Storyboard

Heat transport through a system composed of multiple media can be estimated by analyzing how heat is conducted within each medium and transferred at each interface. The calculation is performed using the specific parameters of each medium and interface, as well as the temperatures at both ends of the system, thereby providing the temperatures at each interface.

>Model

ID:(1483, 0)

Iframe

>Top

ID:(15277, 0)

Concept

>Top

The basic system includes a transfer generated by the temperature difference ($\Delta T$), which consists of the temperature difference at internal interface ($\Delta T_i$), the temperature difference in the conductor ($\Delta T_0$), and the temperature difference at external interface ($\Delta T_e$). Therefore:

With the heat flow rate ($q$) being responsible for the transfer between the interior and the conductor, using the internal transmission coefficient ($\alpha_i$):

Conduction involves the thermal conductivity ($\lambda$) and the conductor length ($L$):

And the transfer from the conductor to the exterior, with the external transmission coefficient ($\alpha_e$), is represented by:

All this is graphically represented by:

ID:(7723, 0)

Concept

>Top

The heat flow rate ($q$) is calculated from the total transport coefficient (multiple medium, two interfaces) ($k$) and the temperature difference ($\Delta T$) using the following equation:

where the total transport coefficient (multiple medium, two interfaces) ($k$) is derived from the external transmission coefficient ($\alpha_e$), the internal transmission coefficient ($\alpha_i$), the thermal conductivity ($\lambda$), and the conductor length ($L$) through this equation:

This is represented in the image below:

ID:(1675, 0)

Concept

>Top

Typically, the temperature variation within a conductor follows a linear pattern. However, in the case of gaseous and/or liquid media in contact with the conductor, there is a gradual temperature variation from the center of the medium to the surface, as depicted in the following image:

the outer surface temperature ($T_{es}$) depends on the outdoor Temperature ($T_e$), the coefficient of total transportation ($k$), the external transmission coefficient ($\alpha_e$), and the temperature difference ($\Delta T$):

the inner surface temperature ($T_{is}$) is a function of the indoor temperature ($T_i$) and the internal transmission coefficient ($\alpha_i$):

and the temperature difference ($\Delta T$):

ID:(7722, 0)

Concept

>Top

When the material includes multiple conductors connected in series, the total transport coefficient (multiple medium, two interfaces) ($k$) is calculated from the external transmission coefficient ($\alpha_e$), the internal transmission coefficient ($\alpha_i$), the thermal conductivity element i ($\lambda_i$), and the element length i ($L_i$) using the equation:

This process is illustrated in the following diagram:

ID:(7721, 0)

Top

>Top

Parameters

$k$

k

Coefficient of total transportation

W/m K

$L$

L

Conductor length

m

$\alpha_e$

alpha_e

External transmission coefficient

W/m^2K

$\alpha_i$

alpha_i

Internal transmission coefficient

W/m^2K

$\lambda$

lambda

Thermal conductivity

W/m K

Variables

$q$

q

Heat flow rate

W/m^2

$dQ$

dQ

Heat transported

J

$T_i$

T_i

Indoor temperature

K

$T_{is}$

T_is

Inner surface temperature

K

$T_e$

T_e

Outdoor temperature

K

$T_{es}$

T_es

Outer surface temperature

K

$S$

S

Section

m^2

$\Delta T$

DT

Temperature difference

K

$\Delta T_e$

DT_e

Temperature difference at external interface

K

$\Delta T_i$

DT_i

Temperature difference at internal interface

K

$\Delta T_0$

DT_0

Temperature difference in the conductor

K

$dt$

dt

Time variation

s

Calculations

• Alternative method
• Traditional method
• Strategy
• 2D
• 3D

Equation

Number

First, select the equation: to , then, select the variable: to

---

Calculations

Symbol

Equation

Solved

Translated

Calculations

Symbol

Equation

Solved

Translated

Variable Given Calculate Target : Equation To be used

Equations

ID:(15336, 0)

