Sistema Circulatorio

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ID:(330, 0)



Total Pressure difference of series resistors (2)

Equation

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In the case of hydraulic resistances in series, the pressure drops across each of them, and the sum of these pressure drops is equal to the total pressure difference across the entire series.

For two resistances in series, the hydraulic Resistance 1 ($R_{h1}$) and the hydraulic Resistance 2 ($R_{h2}$), with their respective pressure drops the pressure Difference 1 ($\Delta p_1$) and the pressure Difference 2 ($\Delta p_2$), the sum of these drops equals the total pressure difference the total pressure difference ($\Delta p_t$):

$ \Delta p_t = \Delta p_1 + \Delta p_2 $

$\Delta p_1$
Pressure Difference 1
$Pa$
9841
$\Delta p_2$
Pressure Difference 2
$Pa$
5820
$\Delta p_t$
Total pressure difference
$Pa$
9842

ID:(9943, 0)



Structure of Blood

Image

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ID:(1894, 0)



Average speed in the Section

Concept

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A flow through a section travels with a speed that can vary over it. However, an average speed can be defined simply by considering the total flow through the section.

ID:(9479, 0)



Liquid or Gas Flow

Concept

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The flow of a liquid or gas corresponds to the volume of this flowing through a section in a given time.

The units in which it is measured is in unit of volume per unit of time such as in cubic meters per second or liters per minute.

ID:(9478, 0)



Mean volume flow

Equation

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The volume flow ($J_V$) corresponds to the volume flowing ($\Delta V$) flowing through the channel at the time elapsed ($\Delta t$). Therefore, we have:

$ J_V =\displaystyle\frac{ \Delta V }{ \Delta t }$

$\Delta t$
Time elapsed
$s$
5103
$\Delta V$
Volume element
$m^3$
10290
$J_V$
Volume flow
$m^3/s$
5448

ID:(4347, 0)



Flow density

Equation

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If you have a total flow J_V that passes through a section S you can define a flow density by dividing this by the section:

$ j_V =\displaystyle\frac{ J_V }{ S }$

$j_V$
Density Volume Flow
$m/s$
5824
$S$
Section Tube
$m^2$
6267
$J_V$
Volume flow
$m^3/s$
5448

ID:(4256, 0)



Simulador

Php

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El siguiente simulador logra modelar lo que es el flujo de sangre por el sistema circulatorio.

Las curvas finales muestran como se distribuyen los radios, largos, numero de vasos, como va cayendo la presión desde la sístole a la dístole y el flujo que se observa si se tiene una herida según el vaso.

ID:(8018, 0)



Flow in Birfucation

Equation

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$J_{VN}=\displaystyle\frac{J_V}{N}$

ID:(3805, 0)



Darcy's law and hydraulic resistance

Equation

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Darcy rewrites the Hagen Poiseuille equation so that the pressure difference ($\Delta p$) is equal to the hydraulic resistance ($R_h$) times the volume flow ($J_V$):

$ \Delta p = R_h J_V $

$R_h$
Hydraulic resistance
$kg/m^4s$
5424
$\Delta p$
Variación de la Presión
$Pa$
6673
$J_V$
Volume flow
$m^3/s$
5448

The volume flow ($J_V$) can be calculated from the hydraulic conductance ($G_h$) and the pressure difference ($\Delta p$) using the following equation:

$ J_V = G_h \Delta p $



Furthermore, using the relationship for the hydraulic resistance ($R_h$):

$ R_h = \displaystyle\frac{1}{ G_h }$



results in:

$ \Delta p = R_h J_V $

ID:(3179, 0)



Branching Ratio

Equation

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$n_{i+1}=\displaystyle\frac{N_{i+1}}{N_i}$

ID:(3803, 0)



Hydraulic resistance of a tube

Equation

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Since the hydraulic resistance ($R_h$) is equal to the inverse of the hydraulic conductance ($G_h$), it can be calculated from the expression of the latter. In this way, we can identify parameters related to geometry (the tube length ($\Delta L$) and the tube radius ($R$)) and the type of liquid (the viscosity ($\eta$)), which can be collectively referred to as a hydraulic resistance ($R_h$):

$ R_h =\displaystyle\frac{8 \eta | \Delta L | }{ \pi R ^4}$

$R_h$
Hydraulic resistance
$kg/m^4s$
5424
$\pi$
Pi
3.1415927
$rad$
5057
$\Delta L$
Tube length
$m$
5430
$R$
Tube radius
$m$
5417
$\eta$
Viscosity
$Pa s$
5422

Since the hydraulic resistance ($R_h$) is equal to the hydraulic conductance ($G_h$) as per the following equation:

$ R_h = \displaystyle\frac{1}{ G_h }$



and since the hydraulic conductance ($G_h$) is expressed in terms of the viscosity ($\eta$), the tube radius ($R$), and the tube length ($\Delta L$) as follows:

