Internal energy

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Internal energy is the inherent energy of the system, i.e., the sum of the kinetic and potential energies of the particles comprising it.

Internal energy is a function of the system's state and depends solely on the current state, regardless of how it reached that state.

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Mechanisms

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Internal energy is the total energy contained within a system, including the kinetic energy of molecules moving and vibrating, and the potential energy from the forces between the molecules. It encompasses all the microscopic forms of energy that are not related to the motion or position of the system as a whole, such as thermal energy and chemical energy.

The internal energy of a system changes when heat is added to or removed from the system, or when work is done by or on the system. This is expressed in the first law of thermodynamics, which states that the change in internal energy is equal to the heat added to the system minus the work done by the system.

Internal energy is a state function, meaning it depends only on the current state of the system and not on how the system reached that state. This property allows for the calculation of energy changes between different states using state variables like temperature, pressure, and volume.

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Concept

Mechanisms

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Internal energy: differential relationship

Concept

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As the internal energy differential ($dU$) depends on the differential inexact Heat ($\delta Q$), the pressure ($p$), and the volume Variation ($dV$) according to the equation:

$ dU = \delta Q - p dV $



and the expression for the second law of thermodynamics with the absolute temperature ($T$) and the entropy variation ($dS$) as:

$ \delta Q = T dS $



we can conclude that:

$ dU = T dS - p dV $

ID:(570, 0)



Internal energy

Concept

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If the absolute temperature ($T$) and the pressure ($p$) are kept constant, the variation of the internal energy ($dU$), which depends on the entropy variation ($dS$) and the volume Variation ($dV$), is expressed as:

$ dU = T dS - p dV $



Integrating this results in the following expression in terms of the internal energy ($U$), the entropy ($S$), and the volume ($V$):

$ U = T S - p V $

[1] "Über die quantitative und qualitative Bestimmung der Kräfte" (On the Quantitative and Qualitative Determination of Forces), Julius Robert von Mayer, Annalen der Chemie und Pharmacie, 1842

[2] "Ãœber die Erhaltung der Kraft" (On the Conservation of Force), Hermann von Helmholtz, 1847

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Internal energy: differential ratio

Concept

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Given that the internal energy ($U$) depends on the entropy ($S$) and the volume ($V$), the internal energy differential ($dU$) can be calculated as follows:

$dU = \left(\displaystyle\frac{\partial U}{\partial S}\right)_V dS + \left(\displaystyle\frac{\partial U}{\partial V}\right)_S dV$



To simplify the notation of this expression, we introduce the derivative of the internal energy ($U$) with respect to the entropy ($S$) while keeping the volume ($V$) constant as:

$DU_{S,V} \equiv \left(\displaystyle\frac{\partial U}{\partial S}\right)_V$



and the derivative of the internal energy ($U$) with respect to the volume ($V$) while keeping the entropy ($S$) constant as:

$DU_{V,S} \equiv \left(\displaystyle\frac{\partial U}{\partial V}\right)_S$



therefore, we can write:

$ dU = DU_{S,V} dS + DU_{V,S} dV $

ID:(15703, 0)



Internal energy and equation of state at constant entropy

Concept

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The internal energy differential ($dU$) is a function of the variations in the entropy ($S$) and the volume ($V$), as well as the slopes the partial derivative of internal energy with respect to volume at constant entropy ($DU_{V,S}$) and the partial derivative of internal energy with respect to entropy at constant volume ($DU_{S,V}$), which is expressed as:

$ dU = DU_{S,V} dS + DU_{V,S} dV $



When compared with the equation for the internal energy differential ($dU$):

$ dU = T dS - p dV $



it results in the slope of the internal energy ($U$) with respect to the variation in the volume ($V$):

$ DU_{V,S} =- p $

ID:(568, 0)



Internal energy and equation of state at constant volume

Concept

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The internal energy differential ($dU$) is a function of the variations in the entropy ($S$) and the volume ($V$), as well as the slopes the partial derivative of internal energy with respect to volume at constant entropy ($DU_{V,S}$) and the partial derivative of internal energy with respect to entropy at constant volume ($DU_{S,V}$), which is expressed as:

$ dU = DU_{S,V} dS + DU_{V,S} dV $



When compared with the equation for the internal energy differential ($dU$):

$ dU = T dS - p dV $



it results in the slope of the internal energy ($U$) with respect to the variation in the entropy ($S$):

$ DU_{S,V} = T $

ID:(569, 0)



