Vapor

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The evaporation of a liquid generates a vapor that can reach a characteristic pressure and concentration known as the saturation point. Typically, the vapors of the liquid are subject to fluctuations, achieving only partial concentrations and pressures that can be characterized based on their degree of saturation. An example of this is relative humidity, which represents the percentage of humidity present in relation to the saturated concentration of water vapor.

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Mechanisms

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Code
Concept

Mechanisms

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Water Vapor

Concept

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The gaseous phase of water corresponds to what is known as water vapor. It is created as water molecules acquire enough kinetic energy to escape from the liquid phase and begin to move through the space above the liquid. Periodically, the molecules in the gaseous state collide with the liquid surface again and are captured, returning to the liquid state.

As the number of molecules in the gaseous state increases, so does the number that returns to the liquid. This process continues until an equilibrium is reached between the molecules leaving the liquid and those being reabsorbed. In this situation, it is said that the space above the liquid is saturated.

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Amount of water vapor

Concept

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When the volume variation in phase change ($\Delta V$) changes phase from a liquid to a gas, it can be expressed as:

$\Delta V = V_{\text{gas}} - V_{\text{liquid}}$



Since the volume of the gas is significantly greater than that of the liquid,

$V_{\text{gas}} \gg V_{\text{liquid}}$



we can approximate:

$\Delta V \approx V_{\text{gas}}$



Given that water vapor behaves similarly to an ideal gas, we can state that with the values of the universal gas constant ($R$), the number of moles ($n$), the absolute temperature ($T$), and the water vapor pressure unsaturated ($p_v$):

$ p_v \Delta V = n_v R T $



Therefore, the volume variation in phase change ($\Delta V$) is:

$\Delta V = \displaystyle\frac{nRT}{p_v}$

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Pressure saturated water vapor

Concept

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Using the Clausius-Clapeyron equation for the gradient of the pressure ($p$) with respect to the absolute temperature ($T$), which depends on the latent Heat ($L$) and the volume variation in phase change ($\Delta V$):

$\displaystyle\frac{ dp }{ dT }=\displaystyle\frac{ L }{ \Delta V T }$



In the case of the phase change from liquid to gas, we can assume that the change in volume is approximately equal to the volume of the vapor. Therefore, we can employ the ideal gas equation with the number of moles ($n$), the volume ($V$), the universal gas constant ($R$), and the pressure ($p$):

$ p V = n R T $



Since the Clausius-Clapeyron equation can be written as:

$\displaystyle\frac{dp}{dT}=\displaystyle\frac{L}{n}\displaystyle\frac{p}{R T^2}$



Where the molar Latent Heat ($l_m$) ($l_m = L/n$) corresponds to the change in enthalpy during the phase change h (the energy required to form water), we finally have:

$\displaystyle\frac{dp}{dT}=l_m\displaystyle\frac{p}{RT^2}$



If we integrate this equation between the pressure saturated water vapor ($p_s$) and the pressure at point p_0 at temperature T_0, we obtain:

$p_s=p_0e^{l_m/RT_0}e^{-l_m/RT}$



If we evaluate this expression with the data at the critical point:

$p_{ref}=p_0e^{l_m/RT_0}$



We finally have:

$ p_s = p_{ref} e^{- l_m / R T }$

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Presión Vapor de Agua

Concept

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The relationship between the relative humidity ($RH$) with the concentration of water vapor molecules ($c_v$) and saturated water vapor concentration ($c_s$) is expressed as:

$ RH =\displaystyle\frac{ c_v }{ c_s }$



and by relating the pressure ($p$) with the molar concentration ($c_m$), the absolute temperature ($T$), and the universal gas constant ($R$), we obtain:

$ p = c_m R T $



This applies to the vapor pressure of water, where:

$p_v = c_v R T$



and the saturated vapor pressure of water:

$p_s = c_s R T$



resulting in the following equation:

$ RH =\displaystyle\frac{ p_v }{ p_s }$

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Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$c_v$
c_v
Concentration of water vapor molecules
mol/m^3
$\Delta m$
Dm
Evaporated Mass
kg
$L$
L
Latent Heat
J/kg
$l_m$
l_m
Molar Latent Heat
J/mol
$M_m$
M_m
Molar Mass
kg/mol
$p_s$
p_s
Pressure saturated water vapor
Pa
$p_{ref}$
p_ref
Reference pressure
Pa
$c_s$
c_s
Saturated water vapor concentration
mol/m^3
$R$
R
Universal gas constant
J/mol K
$\Delta v_m$
Dv_m
Variation of molar volume during phase change
m^3/mol
$\Delta V$
DV
Volume variation in phase change
m^3
$p_v$
p_v
Water vapor pressure unsaturated
Pa

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$T$
T
Absolute temperature
K
$\Delta Q$
DQ
Heat supplied to liquid or solid
J
$n_s$
n_s
Number of moles of saturated water vapor
mol
$n_v$
n_v
Number of moles of water vapor
mol
$RH$
RH
Relative humidity
-

