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Plane method

Storyboard

Slopes have the issue that the soil can slide if the forces generated by its own weight exceed the soil's cohesion. Since cohesion can vary due to external factors, there is a possibility that a mass may lose stability and shift, making it essential to understand its vulnerability and the likelihood of future destabilization.

>Model

ID:(383, 0)



Mechanisms

Iframe

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Code
Concept

Mechanisms

ID:(16106, 0)



Geometry of the Embankment

Description

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Para modelar la estabilidad de un terreno asumimos un fondo rocoso con una pendiente dada y una capa de suelo homogénea que se puede deslizar sobre esta.

ID:(1134, 0)



Sección

Image

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La sección que estamos estudiando tiene un ancho \Delta.y un largo L:

ID:(2971, 0)



Fuerzas gravitacionales y roce

Image

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En primera instancia podemos considerar que la masa genera una fuerza gravitacional que trata de deslizar el suelo por la pendiente. Por otro lado la componente vertical al fondo rocoso genera el roce necesario para mantener la masa en su lugar:

De no existir agua ambas fuerzas son proporcionales a la masa por lo que finalmente solo dependerá del coeficiente de roce si la capa es estable.

ID:(2970, 0)



Rol del agua en el suelo

Image

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De existir agua en el suelo esta contribuye en varias formas para desestabilizar la capa de suelo. Una primera forma es creando una fuerza de sustentación que reduce la fuerza normal y con ello el roce que sujeta el suelo en el lugar:

Este comportamiento corresponde a lo que se podría llamar en el limite la tendencia a que el suelo flote.

ID:(7985, 0)



Fuerzas de adhesión entre granos

Image

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La segunda contribución del agua tiende, en la medida que el agua este adecuadamente dosificada, a estabilizar el suelo. Si solo figura como humedad relativa alta se forman meniscos de agua entre los granos que ejercen fuerzas cohesivas. Sin embargo si la capa de suelo es inundada dicha sección pierde esta cohesión y es el resto sobre el nivel del agua que debe soportar el peso de la masa:

ID:(7986, 0)



Cohesion and Internal friction angle model

Concept

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The cohesion of the material (c) and the angle of internal friction of the soil (\phi) depend on the soil composition (the mass fraction of sand in the sample (g_a), the mass fraction of silt in the sample (g_i), the mass fraction of clay in the sample (g_c)) and water content (the mass fraction of water in the sample (g_w)).

Based on measurements, phenomenological models can be developed to describe these properties:

Cohesion Model

Cohesion the cohesion of the material (c) is expressed using the equation:

c = c_0 + k ( g_i + g_c ) - m g_w



Where the constants the inherent cohesion of dry material (c_0), the degree of cohesion induced by fine particles (k), and the sensitivity of cohesion to water (m) take the following typical values:

• the inherent cohesion of dry material (c_0):

Sandy soils 0-5 kPa
Loamy soils 5-15 kPa
Clayey soils 15-50 kPa


• the degree of cohesion induced by fine particles (k): 20 - 200 kPa
• the sensitivity of cohesion to water (m): 5 - 20 kPa

Internal Friction Angle Model

The internal friction angle the angle of internal friction of the soil (\phi) is described using the equation:

\phi = \phi_0 + k_a g_a - k_c g_c - k_w g_w



Where the constants the internal friction angle of the base soil (\phi_0), the friction angle sensitivity to clay (k_c), the friction angle sensitivity to sand (k_a), and the friction angle sensitivity to water (k_w) take the following values:

• the internal friction angle of the base soil (\phi_0):

Dry sand 30° - 40°
Dry loam 20° - 30°
Compact clays 15° - 25°


• the friction angle sensitivity to clay (k_c): 5° - 10°
• the friction angle sensitivity to sand (k_a): 3° - 8°
• the friction angle sensitivity to water (k_w): 5° - 15°

ID:(16125, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
\phi
phi
Angle of internal friction of the soil
rad
c
c
Cohesion of the material
Pa
k
k
Degree of cohesion induced by fine particles
Pa
k_c
k_c
Friction angle sensitivity to clay
rad
k_a
k_a
Friction angle sensitivity to sand
rad
k_w
k_w
Friction angle sensitivity to water
rad
g
g
Gravitational Acceleration
m/s^2
c_0
c_0
Inherent cohesion of dry material
Pa
\phi_0
phi_0
Internal friction angle of the base soil
rad
\sigma
sigma
Normal tension
Pa
s
s
Saturation
-
SF
SF
Security factor
-
m
m
Sensitivity of cohesion to water
Pa
\rho_s
rho_s
Solid Density
kg/m^3
\gamma_s
gamma_s
Unit weight of soil
N/m^3
\gamma_w
gamma_w
Unit weight of water
N/m^3
\rho_w
rho_w
Water density
kg/m^3

