Collisions between Particles

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The most basic form of interaction are collisions between particles. These will depend on the size of the particles and their concentration.

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Concentration based on molar mass

Equation

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If we divide the density ($\rho$) by the particle mass ($m$), we will obtain the particle concentration ($c_n$):

$ c_n =\displaystyle\frac{ \rho }{ m }$

$\rho$
Density
$kg/m^3$
5342
$c_n$
Particle concentration
$1/m^3$
5548
$m$
Particle mass
$kg$
5516

Given the particle concentration ($c_n$) with the number of particles ($N$) and the volume ($V$), we have:

$ c_n \equiv \displaystyle\frac{ N }{ V }$



With the particle mass ($m$) and the mass ($M$),

$ m \equiv \displaystyle\frac{ M }{ N }$



As the density ($\rho$) is

$ \rho \equiv\displaystyle\frac{ M }{ V }$



we obtain

$c_n=\displaystyle\frac{N}{V}=\displaystyle\frac{M}{mV}=\displaystyle\frac{\rho}{m}$



Therefore,

$ c_n =\displaystyle\frac{ \rho }{ m }$

ID:(10623, 0)



Free path in a gas

Concept

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When a particle of a gas moves, it interacts with other particles. The simplest form of this interaction is through elastic collisions, meaning that the particle collides without losing energy, changing its direction to impact another particle.

None



Within this process, it makes sense to define the free path ($\bar{l}$), whose value will depend on ($$).

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Free Path of a Molecule

Description

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When a molecule moves periodically through the volume containing the gas, it will eventually encounter another molecule and they may collide. The distance it travels between two consecutive collisions is called the 'mean free path'.

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Free path with neighbors without movement

Concept

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When a particle with a given radius moves through space, it effectively occupies the space of a cylinder with the same radius. For one particle to collide with another, the second particle must have some of its volume within this cylinder. In the most extreme case, the second particle is located at a distance of two radii from the first one, so that the edge of the cylinder touches a point on the sphere closest to the cylinder's axis. The center of this sphere is at a distance equal to one radius from the surface of the cylinder:

None

Therefore, the distance between the cylinder's axis and the center of any particle is two radii, or in other words, a diameter. In essence, one can imagine that the volume literally occupied by the particle traveling through space is a cylinder with a length equal to the free path and a radius equal to the particle's diameter.

ID:(1962, 0)



Free path with mole concentration

Equation

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Since the diameter of the particle $d$ is twice the radius $a$

$d=2a$



and the particle concentration $c_N$ can be expressed in terms of molar concentration $c_n$ as

$c_N=N_Ac_n$



where $N_A$ is Avogadro's number, the equation for mean free path

$l=\displaystyle\frac{1}{4a^2\pi c_N}$



can also be written as:

$l=\displaystyle\frac{1}{d^2\pi c N_A}$

$N_A$
Avogadro's Number
$-$
5403
$l$
Calculation of free path with diameter and molar concentration
$m$
6214
$c$
Molar concentration
$mol/m^3$
5083
$d$
Molecule diameter
$m$
6213
$\pi$
Pi
3.1415927
$rad$
5057

ID:(4477, 0)



Free path with neighbors with movement

Concept

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When neighboring particles are in motion, there is a higher probability of collision due to the fact that they cover a greater distance in the same amount of time. The velocity components, $v_x$, $v_y$, and $v_z$, fluctuate around mean values $\sqrt{\langle v_x^2\rangle}$, $\sqrt{\langle v_y^2\rangle}$, and $\sqrt{\langle v_z^2\rangle}$. Assuming the system is isotropic, the average of each component will be equal to $\displaystyle\frac{1}{3}\sqrt{\langle v^2\rangle}$. Therefore, along the axis along which the particle is moving, it will travel a distance

$\sqrt{\langle v_z^2\rangle}dt=\displaystyle\frac{1}{3}\sqrt{\langle v^2\rangle}dt$



At the same time, particles moving perpendicular will have covered a distance:

$\sqrt{\langle v_x^2\rangle+\langle v_y^2\rangle}dt=\displaystyle\frac{\sqrt{2}}{3}\sqrt{\langle v^2\rangle}dt$



Hence, the collision probability increases by a factor of $\sqrt{2}$ compared to the case where the particles are not in motion:

None

ID:(1963, 0)



Free path with particle concentration

Equation

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The mean free path can be estimated in terms of the diameter of an imaginary cylinder surrounding a particle, on average having one collision with another particle.

