Calorimetry in gases

Storyboard

Calorimetry is the process of measuring the heat associated with a change in a state variable. These state variables typically include temperature, pressure, and volume, though others may be included depending on the state being described.

When the variation in temperature relative to the heat supplied or extracted is measured, it is referred to as heat capacity. In the case of a gas, the heat capacity is influenced by the other state variables. Therefore, heat capacity is defined and measured at constant volume or constant pressure.

>Model

ID:(789, 0)



Mechanisms

Iframe

>Top


Calorimetry is the science of measuring the amount of heat involved in chemical reactions, physical changes, or heat capacity. It quantifies the heat exchanged in processes, providing essential data on the energy changes involved. Calorimetry determines the heat capacity of substances, indicating how different materials respond to heat. It also measures enthalpy changes in chemical reactions, showing whether they are exothermic or endothermic. Additionally, calorimetry studies phase transitions such as melting, boiling, or sublimation by measuring the heat absorbed or released. The data obtained from calorimetry can be used to derive other thermodynamic properties like entropy and Gibbs free energy, offering a comprehensive understanding of a system's behavior. The core principle involves using a calorimeter to measure heat exchange accurately by monitoring temperature changes, which is crucial in fields like chemistry, physics, biology, and engineering.

Code
Concept

Mechanisms

ID:(15244, 0)



Working converter heat

Description

>Top


The conversion of work into energy is studied by generating heat through friction. To do this, a metal band is wrapped around a cylinder containing water and a thermometer. By turning the crank, heat is generated through friction, leading to the heating of the water. If the applied force, the number of rotations, and the radius of the cylinder are measured, the distance traveled can be estimated, allowing for the estimation of energy as the product of force and distance.

ID:(1884, 0)



Calorie content of a solid and liquid

Concept

>Top


If a sample at a given temperature is immersed in a glass of water at a lower temperature, an increase in the water's temperature will be observed. This increase will depend on the specific heat capacity and the mass of the sample:



the heat supplied to liquid or solid ($\Delta Q$) is related to the temperature variation in a liquid or solid ($\Delta T$) and the heat capacity ($C$) as follows:

$ \Delta Q = C \Delta T $



Where the heat capacity ($C$) can be replaced by the specific heat ($c$) and the mass ($M$) using the following relationship:

$ c =\displaystyle\frac{ C }{ M }$



Therefore, we obtain:

$ \Delta Q = M c \Delta T$

ID:(15809, 0)



Heating under constant volume

Description

>Top


If a gas is heated, the heat capacity depends on the way this occurs. One way is at constant volume, meaning the volume is kept fixed while the system is exposed to a higher or lower pressure:



the heat capacity ($C$) in solids and liquids can be considered as a constant $C$ that relates the change in the heat supplied to liquid or solid ($\Delta Q$) and the variación de Temperature ($\Delta T$) through the equation:

$ \Delta Q = C \Delta T $



In the case where the volume ($V$) is constant, the volume Variation ($dV$) is zero:

$dV = 0$



and in this case, the variation of the internal energy ($dU$) is equal to the differential inexact Heat ($\delta Q$):

$dU = \delta Q$



In the case of a gas, the state depends on the absolute temperature ($T$), the pressure ($p$), and the volume ($V$). Therefore, if heat is added, the increase in temperature will depend on whether the volume or the pressure is held constant. In the first case, it is referred to as the heat capacity at constant volume ($C_V$) and denoted as $C_V$, and the relationship is as follows:

$ dU = C_V \Delta T $



Where the heat capacity at constant volume ($C_V$) can be replaced by the specific heat of gases at constant volume ($c_V$) and the mass ($M$) using the following relationship:

$ c_V =\displaystyle\frac{ C_V }{ M }$



Therefore, we obtain:

$ dU = c_V M \Delta T $

ID:(11190, 0)



Heating under constant pressure

Description

>Top


If a gas is heated, the heat capacity depends on the way this occurs. One way is at constant pressure, where the volume is allowed to expand or contract in such a way that the pressure remains constant:



the heat capacity ($C$) in solids and liquids can be considered as a constant $C$ that relates the change in ($$) and the variación de Temperature ($\Delta T$) through the equation:

$ \Delta Q = C \Delta T $



In the case of a gas, the state depends on the absolute temperature ($T$), the pressure ($p$), and the volume ($V$). Therefore, if heat is added, the increase in temperature will depend on whether the volume or the pressure is held constant. In the first case, it is referred to as the heat capacity at constant pressure ($C_p$) and denoted as $C_p$, and the relationship is as follows:

$ \Delta Q = C_p \Delta T $



Where the heat capacity at constant pressure ($C_p$) can be replaced by the specific heat at constant pressure ($c_p$) and the mass ($M$) using the following relationship:

$ c_p =\displaystyle\frac{ C_p }{ M }$



Therefore, we obtain:

$ \Delta Q = c_p M \Delta T $

ID:(11189, 0)



Model

Top

>Top



Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$C_p$
C_p
Heat capacity at constant pressure
J/kg
$C_V$
C_V
Heat capacity at constant volume
J/kg
$M$
M
Mass
kg
$c_p$
c_p
Specific heat at constant pressure
J/kg K
$c_V$
c_V
Specific heat of gases at constant volume
J/kg K
$\Delta T$
DT
Variación de Temperature
K

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$dU$
dU
Variation of the internal energy
J

Calculations


First, select the equation: to , then, select the variable: to

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used




Equations

#
Equation

$ c_p =\displaystyle\frac{ C_p }{ M }$

c_p = C_p / M


$ c_V =\displaystyle\frac{ C_V }{ M }$

c_V = C_V / M


$ \Delta Q = C_p \Delta T $

DQ = C_p * DT


$ \Delta Q = c_p M \Delta T $

DQ = c_p * M * DT


$ dU = C_V \Delta T $

dU = C_V * DT


$ dU = c_V M \Delta T $

dU = c_V * M * DT

ID:(15303, 0)



Caloric content of a gas at a constant volume

Equation

>Top, >Model


The variation of the internal energy ($dU$) is for the case that the volume ($V$) is constant equal to the heat capacity at constant volume ($C_V$) for the absolute temperature ($T$):

$ dU = C_V \Delta T $

$C_V$
Heat capacity at constant volume
$J/K$
8481
$\Delta T$
Variación de Temperature
$K$
7510
$dU$
Variation of the internal energy
$J$
5400

The heat capacity ($C$) in solids and liquids can be considered as a constant $C$ that relates the change in the heat supplied to liquid or solid ($\Delta Q$) and the variación de Temperature ($\Delta T$) through the equation:

$ \Delta Q = C \Delta T $



In the case where the volume ($V$) is constant, the volume Variation ($dV$) is zero:

$dV = 0$



and in this case, the variation of the internal energy ($dU$) is equal to the differential inexact Heat ($\delta Q$):

$dU = \delta Q$



In the case of a gas, the state depends on the absolute temperature ($T$), the pressure ($p$), and the volume ($V$). Therefore, if heat is added, the increase in temperature will depend on whether the volume or the pressure is held constant. In the first case, it is referred to as the heat capacity at constant volume ($C_V$) and denoted as $C_V$, and the relationship is as follows:

$ dU = C_V \Delta T $

ID:(4862, 0)



Calorie content of a constant pressure gas

Equation

>Top, >Model


($$) can be calculated from the heat capacity at constant pressure ($C_p$) and the variación de Temperature ($\Delta T$) using:

$ \Delta Q = C_p \Delta T $

$C_p$
Heat capacity at constant pressure
$J/K$
7937
$\Delta T$
Variación de Temperature
$K$
7510

The heat capacity ($C$) in solids and liquids can be considered as a constant $C$ that relates the change in ($$) and the variación de Temperature ($\Delta T$) through the equation:

$ \Delta Q = C \Delta T $



In the case of a gas, the state depends on the absolute temperature ($T$), the pressure ($p$), and the volume ($V$). Therefore, if heat is added, the increase in temperature will depend on whether the volume or the pressure is held constant. In the first case, it is referred to as the heat capacity at constant pressure ($C_p$) and denoted as $C_p$, and the relationship is as follows:

$ \Delta Q = C_p \Delta T $

ID:(4863, 0)



Specific heat of gases at constant volume

Equation

>Top, >Model


The specific heat of gases at constant volume ($c_V$) is equal to the heat capacity at constant volume ($C_V$) divided by the mass ($M$):

$ c_V =\displaystyle\frac{ C_V }{ M }$

$C_V$
Heat capacity at constant volume
$J/K$
8481
$M$
Mass
$kg$
5215
$c_V$
Specific heat of gases at constant volume
$J/kg K$
6662

Continuing the analogy to the specific heat ($c$) for liquids and solids with the heat capacity ($C$) and the mass ($M$):

$ c =\displaystyle\frac{ C }{ M }$



there is also a specific heat of gases at constant volume ($c_V$) for heating at constant volume with the heat capacity at constant volume ($C_V$):

$ c_V =\displaystyle\frac{ C_V }{ M }$

ID:(11113, 0)



Caloric content of a gas at constant volume as a function of specific heat

Equation

>Top, >Model


The relationship between the variation of the variation of the internal energy ($dU$) and the temperature variation in a liquid or solid ($\Delta T$) is with the specific heat of gases at constant volume ($c_V$) and the mass ($M$) equal to:

$ dU = c_V M \Delta T $

$M$
Mass
$kg$
5215
$c_V$
Specific heat of gases at constant volume
$J/kg K$
6662
$\Delta T$
Variación de Temperature
$K$
7510
$dU$
Variation of the internal energy
$J$
5400

The variation of the internal energy ($dU$) in relation to the temperature variation in a liquid or solid ($\Delta T$) and the heat capacity at constant volume ($C_V$) is expressed as:

$ dU = C_V \Delta T $



Where the heat capacity at constant volume ($C_V$) can be replaced by the specific heat of gases at constant volume ($c_V$) and the mass ($M$) using the following relationship:

$ c_V =\displaystyle\frac{ C_V }{ M }$



Therefore, we obtain:

$ dU = c_V M \Delta T $

ID:(11115, 0)



Specific heat of gases at constant pressure

Equation

>Top, >Model


The specific heat at constant pressure ($c_p$) is equal to the heat capacity at constant pressure ($C_p$) divided by the mass ($M$):

$ c_p =\displaystyle\frac{ C_p }{ M }$

$C_p$
Heat capacity at constant pressure
$J/K$
7937
$M$
Mass
$kg$
5215
$c_p$
Specific heat at constant pressure
$J/kg K$
9426

Following an analogy to the specific heat ($c$) for liquids and solids with the heat capacity ($C$) and the mass ($M$):

$ c =\displaystyle\frac{ C }{ M }$



there is also a specific heat at constant pressure ($c_p$) for heating at constant pressure with the heat capacity at constant pressure ($C_p$):

$ c_p =\displaystyle\frac{ C_p }{ M }$

ID:(11114, 0)



Caloric content of a gas at constant pressure as a function of specific heat

Equation

>Top, >Model


The heat supplied to liquid or solid ($\Delta Q$) can be calculated with the specific heat at constant pressure ($c_p$), the mass ($M$) and the temperature variation in a liquid or solid ($\Delta T$) using:

$ \Delta Q = c_p M \Delta T $

$M$
Mass
$kg$
5215
$c_p$
Specific heat at constant pressure
$J/kg K$
9426
$\Delta T$
Variación de Temperature
$K$
7510

The heat supplied to liquid or solid ($\Delta Q$) in relation to the temperature variation in a liquid or solid ($\Delta T$) and the heat capacity at constant pressure ($C_p$) is expressed as:

$ \Delta Q = C_p \Delta T $



Where the heat capacity at constant pressure ($C_p$) can be replaced by the specific heat at constant pressure ($c_p$) and the mass ($M$) using the following relationship:

$ c_p =\displaystyle\frac{ C_p }{ M }$



Therefore, we obtain:

$ \Delta Q = c_p M \Delta T $

ID:(11116, 0)