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
H
H
Layer height
m
g_c
g_c
Mass fraction of clay in the sample
-
g_a
g_a
Mass fraction of sand in the sample
-
g_i
g_i
Mass fraction of silt in the sample
-
g_w
g_w
Mass fraction of water in the sample
-
\tau
tau
Shear stress
Pa
\theta
theta
Slope angle of the hillside
p_v
p_v
Water pressure in pores
Pa

Calculations


First, select the equation: to , then, select the variable: to
c = c_0 + k *( g_i + g_c ) - m * g_w gamma_s = rho_s * g gamma_w = rho_w * g phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_w p_v = s * gamma_w * H SF = ( c + ( sigma - p_v )*tan( phi ))/ tau sigma = gamma_s * H *cos( theta ) tau = gamma_s * H *sin( theta ) phickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used
c = c_0 + k *( g_i + g_c ) - m * g_w gamma_s = rho_s * g gamma_w = rho_w * g phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_w p_v = s * gamma_w * H SF = ( c + ( sigma - p_v )*tan( phi ))/ tau sigma = gamma_s * H *cos( theta ) tau = gamma_s * H *sin( theta ) phickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v




Equations

#
Equation

c = c_0 + k ( g_i + g_c ) - m g_w

c = c_0 + k *( g_i + g_c ) - m * g_w


\gamma_s = \rho_s g

gamma_s = rho_s * g


\gamma_w = \rho_w g

gamma_w = rho_w * g


\phi = \phi_0 + k_a g_a - k_c g_c - k_w g_w

phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_w


p_v = s \gamma_w H

p_v = s * gamma_w * H


SF = \displaystyle\frac{ c + ( \sigma - p_v )\tan \phi }{ \tau }

SF = ( c + ( sigma - p_v )*tan( phi ))/ tau


\sigma = \gamma_s H \cos \theta

sigma = gamma_s * H *cos( theta )


\tau = \gamma_s H \sin \theta

tau = gamma_s * H *sin( theta )

ID:(16105, 0)



Factor of safety

Equation

>Top, >Model


The the security factor (SF) represents the ratio of the stress that prevents sliding. It is calculated based on the cohesion of the material (c), adjusted by the normal tension (\sigma), reduced by the water pressure in pores (p_v), and weighted using the tangent of the angle of internal friction of the soil (\phi) and the normal tension (\sigma), as expressed in the following equation:

SF = \displaystyle\frac{ c + ( \sigma - p_v )\tan \phi }{ \tau }

\phi
Angle of internal friction of the soil
rad
10528
c
Cohesion of the material
Pa
10527
\sigma
Normal tension
Pa
10510
SF
Security factor
-
10526
\tau
Shear stress
Pa
10512
p_v
Water pressure in pores
Pa
10511
gamma_s = rho_s * g gamma_w = rho_w * g sigma = gamma_s * H *cos( theta ) p_v = s * gamma_w * H tau = gamma_s * H *sin( theta ) SF = ( c + ( sigma - p_v )*tan( phi ))/ tau c = c_0 + k *( g_i + g_c ) - m * g_w phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_wphickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

ID:(16112, 0)



Shear stress

Equation

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The shear stress (\tau) is calculated from unit weight of soil (\gamma_s), combined with the layer height (H), and weighted by the sine of the slope angle of the hillside (\theta), as shown in the following formula:

\tau = \gamma_s H \sin \theta

H
Layer height
m
8239
\tau
Shear stress
Pa
10512
\theta
Slope angle of the hillside
rad
4953
\gamma_s
Unit weight of soil
N/m^3
10508
gamma_s = rho_s * g gamma_w = rho_w * g sigma = gamma_s * H *cos( theta ) p_v = s * gamma_w * H tau = gamma_s * H *sin( theta ) SF = ( c + ( sigma - p_v )*tan( phi ))/ tau c = c_0 + k *( g_i + g_c ) - m * g_w phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_wphickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

ID:(16111, 0)



Unit weight of water

Equation

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unit weight of water (\gamma_w) of water is determined from the water density (\rho_w) and the gravitational Acceleration (g), using the following formula:

\gamma_w = \rho_w g

g
Gravitational Acceleration
9.8
m/s^2
5310
\gamma_w
Unit weight of water
N/m^3
10509
\rho_w
Water density
kg/m^3
6000
gamma_s = rho_s * g gamma_w = rho_w * g sigma = gamma_s * H *cos( theta ) p_v = s * gamma_w * H tau = gamma_s * H *sin( theta ) SF = ( c + ( sigma - p_v )*tan( phi ))/ tau c = c_0 + k *( g_i + g_c ) - m * g_w phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_wphickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

ID:(16108, 0)



Unit weight of soil

Equation

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unit weight of soil (\gamma_s) of a body is calculated using the solid Density (\rho_s) and the gravitational Acceleration (g), as expressed in the following formula:

\gamma_s = \rho_s g

g
Gravitational Acceleration
9.8
m/s^2
5310
\rho_s
Solid Density
kg/m^3
4944
\gamma_s
Unit weight of soil
N/m^3
10508
gamma_s = rho_s * g gamma_w = rho_w * g sigma = gamma_s * H *cos( theta ) p_v = s * gamma_w * H tau = gamma_s * H *sin( theta ) SF = ( c + ( sigma - p_v )*tan( phi ))/ tau c = c_0 + k *( g_i + g_c ) - m * g_w phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_wphickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

ID:(16107, 0)



Pore water pressure

Equation

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The water pressure in pores (p_v) generated by water in the pores is calculated using the saturation (s), unit weight of water (\gamma_w), and the layer height (H), as shown in the following formula:

p_v = s \gamma_w H

H
Layer height
m
8239
s
Saturation
-
10529
\gamma_w
Unit weight of water
N/m^3
10509
p_v
Water pressure in pores
Pa
10511
gamma_s = rho_s * g gamma_w = rho_w * g sigma = gamma_s * H *cos( theta ) p_v = s * gamma_w * H tau = gamma_s * H *sin( theta ) SF = ( c + ( sigma - p_v )*tan( phi ))/ tau c = c_0 + k *( g_i + g_c ) - m * g_w phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_wphickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

ID:(16110, 0)



Normal stress

Equation

>Top, >Model


The normal tension (\sigma) is the stress that counteracts sliding, calculated using unit weight of soil (\gamma_s), the layer height (H), and the slope angle of the hillside (\theta), as shown in the following formula:

\sigma = \gamma_s H \cos \theta

H
Layer height
m
8239
\sigma
Normal tension
Pa
10510
\theta
Slope angle of the hillside
rad
4953
\gamma_s
Unit weight of soil
N/m^3
10508
gamma_s = rho_s * g gamma_w = rho_w * g sigma = gamma_s * H *cos( theta ) p_v = s * gamma_w * H tau = gamma_s * H *sin( theta ) SF = ( c + ( sigma - p_v )*tan( phi ))/ tau c = c_0 + k *( g_i + g_c ) - m * g_w phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_wphickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

ID:(16109, 0)



Cohesion model

Equation

>Top, >Model


The cohesion of the material (c) can be estimated using the inherent cohesion of dry material (c_0), the degree of cohesion induced by fine particles (k), the sensitivity of cohesion to water (m), the mass fraction of clay in the sample (g_c), the mass fraction of silt in the sample (g_i), and the mass fraction of water in the sample (g_w), with the following formula:

c = c_0 + k ( g_i + g_c ) - m g_w

c
Cohesion of the material
Pa
10527
k
Degree of cohesion induced by fine particles
Pa
10532
c_0
Inherent cohesion of dry material
Pa
10531
g_c
Mass fraction of clay in the sample
-
10099
g_i
Mass fraction of silt in the sample
-
10098
g_w
Mass fraction of water in the sample
-
10530
m
Sensitivity of cohesion to water
Pa
10535
gamma_s = rho_s * g gamma_w = rho_w * g sigma = gamma_s * H *cos( theta ) p_v = s * gamma_w * H tau = gamma_s * H *sin( theta ) SF = ( c + ( sigma - p_v )*tan( phi ))/ tau c = c_0 + k *( g_i + g_c ) - m * g_w phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_wphickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

ID:(16123, 0)



Internal friction angle model

Equation

>Top, >Model


The angle of internal friction of the soil (\phi) can be estimated using the internal friction angle of the base soil (\phi_0), the friction angle sensitivity to clay (k_c), the friction angle sensitivity to sand (k_a), the friction angle sensitivity to water (k_w), the mass fraction of clay in the sample (g_c), the mass fraction of sand in the sample (g_a), and the mass fraction of water in the sample (g_w), with the following formula:

\phi = \phi_0 + k_a g_a - k_c g_c - k_w g_w

\phi
Angle of internal friction of the soil
rad
10528
k_c
Friction angle sensitivity to clay
rad
10538
k_a
Friction angle sensitivity to sand
rad
10537
k_w
Friction angle sensitivity to water
rad
10536
\phi_0
Internal friction angle of the base soil
rad
10534
g_c
Mass fraction of clay in the sample
-
10099
g_a
Mass fraction of sand in the sample
-
5797
g_w
Mass fraction of water in the sample
-
10530
gamma_s = rho_s * g gamma_w = rho_w * g sigma = gamma_s * H *cos( theta ) p_v = s * gamma_w * H tau = gamma_s * H *sin( theta ) SF = ( c + ( sigma - p_v )*tan( phi ))/ tau c = c_0 + k *( g_i + g_c ) - m * g_w phi = phi_0 + k_a * g_a - k_c * g_c - k_w * g_wphickk_ck_ak_wgc_0phi_0Hg_cg_ag_ig_wsigmasSFmtauthetarho_sgamma_sgamma_wrho_wp_v

ID:(16124, 0)