$ G_h =\displaystyle\frac{ \pi R ^4}{8 \eta | \Delta L | }$



we can conclude that:

$ R_h =\displaystyle\frac{8 \eta | \Delta L | }{ \pi R ^4}$

ID:(3629, 0)



Hydraulic resistance of elements in series

Equation

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When there are multiple hydraulic resistances connected in series, we can calculate the total hydraulic resistance in series ($R_{st}$) by summing the hydraulic resistance in a network ($R_{hk}$), as expressed in the following formula:

$ R_{st} =\displaystyle\sum_k R_{hk} $

$R_{hk}$
Hydraulic resistance in a network
$kg/m^4s$
9887
$R_{st}$
Total hydraulic resistance in series
$kg/m^4s$
5428

One way to model a tube with varying cross-section is to divide it into sections with constant radius and then sum the hydraulic resistances in series. Suppose we have a series of the hydraulic resistance in a network ($R_{hk}$), which depends on the viscosity ($\eta$), the cylinder k radio ($R_k$), and the tube k length ($\Delta L_k$) via the following equation:

$ R_h =\displaystyle\frac{8 \eta | \Delta L | }{ \pi R ^4}$



In each segment, there will be a pressure difference in a network ($\Delta p_k$) with the hydraulic resistance in a network ($R_{hk}$) and the volume flow ($J_V$) to which Darcy's Law is applied:



the total pressure difference ($\Delta p_t$) will be equal to the sum of the individual pressure difference in a network ($\Delta p_k$):

$ \Delta p_t =\displaystyle\sum_k \Delta p_k $



therefore,

$\Delta p_t=\displaystyle\sum_k \Delta p_k=\displaystyle\sum_k (R_{hk}J_V)=\left(\displaystyle\sum_k R_{hk}\right)J_V\equiv R_{st}J_V$



Thus, the system can be modeled as a single conduit with the hydraulic resistance calculated as the sum of the individual components:

$ R_{st} =\displaystyle\sum_k R_{hk} $

ID:(3180, 0)



Borders

Concept

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The edges of the systems affect the flow by diverting flows and if they are higher viscosity reducing the speed of this on its surface.

ID:(9482, 0)



Cylindrical Tube

Condition

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One type of Borders is for example a cylindrical tube of a given radius. This can be constant or vary throughout this.

ID:(9483, 0)



Hydraulic Resistance

Concept

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The Viscosity of a fluid causes it to resist flowing under a pressure difference. This occurs in particular in the presence of a Borders that leads to the fluid canceling its velocity on its surface.

Resistance means loss of energy that corresponds to the kinetic velocity that is lost when the fluid stops at the surface of the edges of the system.

ID:(9480, 0)



Hydraulic resistance of elements in series

Concept

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In the case of a sum where the elements are connected in series, the total hydraulic resistance of the system is calculated by summing the individual resistances of each element.



One way to model a tube with varying cross-section is to divide it into sections with constant radius and then sum the hydraulic resistances in series. Suppose we have a series of the hydraulic resistance in a network ($R_{hk}$), which depends on the viscosity ($\eta$), the cylinder k radio ($R_k$), and the tube k length ($\Delta L_k$) via the following equation:

$ R_h =\displaystyle\frac{8 \eta | \Delta L | }{ \pi R ^4}$



In each segment, there will be a pressure difference in a network ($\Delta p_k$) with the hydraulic resistance in a network ($R_{hk}$) and the volume flow ($J_V$) to which Darcy's Law is applied:



the total pressure difference ($\Delta p_t$) will be equal to the sum of the individual pressure difference in a network ($\Delta p_k$):

$ \Delta p_t =\displaystyle\sum_k \Delta p_k $



therefore,

$\Delta p_t=\displaystyle\sum_k \Delta p_k=\displaystyle\sum_k (R_{hk}J_V)=\left(\displaystyle\sum_k R_{hk}\right)J_V\equiv R_{st}J_V$



Thus, the system can be modeled as a single conduit with the hydraulic resistance calculated as the sum of the individual components:

$ R_{st} =\displaystyle\sum_k R_{hk} $

ID:(3630, 0)



Viscosity

Concept

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Viscosity can be understood as the tendency of the fluid to redistribute momentum and its corresponding velocity.

In a high viscosity liquid, a high speed zone is slowed down by dragging the liquid from surrounding areas with a low speed that therefore gains speed.

In a low viscosity liquid a high speed zone is not affected mostly by lower speed zones by displacing these and continuing the flow without further speed reduction.

ID:(9481, 0)



Pressure difference

Equation

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When two liquid columns are connected with the pressure in column 1 ($p_1$) and the pressure in column 2 ($p_2$), a the pressure difference ($\Delta p$) is formed, which is calculated according to the following formula:

$ \Delta p = p_2 - p_1 $

$p_1$
Pressure in column 1
$Pa$
6261
$p_2$
Pressure in column 2
$Pa$
6262
$\Delta p$
Variación de la Presión
$Pa$
6673



the pressure difference ($\Delta p$) represents the pressure difference that will cause the liquid to flow from the taller column to the shorter one.