Equation

>Top, >Model

The temperature difference ($\Delta T$) is calculated by subtracting the outdoor temperature ($T_e$) and the indoor temperature ($T_i$), which is expressed as:

$\Delta T = T_i - T_e$

Conditions

Variables

$T_i$

Indoor temperature

$K$

5208

$T_e$

Outdoor temperature

$K$

5207

$\Delta T$

Temperature difference

$K$

10161

Relation

ID:(15116, 0)

Equation

>Top, >Model

The temperature difference at external interface ($\Delta T_e$) is calculated by subtracting the outer surface temperature ($T_{es}$) from the outdoor temperature ($T_e$):

$\Delta T_e = T_{es} - T_e$

Conditions

Variables

$T_e$

Outdoor temperature

$K$

5207

$T_{es}$

Outer surface temperature

$K$

5214

$\Delta T_e$

Temperature difference at external interface

$K$

10167

Relation

ID:(15118, 0)

Equation

>Top, >Model

The temperature difference at internal interface ($\Delta T_i$) is calculated by subtracting the inner surface temperature ($T_{is}$) from the indoor temperature ($T_i$):

$\Delta T_i = T_i - T_{is}$

Conditions

Variables

$T_i$

Indoor temperature

$K$

5208

$T_{is}$

Inner surface temperature

$K$

5212

$\Delta T_i$

Temperature difference at internal interface

$K$

10166

Relation

ID:(15117, 0)

Equation

>Top, >Model

In the case of a solid, and similarly for a liquid, we can describe the system as a structure of atoms held together by something that behaves like a spring. When both ends have temperatures of ($$), with the inner surface temperature ($T_{is}$) and the outer surface temperature ($T_{es}$):

$\Delta T_0 = T_{is} - T_{es}$

Conditions

Variables

$T_{is}$

Inner surface temperature

$K$

5212

$T_{es}$

Outer surface temperature

$K$

5214

$\Delta T_0$

Temperature difference in the conductor

$K$

10165

Relation

ID:(15120, 0)

Equation

>Top, >Model

In the process of heat transfer, the temperature gradually decreases from the system with the highest temperature (internal) to the one with the lowest temperature (external). In this process, it first decreases from the internal average temperature to the temperature difference at internal interface ($\Delta T_i$), then to the temperature difference in the conductor ($\Delta T_0$), and finally to the temperature difference at external interface ($\Delta T_e$). The sum of these three variations equals the total drop, that is, the temperature difference ($\Delta T$), as shown below:

$\Delta T = \Delta T_i + \Delta T_0 + \Delta T_e$

Conditions

Variables

$\Delta T$

Temperature difference

$K$

10161

$\Delta T_e$

Temperature difference at external interface

$K$

10167

$\Delta T_i$

Temperature difference at internal interface

$K$

10166

$\Delta T_0$

Temperature difference in the conductor

$K$

10165

Relation

ID:(15115, 0)

Equation

>Top, >Model

The heat flux ($q$) is a function of the thermal conductivity ($\lambda$), the conductor length ($L$) and the temperature difference in the conductor ($\Delta T_0$):

$q = \displaystyle\frac{ \lambda }{ L } \Delta T_0$

Conditions

Variables

$L$

Conductor length

$m$

5206

$q$

Heat flow rate

$W/m^2$

10178

$\Delta T_0$

Temperature difference in the conductor

$K$

10165

$\lambda$

Thermal conductivity

$J/m s K$

5204

Relation

ID:(7712, 0)

Equation

>Top, >Model

In this way, we establish a relationship that allows us to calculate the heat flow rate ($q$) as a function of the total transport coefficient (multiple medium, two interfaces) ($k$), and the temperature difference ($\Delta T$):

$q = k \Delta T$

Conditions

Variables

$k$

Coefficient of total transportation

$W/m^2K$

5174

$q$

Heat flow rate

$W/m^2$

10178

$\Delta T$

Temperature difference

$K$

10161

Relation

Development

With the temperature difference at internal interface ($\Delta T_i$), the temperature difference in the conductor ($\Delta T_0$), the temperature difference at external interface ($\Delta T_e$), and the temperature difference ($\Delta T$), we obtain

