum possible.

The propulsion force ($F_p$) counteracts the resistance force ($F_W$) by generating velocity, which in turn increases the same resistance force, as described in the total object profile ($S_p$), the coefficient of resistance ($C_W$), the density ($\rho$), and the speed with respect to the medium ($v$) in

equation=4418

This process continues to increase the velocity until the point where the propulsion force equals the resistance force, representing the maximum achievable speed.

By equating the propulsion force with the resistance force and solving for velocity, we obtain the maximum speed ($v_p$):

kyon

As aerodynamic resistance starts to reduce the propulsion force, this initial acceleration will be the maximum possible.

With the acceleration generated by the engines, represented as

equation=14506

and the maximum velocity associated with the resistance, described by

equation=14507

we can define a characteristic time using the following expression:

kyon

This time provides an estimate of the order of magnitude of the takeoff and landing process, which typically occurs within a few minutes.

The equation to calculate the speed with respect to the medium ($v$) in the takeoff time ($t$) with the maximum acceleration ($a_p$) and the maximum speed ($v_p$) is as follows:

equation=15159

Upon integration, it results in the takeoff/landing propulsion time ($\tau_p$) and the landing speed ($v_L$).

kyon

At the beginning, when the time is much smaller than the characteristic time, the tangent can be replaced by its argument. This implies that the velocity primarily decreases due to the influence of the engines.

The equation for ERROR:6110,0 for an aircraft during landing is given with the landing speed ($v_L$), the maximum speed ($v_p$), the takeoff/landing propulsion time ($\tau_p$), and the takeoff time ($t$) as follows:

equation=14511

Therefore, the landing time ($t_L$) is calculated using this equation for the case when the velocity at that moment is zero. This translates to:

kyon

Given that the speed with respect to the medium ($v$) during landing varies with respect to the takeoff time ($t$) with the landing speed ($v_L$), the maximum speed ($v_p$), and the takeoff/landing propulsion time ($\tau_p$) according to the equation:

equation=14511

we can calculate the distance traveled along the runway by integrating this equation over time:

kyon

The resulting equation is a third-order approximation of $t/\tau_p$, which means that aerodynamic aids for braking are significantly reduced compared to engine thrust reversal.

Furthermore, we can use the landing time to estimate the required runway length for landing.

The landing concludes when the speed with respect to the medium ($v$) becomes zero, which implies that the time ($t$) equals the landing time ($t_L$), resulting in a reduction of the path taken on the strip ($s$) to the landing Distance ($s_L$). Therefore, with the maximum acceleration ($a_p$) and the landing speed ($v_L$), the following is obtained:

kyon


>Model

ID:(1968, 0)



Mechanisms

Definition


ID:(15174, 0)



Landing braking

Image

Airplanes use three mechanisms to brake during landing:

• Thrust reversal, which involves redirecting the engine thrust forward instead of backward.
• Wing spoilers, which increase the coefficient of drag by exposing a surface to the airflow.
• Conventional wheel brakes.

[1] Review of Thrust Reverser Mechanism used in Turbofan Jet Engine Aircraft, Mohd Anees Siddiqui, Md Shakibul Haq, International Journal of Engineering Research and Technology, Volume 6, Number 5 (2013), pp. 717-726, diagrams [2] Michael Fabry, F-GHXX Boeing 737-2A1(Adv) Some reverse thrust action during a very rainy day, (jetphotos.com) - center, left [3] N90024 American Airlines Airbus A319-115(WL), AIRCANADA087, (planespotters.net) - center, right

The image below shows two types of thrust reversers: the first one uses a deflector that is moved into the airflow exiting the engine, while the second one directly deflects the flow forward.

ID:(14476, 0)



Model

Note


ID:(15187, 0)