ID:(4252, 0)



Parallel hydraulic conductivity

Concept

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If we have three hydraulic resistances $R_{h1}$, $R_{h2}$, and $R_{h3}$, the series sum of the resistances will be:

$ K_{pt} = \displaystyle\sum_k K_{hk}$

$R_{h1}$
Hydraulic Resistance 1
$kg/m^4s$
5425
$R_{h2}$
Hydraulic Resistance 2
$kg/m^4s$
5426
$R_{h3}$
Hydraulic Resistance 3
$kg/m^4s$
5427
$R_{st}$
Total hydraulic resistance in series
$kg/m^4s$
5428

ID:(3631, 0)



Hydraulic Resistance in Series (N)

Equation

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If you have N hydraulic resistors all the same R_h, the serial sum will be

$ R_{st} = N R_h $

$R_h$
Hydraulic resistance
$kg/m^4s$
5424
$N$
Number of Equal Hydraulic Resistors
$-$
5431
$R_{st}$
Total hydraulic resistance in series
$kg/m^4s$
5428

ID:(3632, 0)



Hydraulic resistance of parallel elements

Equation

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The total hydraulic resistance in parallel ($R_{pt}$) can be calculated as the inverse of the sum of the hydraulic resistance in a network ($R_{hk}$):

$\displaystyle\frac{1}{ R_{pt} }=\sum_k\displaystyle\frac{1}{ R_{hk} }$

$R_{hk}$
Hydraulic resistance in a network
$kg/m^4s$
9887
$R_{pt}$
Total hydraulic resistance in parallel
$kg/m^4s$
5429

The parallel total hydraulic conductance ($G_{pt}$) combined with the hydraulic conductance in a network ($G_{hk}$) in

$ G_{pt} =\displaystyle\sum_k G_{hk} $



and along with the hydraulic resistance in a network ($R_{hk}$) and the equation



leads to the total hydraulic resistance in parallel ($R_{pt}$) via

$\displaystyle\frac{1}{ R_{pt} }=\sum_k\displaystyle\frac{1}{ R_{hk} }$

ID:(3181, 0)



Hydraulic Resistance in Parallel (N)

Equation

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If you have N hydraulic resistors all the same R_h, the sum in parallel will be

$ R_{pt} =\displaystyle\frac{1}{ N } R_h $

$R_h$
Hydraulic resistance
$kg/m^4s$
5424
$N$
Number of Equal Hydraulic Resistors
$-$
5431
$R_{pt}$
Total hydraulic resistance in parallel
$kg/m^4s$
5429

ID:(3635, 0)



Hydraulic conductancia of elements in series

Equation

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In the case of hydraulic resistances in series, the inverse of the total Series Hydraulic Conductance ($G_{st}$) is calculated by summing the inverses of each the hydraulic conductance in a network ($G_{hk}$):

$\displaystyle\frac{1}{ G_{st} }=\displaystyle\sum_k\displaystyle\frac{1}{ G_{hk} }$

$G_{hk}$
Hydraulic conductance in a network
$m^4s/kg$
10134
$G_{st}$
Total Series Hydraulic Conductance
$m^4s/kg$
10135

The total hydraulic resistance in series ($R_{st}$), along with the hydraulic resistance in a network ($R_{hk}$), in

$ R_{st} =\displaystyle\sum_k R_{hk} $



and along with the hydraulic conductance in a network ($G_{hk}$) and the equation



leads to the total Series Hydraulic Conductance ($G_{st}$) can be calculated with:

$\displaystyle\frac{1}{ G_{st} }=\displaystyle\sum_k\displaystyle\frac{1}{ G_{hk} }$

ID:(3633, 0)



Hydraulic conductance of elements in parallel

Equation

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The parallel total hydraulic conductance ($G_{pt}$) is calculated with the sum of the hydraulic conductance in a network ($G_{hk}$):

$ G_{pt} =\displaystyle\sum_k G_{hk} $

$G_{hk}$
Hydraulic conductance in a network
$m^4s/kg$
10134
$G_{pt}$
Parallel total hydraulic conductance
$m^4s/kg$
10136

With the total flow ($J_{Vt}$) being equal to the volume flow in a network ($J_{Vk}$):

$ J_{Vt} =\displaystyle\sum_k J_{Vk} $



and with the pressure difference ($\Delta p$) and the hydraulic conductance in a network ($G_{hk}$), along with the equation



for each element, it leads us to the conclusion that with the parallel total hydraulic conductance ($G_{pt}$),

$J_{Vt}=\displaystyle\sum_k J_{Vk} = \displaystyle\sum_k G_{hk}\Delta p = G_{pt}\Delta p$



we have

$ G_{pt} =\displaystyle\sum_k G_{hk} $

.

ID:(3634, 0)