Energía Libre de Gibbs

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Se obtienen mediante la función partición las distintas funciones y relaciones termodinámicas.

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ID:(443, 0)



Gibbs free energy with partition function

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To calculate the Gibbs function of the partition function, it is enough to see how the enthalpy and the entropy of it are constructed. How do you have to

ID:(11726, 0)



Energía Libre de Gibbs

Description

Se obtienen mediante la función partición las distintas funciones y relaciones termodinámicas.

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$T$
T
Absolute temperature
K
$\beta$
beta
Beta
1/J
$dG$
dG
Differential of the Gibbs free energy
J
$H$
H
Enthalpy
J
$S$
S
Entropy
J/K
$Z$
Z
Función Partición
-
$G$
G
Gibbs free energy
J
$G$
G
Gibbs Free Energy
J
$DS_{p,T}$
DS_pT
Partial derivative of entropy with respect to pressure at constant temperature
m^3
$DG_{p,T}$
DG_pT
Partial derivative of the Gibbs free energy with respect to pressure at constant temperature
m^3
$DG_{T,p}$
DG_Tp
Partial derivative of the Gibbs free energy with respect to temperature at constant pressure
J/K
$DV_{T,p}$
DV_Tp
Partial derivative of volume with respect to temperature at constant pressure
m^3/K
$p$
p
Pressure
Pa
$dp$
dp
Pressure Variation
Pa
$dT$
dT
Temperature variation
K
$dG$
dG
Variation of Gibbs Free Energy
J
$V$
V
Volume
m^3
$V$
V
Volumen
m^3

Calculations


First, select the equation:   to ,  then, select the variable:   to 

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

 Variable   Given   Calculate   Target :   Equation   To be used



Equations

The gibbs free energy ($G$) as a function of the enthalpy ($H$), the entropy ($S$), and the absolute temperature ($T$) is expressed as:

$ G = H - T S $



The value of the differential of the Gibbs free energy ($dG$) is determined using the differential enthalpy ($dH$), the temperature variation ($dT$), and the entropy variation ($dS$) through the equation:

$dG=dH-SdT-TdS$



Since the differential enthalpy ($dH$) is related to the volume ($V$) and the pressure Variation ($dp$) as follows:

$ dH = T dS + V dp $



It follows that the differential enthalpy ($dH$), the entropy variation ($dS$), and the pressure Variation ($dp$) are interconnected in the following manner:

$ dG =- S dT + V dp $

(ID 3541)

The differential of the Gibbs free energy ($dG$) is a function of the variations of the absolute temperature ($T$) and the pressure ($p$), as well as the slopes the partial derivative of the Gibbs free energy with respect to temperature at constant pressure ($DG_{T,p}$) and the partial derivative of the Gibbs free energy with respect to pressure at constant temperature ($DG_{p,T}$), expressed as:

$ dG = DG_{T,p} dT + DG_{p,T} dp $



Comparing this with the equation for the variation of Gibbs Free Energy ($dG$):

$ dG =- S dT + V dp $



and with the first law of thermodynamics, it follows that the partial derivative of the Gibbs free energy with respect to temperature at constant pressure ($DG_{T,p}$) is equal to negative the entropy ($S$):

$ DG_{T,p} =- S $

(ID 3552)

The differential of the Gibbs free energy ($dG$) is a function of the variations of the absolute temperature ($T$) and the pressure ($p$), as well as the slopes the partial derivative of the Gibbs free energy with respect to temperature at constant pressure ($DG_{T,p}$) and the partial derivative of the Gibbs free energy with respect to pressure at constant temperature ($DG_{p,T}$), expressed as:

$ dG = DG_{T,p} dT + DG_{p,T} dp $



Comparing this with the equation for the variation of Gibbs Free Energy ($dG$):

$ dG =- S dT + V dp $



and with the first law of thermodynamics, it follows that the partial derivative of the Gibbs free energy with respect to pressure at constant temperature ($DG_{p,T}$) is equal to the volume ($V$):

$ DG_{p,T} = V $

(ID 3553)

Since the differential of the Gibbs free energy ($dG$) is an exact differential, it implies that the gibbs free energy ($G$) with respect to the absolute temperature ($T$) and the pressure ($p$) must be independent of the order in which the function is derived:

$D(DG_{T,p}){p,T}=D(DG{p,T})_{T,p}$



Using the relationship for the slope the partial derivative of the Gibbs free energy with respect to pressure at constant temperature ($DG_{p,T}$) with respect to the volume ($V$)

$ DG_{p,T} = V $



and the relationship for the slope the partial derivative of the Gibbs free energy with respect to temperature at constant pressure ($DG_{T,p}$) with respect to the entropy ($S$)

$ DG_{T,p} =- S $



we can conclude that:

$ DS_{p,T} = -DV_{T,p} $

(ID 3557)

Given that the gibbs free energy ($G$) depends on the absolute temperature ($T$) and the pressure ($p$), the variation of Gibbs Free Energy ($dG$) can be calculated using:

$dG = \left(\displaystyle\frac{\partial G}{\partial T}\right)_p dT + \left(\displaystyle\frac{\partial G}{\partial p}\right)_T dp$



To simplify this expression, we introduce the notation for the derivative of the gibbs free energy ($G$) with respect to the absolute temperature ($T$) while keeping the pressure ($p$) constant as:

$DG_{T,p} \equiv \left(\displaystyle\frac{\partial G}{\partial T}\right)_p$



and for the derivative of the gibbs free energy ($G$) with respect to the pressure ($p$) while keeping the absolute temperature ($T$) constant as:

$DG_{p,T} \equiv \left(\displaystyle\frac{\partial G}{\partial p}\right)_T$



thus we can write:

$ dG = DG_{T,p} dT + DG_{p,T} dp $

(ID 8188)


Examples

To calculate the Gibbs function of the partition function, it is enough to see how the enthalpy and the entropy of it are constructed. How do you have to

(ID 11726)


ID:(443, 0)