$\Delta T = \Delta T_i + \Delta T_0 + \Delta T_e$

which can be rewritten with the heat transported ($dQ$), the time variation ($dt$), the section ($S$)

$q = \alpha_i \Delta T_i$

$q = \alpha_e \Delta T_e$

and with the thermal conductivity ($\lambda$) and the conductor length ($L$)

$q = \displaystyle\frac{ \lambda }{ L } \Delta T_0$

and

$\displaystyle\frac{1}{ k }=\displaystyle\frac{1}{ \alpha_i }+\displaystyle\frac{1}{ \alpha_e }+\displaystyle\frac{ L }{ \lambda }$

as

$\Delta T = \Delta T_i + \Delta T_0 + \Delta T_e = \displaystyle\frac{1}{S} \frac{dQ}{dt} \left(\displaystyle\frac{1}{\alpha_i} + \displaystyle\frac{1}{\alpha_e} + \displaystyle\frac{L}{\lambda}\right) = \displaystyle\frac{1}{Sk} \displaystyle\frac{dQ}{dt}$

resulting in

$q = k \Delta T$

ID:(7716, 0)

Equation

>Top, >Model

In this way, we establish a relationship that allows us to calculate the heat flow rate ($q$) based on the temperature difference at internal interface ($\Delta T_i$), and the internal transmission coefficient ($\alpha_i$):

$q = \alpha_i \Delta T_i$

Conditions

Variables

$q$

Heat flow rate

$W/m^2$

10178

$\alpha_i$

Internal transmission coefficient

$W/m^2K$

10163

$\Delta T_i$

Temperature difference at internal interface

$K$

10166

Relation

ID:(15113, 0)

Equation

>Top, >Model

In this manner, we establish a relationship that enables us to calculate the heat flow rate ($q$) based on the temperature difference at external interface ($\Delta T_e$), and the external transmission coefficient ($\alpha_e$):

$q = \alpha_e \Delta T_e$

Conditions

Variables

$\alpha_e$

External transmission coefficient

$W/m^2K$

10162

$q$

Heat flow rate

$W/m^2$

10178

$\Delta T_e$

Temperature difference at external interface

$K$

10167

Relation

ID:(15114, 0)

Equation

>Top, >Model

The outer surface temperature ($T_{es}$) is not equal to the temperature of the medium, which is the outdoor temperature ($T_e$). This temperature can be calculated from the temperature difference ($\Delta T$), the total transport coefficient (multiple medium, two interfaces) ($k$), and the external transmission coefficient ($\alpha_e$) using the following formula:

$T_{es} = T_e + \displaystyle\frac{ k }{ \alpha_e } \Delta T$

Conditions

Variables

$k$

Coefficient of total transportation

$W/m^2K$

5174

$\alpha_e$

External transmission coefficient

$W/m^2K$

10162

$T_e$

Outdoor temperature

$K$

5207

$T_{es}$

Outer surface temperature

$K$

5214

$\Delta T$

Temperature difference

$K$

10161

Relation

Development

With the heat transported ($dQ$), the time variation ($dt$), the section ($S$), the temperature difference ($\Delta T$), and the total transport coefficient (multiple medium, two interfaces) ($k$), we obtain

$q = k \Delta T$

which, with the external transmission coefficient ($\alpha_e$) and the temperature difference at external interface ($\Delta T_e$)

$q = \alpha_e \Delta T_e$

results in

$k\Delta T = \alpha_e \Delta T_e$

and with the outdoor temperature ($T_e$) and the outer surface temperature ($T_{es}$) and

$\Delta T_e = T_{es} - T_e$

results in

$T_{es} = T_e + \displaystyle\frac{ k }{ \alpha_e } \Delta T$

ID:(15122, 0)

