Action and Reaction in Rotation

Storyboard

Newton's third principle in the case of rotation defines that the torques have to be generated in pairs so that their sum is zero. This implies that before an action there is always a reaction of equal magnitude but in the opposite direction.

>Model

ID:(757, 0)



Mechanisms

Iframe

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Code
Concept

Mechanisms

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Action and reaction in torque

Image

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Similar to the case of translational motion, where the third principle states that every action has an equal and opposite reaction. This means that if I try to rotate an object in one direction, its support will rotate in the opposite direction.

An example of this is a rotating chair. This exercise can be done with extended legs and arms, attempting to rotate in the same direction, or with an object that is rotating and an attempt to alter its angular momentum, which generates an opposing angular momentum in the support:

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Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$I_1$
I_1
Moment of inertia of the first object
kg m^2
$I_2$
I_2
Moment of inertia of the second object
kg m^2
$T_R$
T_R
Reaction Torque
N m
$T_A$
T_A
Torque Action
N m

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$\Delta t$
Dt
Time elapsed
s
$\Delta\omega_1$
Domega_1
Variation of angular velocities of the first object
rad/s
$\Delta\omega_2$
Domega_2
Variation of angular velocities of the second object
rad/s
$\Delta L_1$
DL_1
Variation of the angular momentum of the first object
kg m^2/s
$\Delta L_2$
DL_2
Variation of the angular momentum of the second object
kg m^2/s

Calculations


First, select the equation: to , then, select the variable: to

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used




Equations

#
Equation

$ \Delta L_1 = I_1 \Delta \omega $

DL = I * Domega


$ \Delta L_2 = I_2 \Delta \omega $

DL = I * Domega


$ T_m =\displaystyle\frac{ \Delta L_1 }{ \Delta t }$

T_m = DL / Dt


$ T_m =\displaystyle\frac{ \Delta L_2 }{ \Delta t }$

T_m = DL / Dt


$ T_R = - T_A$

T_R = - T_A

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Action and reaction in torque

Equation

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Similar to the case of translational motion, where the third principle states that every action has an equal and opposite reaction:

$ F_R =- F_A $



The analogous concept in rotation is

$ T_R = - T_A$

$T_R$
Reaction Torque
$N m$
4989
$T_A$
Torque Action
$N m$
10409

Since action and reaction in the case of forces are given by

$ F_R =- F_A $



multiplying this equation by the radius yields

$rF_R=-rF_A$



and with

$ T = r F $



we have

$ T_R = - T_A$

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Medium Torque (1)

Equation

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In the case of translation, the second principle defines how translational motion is generated with the definition of force

$ F \equiv\displaystyle\frac{ \Delta p }{ \Delta t }$



In the case of rotation, within a time interval $\Delta t$, the angular momentum $\Delta L$ changes according to:

$ T_m =\displaystyle\frac{ \Delta L }{ \Delta t }$

$\Delta t$
Time elapsed
$s$
5103
$T$
$T_A$
Torque Action
$N m$
10409
$dL$
$\Delta L_1$
Variation of the angular momentum of the first object
$kg m^2/s$
10403

.

ID:(9876, 1)



Medium Torque (2)

Equation

>Top, >Model


In the case of translation, the second principle defines how translational motion is generated with the definition of force

$ F \equiv\displaystyle\frac{ \Delta p }{ \Delta t }$



In the case of rotation, within a time interval $\Delta t$, the angular momentum $\Delta L$ changes according to:

$ T_m =\displaystyle\frac{ \Delta L }{ \Delta t }$

$\Delta t$
Time elapsed
$s$
5103
$T$
$T_R$
Reaction Torque
$N m$
4989
$dL$
$\Delta L_2$
Variation of the angular momentum of the second object
$kg m^2/s$
10404

.

ID:(9876, 2)



Variation of angular momentum (1)

Equation

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If a variation of Angular Momentum ($\Delta L$) is given with the moment of Inertia ($I$) constant, then a difference in Angular Speeds ($\Delta\omega$) is generated according to:

$ \Delta L_1 = I_1 \Delta\omega_1 $

$ \Delta L = I \Delta \omega $

$\Delta \omega$
$\Delta\omega_1$
Variation of angular velocities of the first object
$rad/s$
10405
$I$
$I_1$
Moment of inertia of the first object
$kg m^2$
10407
$\Delta L$
$\Delta L_1$
Variation of the angular momentum of the first object
$kg m^2/s$
10403

ID:(15843, 1)



Variation of angular momentum (2)

Equation

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If a variation of Angular Momentum ($\Delta L$) is given with the moment of Inertia ($I$) constant, then a difference in Angular Speeds ($\Delta\omega$) is generated according to:

$ \Delta L_2 = I_2 \Delta\omega_2 $

$ \Delta L = I \Delta \omega $

$\Delta \omega$
$\Delta\omega_2$
Variation of angular velocities of the second object
$rad/s$
10406
$I$
$I_2$
Moment of inertia of the second object
$kg m^2$
10408
$\Delta L$
$\Delta L_2$
Variation of the angular momentum of the second object
$kg m^2/s$
10404

ID:(15843, 2)