Internal energy and its relation of Maxwell

Concept

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Since the internal energy differential ($dU$) is an exact differential, we should note that the internal energy ($U$) with respect to the entropy ($S$) and the volume ($V$) must be independent of the order in which the function is derived:

$D(DU_{S,V}){V,S}=D(DU{V,S})_{S,V}$



Using the relationship between the slope the partial derivative of internal energy with respect to entropy at constant volume ($DU_{S,V}$) and the absolute temperature ($T$)

$ DU_{S,V} = T $

,

and the relationship between the slope the partial derivative of internal energy with respect to volume at constant entropy ($DU_{V,S}$) and the pressure ($p$)

$ DU_{V,S} =- p $

,

we can conclude that:

$ DT_{V,S} =- Dp_{S,V} $

ID:(15738, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$DU_{S,V}$
DU_SV
Partial derivative of internal energy with respect to entropy at constant volume
K
$DU_{V,S}$
DU_VS
Partial derivative of internal energy with respect to volume at constant entropy
Pa
$Dp_{S,V}$
Dp_SV
Partial derivative of pressure with respect to entropy at constant volume
K/m^3
$DT_{V,S}$
DT_VS
Partial derivative of temperature with respect to volume at constant entropy
K/m^3

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$T$
T
Absolute temperature
K
$S$
S
Entropy
J/K
$dS$
dS
Entropy variation
J/K
$U$
U
Internal energy
J
$dU$
dU
Internal energy differential
J
$p$
p
Pressure
Pa
$dU$
dU
Variation of the internal energy
J
$V$
V
Volume
m^3
$dV$
dV
Volume Variation
m^3

Calculations


First, select the equation: to , then, select the variable: to

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used




Equations

#
Equation

$ DT_{V,S} =- Dp_{S,V} $

DT_VS=- Dp_SV


$ dU = DU_{S,V} dS + DU_{V,S} dV $

dU = DU_SV * dS + DU_VS * dV


$ dU = T dS - p dV $

dU = T * dS - p * dV


$ DU_{S,V} = T $

DU_SV = T


$ DU_{V,S} =- p $

DU_VS =- p


$ U = T S - p V $

U = T * S - p * V

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Internal Energy: differential ratio

Equation

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The dependency of the internal energy differential ($dU$) on the pressure ($p$) and the volume Variation ($dV$), in addition to the absolute temperature ($T$) and the entropy variation ($dS$), is given by:

$ dU = T dS - p dV $

$T$
Absolute temperature
$K$
5177
$dS$
Entropy variation
$J/K$
5225
$p$
Pressure
$Pa$
5224
$dU$
Variation of the internal energy
$J$
5400
$dV$
Volume Variation
$m^3$
5223

As the internal energy differential ($dU$) depends on the differential inexact Heat ($\delta Q$), the pressure ($p$), and the volume Variation ($dV$) according to the equation:

$ dU = \delta Q - p dV $



and the expression for the second law of thermodynamics with the absolute temperature ($T$) and the entropy variation ($dS$) as:

$ \delta Q = T dS $



we can conclude that:

$ dU = T dS - p dV $

.

ID:(3471, 0)



Internal Energy

Equation

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The internal energy ($U$) is with the absolute temperature ($T$), the pressure ($p$), the entropy ($S$) and the volume ($V$) equal to:

$ U = T S - p V $

$T$
Absolute temperature
$K$
5177
$S$
Entropy
$J/K$
5227
$U$
Internal energy
$J$
5228
$p$
Pressure
$Pa$
5224
$V$
Volume
$m^3$
5226

If the absolute temperature ($T$) and the pressure ($p$) are kept constant, the variation of the internal energy ($dU$), which depends on the entropy variation ($dS$) and the volume Variation ($dV$), is expressed as:

$ dU = T dS - p dV $



Integrating this results in the following expression in terms of the internal energy ($U$), the entropy ($S$), and the volume ($V$):

$ U = T S - p V $

ID:(3472, 0)



Internal energy and equation of state at constant entropy

Equation

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Comparing this with the first law of thermodynamics, it turns out that the partial derivative of internal energy with respect to volume at constant entropy ($DU_{V,S}$) is equal to minus the pressure ($p$):

$ DU_{V,S} =- p $

$DU_{V,s}$
Partial derivative of internal energy with respect to volume at constant entropy
$Pa$
8734
$p$
Pressure
$Pa$
5224