Equation

>Top, >Model

The inner surface temperature ($T_{is}$) is not equal to the temperature of the medium itself, which is the indoor temperature ($T_i$). This temperature can be calculated from the temperature difference ($\Delta T$), the total transport coefficient (multiple medium, two interfaces) ($k$), and the internal transmission coefficient ($\alpha_i$) using the following formula:

$T_{is} = T_i - \displaystyle\frac{ k }{ \alpha_i } \Delta T$

Conditions

Variables

$k$

Coefficient of total transportation

$W/m^2K$

5174

$T_i$

Indoor temperature

$K$

5208

$T_{is}$

Inner surface temperature

$K$

5212

$\alpha_i$

Internal transmission coefficient

$W/m^2K$

10163

$\Delta T$

Temperature difference

$K$

10161

Relation

Development

With the heat transported ($dQ$), the time variation ($dt$), the section ($S$), the temperature difference ($\Delta T$), and the total transport coefficient (multiple medium, two interfaces) ($k$), we have

$q = k \Delta T$

which, with the internal transmission coefficient ($\alpha_i$) and the temperature difference at internal interface ($\Delta T_i$)

$q = \alpha_i \Delta T_i$

results in

$k\Delta T = \alpha_i \Delta T_i$

and with the indoor temperature ($T_i$) and the inner surface temperature ($T_{is}$) and

$\Delta T_i = T_i - T_{is}$

results in

$T_{is} = T_i - \displaystyle\frac{ k }{ \alpha_i } \Delta T$

ID:(15121, 0)

Equation

>Top, >Model

The value of the coefficient of total transportation ($k$) in the transport equation is determined using the external transmission coefficient ($\alpha_e$), the internal transmission coefficient ($\alpha_i$), the thermal conductivity ($\lambda$), and the conductor length ($L$) as follows:

$\displaystyle\frac{1}{ k }=\displaystyle\frac{1}{ \alpha_i }+\displaystyle\frac{1}{ \alpha_e }+\displaystyle\frac{ L }{ \lambda }$

Conditions

Variables

$k$

Coefficient of total transportation

$W/m^2K$

5174

$L$

Conductor length

$m$

5206

$\alpha_e$

External transmission coefficient

$W/m^2K$

10162

$\alpha_i$

Internal transmission coefficient

$W/m^2K$

10163

$\lambda$

Thermal conductivity

$J/m s K$

5204

Relation

Development

With the temperature difference at internal interface ($\Delta T_i$), the temperature difference in the conductor ($\Delta T_0$), the temperature difference at external interface ($\Delta T_e$), and the temperature difference ($\Delta T$), we obtain

$\Delta T = \Delta T_i + \Delta T_0 + \Delta T_e$

which can be rewritten with the heat transported ($dQ$), the time variation ($dt$), the section ($S$)

$q = \alpha_i \Delta T_i$

$q = \alpha_e \Delta T_e$

and with the thermal conductivity ($\lambda$) and the conductor length ($L$)

$q = \displaystyle\frac{ \lambda }{ L } \Delta T_0$

as

$\Delta T_i + \Delta T_0 + \Delta T_e = \displaystyle\frac{1}{S} \displaystyle\frac{dQ}{dt} \left(\displaystyle\frac{1}{\alpha_i} + \displaystyle\frac{1}{\alpha_e} + \displaystyle\frac{L}{\lambda}\right)$

so we can define a combined coefficient as

$\displaystyle\frac{1}{ k }=\displaystyle\frac{1}{ \alpha_i }+\displaystyle\frac{1}{ \alpha_e }+\displaystyle\frac{ L }{ \lambda }$

ID:(3486, 0)

Equation

>Top, >Model

The heat flow rate ($q$) is defined in terms of the heat transported ($dQ$), the time variation ($dt$), and the section ($S$) as follows:

$q \equiv \displaystyle\frac{1}{ S }\displaystyle\frac{ dQ }{ dt }$

Conditions

Variables

$q$

Heat flow rate

$W/m^2$

10178

$dQ$

Heat transported

$J$

10159

$S$

Section

$m^2$

5205

$dt$

Time variation

$s$

10160

Relation

ID:(15133, 0)