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Wire interaction

Storyboard

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Magnetic Field around a Wire

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ID:(1933, 0)



Intensity of the magnetic field of a wire

Equation

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Una alambre por el que circula corriente genera un campo magnético circular en torno de este.

Por ello con el campo magnético se calcula mediante:

H_w = \displaystyle\frac{ I }{ 2\pi r }

ID:(12167, 0)



Charges on a wire

Equation

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When considering a segment dl of a wire with a certain cross-sectional area S and length, it results in a volume of wire. Multiplying this volume by the charge density c gives us the number of charges contained within it. Finally, by multiplying it by the unit charge q, we obtain the total charge present in the segment.

\Delta Q = q c S dl

Q
Charge
C
5459
c
Charge concentration
1/m^3
5474
dl
Length element
m
9669
\Delta Q
Load element
C
9668
S
Section of Conductors
m^2
5475
H_w = I /(2 * pi * r ) dF / dl = mu_0 * mu_r * I_1 * I_2 /(2 * pi * r ) DQ = q * S * dl * c I = q * c * S * q * v v_mQcII_1I_2DF_ldlDQmu_0H_wpirmu_rSd

ID:(12172, 0)



Current in a wire

Equation

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The current is defined by the equation:

I =\displaystyle\frac{ \Delta Q }{ \Delta t }



and the charges within a segment of wire are represented by:

\Delta Q = q c S dl



The ratio of the length of the segment to the corresponding time interval gives us the velocity:

v =\displaystyle\frac{dl}{dt}



Therefore, the current in the wire is equal to:

I = q c S v

\bar{v}
Average speed of charges
m/s
8505
Q
Charge
C
5459
c
Charge concentration
1/m^3
5474
I
Current
A
5483
S
Section of Conductors
m^2
5475
H_w = I /(2 * pi * r ) dF / dl = mu_0 * mu_r * I_1 * I_2 /(2 * pi * r ) DQ = q * S * dl * c I = q * c * S * q * v v_mQcII_1I_2DF_ldlDQmu_0H_wpirmu_rSd

ID:(12173, 0)



Force on a wire

Equation

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If a wire carrying a current I_1 generates a magnetic field given by:

H_w = \displaystyle\frac{ I }{ 2\pi r }



This field generates a magnetic flux density represented by:

\vec{B} = \mu_0 \mu_r \vec{H}



Which, in turn, produces a force per segment in a wire with a current I_2, defined as:

d\vec{F} = I d\vec{l} \times \vec{B}



With this, the force per segment can be expressed as:

\displaystyle\frac{ dF }{ dl } = \mu_0 \mu_r \displaystyle\frac{ I_1 I_2 }{2 \pi r }

I_1
Current 1
A
9677
I_2
Current 2
A
9678
\displaystyle\frac{ dF }{ dl }
Force per length
N/m
9679
\mu_0
Magnetic field constant
1.25663706212e-6
V s/A m
5518
\pi
Pi
3.1415927
rad
5057
\mu_r
Relative magnetic permeability
-
5517
d
Wire distance
m
8588
H_w = I /(2 * pi * r ) dF / dl = mu_0 * mu_r * I_1 * I_2 /(2 * pi * r ) DQ = q * S * dl * c I = q * c * S * q * v v_mQcII_1I_2DF_ldlDQmu_0H_wpirmu_rSd

ID:(12169, 0)



Parallel currents

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When two currents are allowed to flow in a parallel manner, we observe an attractive force between the wires.

It's worth recalling that currents consist of electrons in motion, and electrons naturally repel each other due to their negative charges. However, when these charges are in motion, this repulsive force turns into an attractive force, resulting in the observed attraction between the negatively charged conductors.

ID:(11772, 0)



Opposite parallel currents

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When two currents are allowed to flow in a parallel but opposite direction, we observe a repulsive force between the wires.

Comparing this experiment to the one where the flow is parallel but in the same direction, the key difference lies in the presence of relative velocity in the latter case.

ID:(11773, 0)