The radius of the cylinder corresponds to the maximum distance two particles must have to collide, which is equal to twice the radius of the particle, i.e., the particle diameter ($d$). Since only one collision occurs within this cylinder, the number of particles contained within it must be equal to one. This means that:

$l d^2\pi c_n= 1$



with the particle concentration ($c_n$), and solving for the free path ($\bar{l}$), we obtain:

$ l =\displaystyle\frac{1}{ d ^2 \pi c_n }$

$l$
Free Path in Function of the Radio and Particle Concentration
$m$
6078
$c$
Molar concentration
$mol/m^3$
5083
$\pi$
Pi
3.1415927
$rad$
5057
$a$
Radio of the molecule
$m$
6077

This represents the mean free path.

ID:(4392, 0)



Mean free path for moving neighbors

Equation

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For the case without movement, the probability is the free path ($\bar{l}$), whereas with movement, the probabilities are the particle diameter ($d$) and the particle concentration ($c_n$), respectively.

$ l =\displaystyle\frac{1}{ \pi d ^2 c_n }$



In the case of movement, the probability increases by a factor of $\sqrt{2}$, which means the free path is

$l=\displaystyle\frac{1}{\sqrt{2}\pi d^2c_n}$

$l$
Free path
$m$
5553
$c_n$
Particle concentration
$1/m^3$
5548
$d$
Particle diameter
$m$
5554
$\pi$
Pi
3.1415927
$rad$
5057

ID:(3943, 0)



Mean free path for resting neighbors

Equation

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If d is the diameter of the particle, it can advance as long as there are no particles whose center is in a tube of radio d . Therefore, the free path will be given by a cylinder of long l , radius d and concentration c_n in which on average there is only one particle, it is say

$l\pi d^2c_n=1$



or

$ l =\displaystyle\frac{1}{ \pi d ^2 c_n }$

ID:(3942, 0)



Mechanisms

Iframe

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Code
Concept

Mechanisms

ID:(15294, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$N_A$
N_A
Avogadro's Number
-
$N_A$
N_A
Avogadro's number
-
$l$
l
Calculation of free path with diameter and molar concentration
m
$\rho$
rho
Density
kg/m^3
$\bar{l}$
l
Free path
m
$l_r$
l_r
Free Path in Function of the Radio and Particle Concentration
m
$d$
d
Molecule diameter
m
$n$
n
Número de Moles
mol
$d$
d
Particle diameter
m
$m$
m
Particle mass
kg
$\pi$
pi
Pi
rad
$a$
a
Radio of the molecule
m

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$c$
c
Molar concentration
mol/m^3
$c_m$
c_m
Molar concentration
mol/m^3
$c_n$
c_n
Particle concentration
1/m^3
$V$
V
Volume
m^3

Calculations


First, select the equation: to , then, select the variable: to

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used




Equations

#
Equation

$ c_m \equiv\displaystyle\frac{ n }{ V }$

c_m = n / V


$ c_n = N_A c_m $

c_n = N_A * c_m


$ c_n =\displaystyle\frac{ \rho }{ m }$

c_n = rho / m


$ l =\displaystyle\frac{1}{ d ^2 \pi c_n }$

l = 1/( d ^2 * pi * c )


$l=\displaystyle\frac{1}{d^2\pi c N_A}$

l = 1 / ( d^2 * pi * c_n * N_A )


$ l =\displaystyle\frac{1}{ \pi d ^2 c_n }$

l = 1 / ( pi * d^2 * c_n )


$l=\displaystyle\frac{1}{\sqrt{2}\pi d^2c_n}$

l = 1 / ( sqrt(2) * pi * d^2 * c_n )

ID:(15352, 0)



Molar concentration

Equation

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The molar concentration ($c_m$) corresponds to number of moles ($n$) divided by the volume ($V$) of a gas and is calculated as follows:

$ c_m \equiv\displaystyle\frac{ n }{ V }$

$c_m$
Molar concentration
$mol/m^3$
6609
$n$
Número de Moles
$mol$
6679
$V$
Volume
$m^3$
5226

ID:(4878, 0)



Particle and mole concentration

Equation

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To convert the molar concentration ($c_m$) to the particle concentration ($c_n$), simply multiply the former by the avogadro's number ($N_A$) as follows:

$ c_n = N_A c_m $

$N_A$
Avogadro's number
6.02e+23
$-$
9860
$c_m$
Molar concentration
$mol/m^3$
6609
$c_n$
Particle concentration
$1/m^3$
5548

ID:(10624, 0)