The internal energy differential ($dU$) is a function of the variations in the entropy ($S$) and the volume ($V$), as well as the slopes the partial derivative of internal energy with respect to volume at constant entropy ($DU_{V,S}$) and the partial derivative of internal energy with respect to entropy at constant volume ($DU_{S,V}$), which is expressed as:

$ dU = DU_{S,V} dS + DU_{V,S} dV $



When compared with the equation for the internal energy differential ($dU$):

$ dU = T dS - p dV $



it results in the slope of the internal energy ($U$) with respect to the variation in the volume ($V$):

$ DU_{V,S} =- p $

ID:(3535, 0)



Internal energy and equation of state at constant volume

Equation

>Top, >Model


Comparing this with the first law of thermodynamics, it turns out that the partial derivative of internal energy with respect to entropy at constant volume ($DU_{S,V}$) is equal to the absolute temperature ($T$):

$ DU_{S,V} = T $

$T$
Absolute temperature
$K$
5177
$DU_{S,V}$
Partial derivative of internal energy with respect to entropy at constant volume
$K$
8735

The internal energy differential ($dU$) is a function of the variations in the entropy ($S$) and the volume ($V$), as well as the slopes the partial derivative of internal energy with respect to volume at constant entropy ($DU_{V,S}$) and the partial derivative of internal energy with respect to entropy at constant volume ($DU_{S,V}$), which is expressed as:

$ dU = DU_{S,V} dS + DU_{V,S} dV $



When compared with the equation for the internal energy differential ($dU$):

$ dU = T dS - p dV $



it results in the slope of the internal energy ($U$) with respect to the variation in the entropy ($S$):

$ DU_{S,V} = T $

ID:(3546, 0)



Differential of Internal Energy

Equation

>Top, >Model


Given that the internal energy ($U$) is a function of the entropy ($S$) and the volume ($V$), the internal energy differential ($dU$) can be expressed as follows:

$ dU = DU_{S,V} dS + DU_{V,S} dV $

$dS$
Entropy variation
$J/K$
5225
$dU$
Internal energy differential
$J$
8736
$DU_{S,V}$
Partial derivative of internal energy with respect to entropy at constant volume
$K$
8735
$DU_{V,s}$
Partial derivative of internal energy with respect to volume at constant entropy
$Pa$
8734
$dV$
Volume Variation
$m^3$
5223

Given that the internal energy ($U$) depends on the entropy ($S$) and the volume ($V$), the internal energy differential ($dU$) can be calculated as follows:

$dU = \left(\displaystyle\frac{\partial U}{\partial S}\right)_V dS + \left(\displaystyle\frac{\partial U}{\partial V}\right)_S dV$



To simplify the notation of this expression, we introduce the derivative of the internal energy ($U$) with respect to the entropy ($S$) while keeping the volume ($V$) constant as:

$DU_{S,V} \equiv \left(\displaystyle\frac{\partial U}{\partial S}\right)_V$



and the derivative of the internal energy ($U$) with respect to the volume ($V$) while keeping the entropy ($S$) constant as:

$DU_{V,S} \equiv \left(\displaystyle\frac{\partial U}{\partial V}\right)_S$



therefore, we can write:

$ dU = DU_{S,V} dS + DU_{V,S} dV $

ID:(8185, 0)



Internal energy and its relation of Maxwell

Equation

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With the entropy ($S$), the volume ($V$), the absolute temperature ($T$) and the pressure ($p$) we obtain one of the so-called Maxwell relations:

$ DT_{V,S} =- Dp_{S,V} $

$Dp_{S,V}$
Partial derivative of pressure with respect to entropy at constant volume
$K/m^3$
8739
$DT_{V,S}$
Partial derivative of temperature with respect to volume at constant entropy
$K/m^3$
8738

Since the internal energy differential ($dU$) is an exact differential, we should note that the internal energy ($U$) with respect to the entropy ($S$) and the volume ($V$) must be independent of the order in which the function is derived:

$D(DU_{S,V}){V,S}=D(DU{V,S})_{S,V}$



Using the relationship between the slope the partial derivative of internal energy with respect to entropy at constant volume ($DU_{S,V}$) and the absolute temperature ($T$)

$ DU_{S,V} = T $

,

and the relationship between the slope the partial derivative of internal energy with respect to volume at constant entropy ($DU_{V,S}$) and the pressure ($p$)

$ DU_{V,S} =- p $

,

we can conclude that:

$ DT_{V,S} =- Dp_{S,V} $

ID:(3556, 0)