Calculations


First, select the equation: to , then, select the variable: to

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used




Equations

#
Equation

$ \Delta Q = L \Delta m$

DQ = L * Dm


$\Delta v_m =\displaystyle\frac{ \Delta V }{ M_m }$

Dv_m = DV / M_m


$ l_m \equiv\displaystyle\frac{ L }{ M_m }$

l_m = L / M_m


$ p_v \Delta V = n_v R T $

p * V = n * R * T


$ p_s \Delta V = n_s R T $

p * V = n * R * T


$ p_v = c_v R T $

p = c_m * R * T


$ p_s = c_s R T $

p = c_m * R * T


$ p_s = p_{ref} e^{- l_m / R T }$

p_s = p_ref *exp(- l_m / R * T )


$ RH =\displaystyle\frac{ c_v }{ c_s }$

RH = c_v / c_s


$ RH =\displaystyle\frac{ p_v }{ p_s }$

RH = p_v / p_s

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Specific latent heat

Equation

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The evaporated Mass ($\Delta m$) is defined using the latent Heat ($L$) and the phase Change Heat ($\Delta Q$) as follows:

$ \Delta Q = L \Delta m$

$\Delta m$
Evaporated Mass
$kg$
5248
$\Delta Q$
Heat supplied to liquid or solid
$J$
10151
$L$
Latent Heat
$J/kg$
5238

ID:(3200, 0)



Molar latent heat conversion

Equation

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In many cases the latent molar heat is not available but the latent heat that is expressed, for example, in Joules per kilogram (J/Kg). Since the vapor pressure equation works with the latent molar heat we must convert the latent heat into latent molar heat. Since the latter is per mole, it is enough to divide the latent heat L by the molar mass M_m to obtain the latent molar heat

$ l_m \equiv\displaystyle\frac{ L }{ M_m }$

$L$
Latent Heat
$J/kg$
5238
$l_m$
Molar Latent Heat
$J/mol$
9867
$M_m$
Molar Mass
$kg/mol$
6212

In the case of water, the latent heat of evaporation is of the order of L\ sim 2,256\ times 10^6J/kg while the molar mass is M_m\sim 18,g/cm^3 = 0.018,kg/m^3, resulting in a latent molar heat of L_m\sim 40600,J/mol = 40.6,kJ/mol.

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Molar volume

Equation

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The change in volume between the material in two different states can be expressed in moles

$\Delta v_m =\displaystyle\frac{ \Delta V }{ M_m }$

$M_m$
Molar Mass
$kg/mol$
6212
$\Delta v_m$
Variation of molar volume during phase change
$m^3/mol$
9868
$\Delta V$
Volume variation in phase change
$m^3$
5239

to obtain a characteristic indicator of the material.

ID:(12823, 0)



Pressure saturated water vapor

Equation

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The pressure saturated water vapor ($p_s$) can be calculated using the reference pressure ($p_{ref}$), the universal gas constant ($R$), the absolute temperature ($T$) and the molar Latent Heat ($l_m$) according to the following formula:

$ p_s = p_{ref} e^{- l_m / R T }$

$T$
Absolute temperature
$K$
5177
$l_m$
Molar Latent Heat
$J/mol$
9867
$p_s$
Pressure saturated water vapor
$Pa$
4956
$p_{ref}$
Reference pressure
3.65e+10
$Pa$
5121
$R$
Universal gas constant
8.4135
$J/mol K$
4957

Using the Clausius-Clapeyron equation for the gradient of the pressure ($p$) with respect to the absolute temperature ($T$), which depends on the latent Heat ($L$) and the volume variation in phase change ($\Delta V$):

$\displaystyle\frac{ dp }{ dT }=\displaystyle\frac{ L }{ \Delta V T }$



In the case of the phase change from liquid to gas, we can assume that the change in volume is approximately equal to the volume of the vapor. Therefore, we can employ the ideal gas equation with the number of moles ($n$), the volume ($V$), the universal gas constant ($R$), and the water vapor pressure unsaturated ($p_v$):

$$



Since the Clausius-Clapeyron equation can be written as:

$\displaystyle\frac{dp}{dT}=\displaystyle\frac{L}{n}\displaystyle\frac{p}{R T^2}$



Where the molar Latent Heat ($l_m$) ($l_m = L/n$) corresponds to the change in enthalpy during the phase change h (the energy required to form water), we finally have:

$\displaystyle\frac{dp}{dT}=l_m\displaystyle\frac{p}{RT^2}$



If we integrate this equation between the pressure saturated water vapor ($p_s$) and the pressure at point p_0 at temperature T_0, we obtain:

$p_s=p_0e^{l_m/RT_0}e^{-l_m/RT}$



If we evaluate this expression with the data at the critical point:

$p_{ref}=p_0e^{l_m/RT_0}$



We finally have:

$ p_s = p_{ref} e^{- l_m / R T }$

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General gas law (1)

Equation

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The pressure ($p$), the volume ($V$), the absolute temperature ($T$), and the number of moles ($n$) are related by the following equation:

$ p_v \Delta V = n_v R T $

$ p V = n R T $

$T$
Absolute temperature
$K$
5177
$n$
$n_v$
Number of moles of water vapor
$mol$
10371
$p$
$p_v$
Water vapor pressure unsaturated
$Pa$
6215
$R$
Universal gas constant
8.4135
$J/mol K$
4957
$V$
$\Delta V$
Volume variation in phase change
$m^3$
5239

The pressure ($p$), the volume ($V$), the absolute temperature ($T$), and the number of moles ($n$) are related through the following physical laws:

• Boyle's law

$ p V = C_b $



• Charles's law

$\displaystyle\frac{ V }{ T } = C_c$



• Gay-Lussac's law

$\displaystyle\frac{ p }{ T } = C_g$



• Avogadro's law

$\displaystyle\frac{ n }{ V } = C_a $



These laws can be expressed in a more general form as:

$\displaystyle\frac{pV}{nT}=cte$



This general relationship states that the product of pressure and volume divided by the number of moles and temperature remains constant:

$ p V = n R T $



where the universal gas constant ($R$) has a value of 8.314 J/K·mol.

ID:(3183, 1)



General gas law (2)

Equation

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The pressure ($p$), the volume ($V$), the absolute temperature ($T$), and the number of moles ($n$) are related by the following equation:

$ p_s \Delta V = n_s R T $

$ p V = n R T $

$T$
Absolute temperature
$K$
5177
$n$
$n_s$
Number of moles of saturated water vapor
$mol$
10372
$p$
$p_s$
Pressure saturated water vapor
$Pa$
4956
$R$
Universal gas constant
8.4135
$J/mol K$
4957
$V$
$\Delta V$
Volume variation in phase change
$m^3$
5239

The pressure ($p$), the volume ($V$), the absolute temperature ($T$), and the number of moles ($n$) are related through the following physical laws:

• Boyle's law

$ p V = C_b $



• Charles's law

$\displaystyle\frac{ V }{ T } = C_c$



• Gay-Lussac's law

$\displaystyle\frac{ p }{ T } = C_g$



• Avogadro's law

$\displaystyle\frac{ n }{ V } = C_a $



These laws can be expressed in a more general form as:

$\displaystyle\frac{pV}{nT}=cte$



This general relationship states that the product of pressure and volume divided by the number of moles and temperature remains constant:

$ p V = n R T $



where the universal gas constant ($R$) has a value of 8.314 J/K·mol.

ID:(3183, 2)



Presión Vapor de Agua

Equation

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The relative humidity ($RH$) can be expressed in terms of the water vapor pressure unsaturated ($p_v$) and the pressure saturated water vapor ($p_s$) as follows:

$ RH =\displaystyle\frac{ p_v }{ p_s }$

$p_s$
Pressure saturated water vapor
$Pa$
4956
$RH$
Relative humidity
$-$
4951
$p_v$
Water vapor pressure unsaturated
$Pa$
6215

The relationship between the relative humidity ($RH$) with the concentration of water vapor molecules ($c_v$) and saturated water vapor concentration ($c_s$) is expressed as:

$ RH =\displaystyle\frac{ c_v }{ c_s }$



and by relating the pressure ($p$) with the molar concentration ($c_m$), the absolute temperature ($T$), and the universal gas constant ($R$), we obtain:

$ p = c_m R T $



This applies to the vapor pressure of water, where:

$p_v = c_v R T$



and the saturated vapor pressure of water:

$p_s = c_s R T$



resulting in the following equation:

$ RH =\displaystyle\frac{ p_v }{ p_s }$

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Pressure as a function of molar concentration (1)

Equation

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The pressure ($p$) can be calculated from the molar concentration ($c_m$) using the absolute temperature ($T$), and the universal gas constant ($R$) as follows:

$ p_v = c_v R T $

$ p = c_m R T $

$T$
Absolute temperature
$K$
5177
$c_m$
$c_v$
Concentration of water vapor molecules
$mol/m^3$
4950
$p$
$p_v$
Water vapor pressure unsaturated
$Pa$
6215
$R$
Universal gas constant
8.4135
$J/mol K$
4957

When the pressure ($p$) behaves as an ideal gas, satisfying the volume ($V$), the number of moles ($n$), the absolute temperature ($T$), and the universal gas constant ($R$), the ideal gas equation:

$ p V = n R T $



and the definition of the molar concentration ($c_m$):

$ c_m \equiv\displaystyle\frac{ n }{ V }$



lead to the following relationship:

$ p = c_m R T $

ID:(4479, 1)



Pressure as a function of molar concentration (2)

Equation

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The pressure ($p$) can be calculated from the molar concentration ($c_m$) using the absolute temperature ($T$), and the universal gas constant ($R$) as follows:

$ p_s = c_s R T $

$ p = c_m R T $

$T$
Absolute temperature
$K$
5177
$c_m$
$c_s$
Saturated water vapor concentration
$mol/m^3$
4952
$p$
$p_s$
Pressure saturated water vapor
$Pa$
4956
$R$
Universal gas constant
8.4135
$J/mol K$
4957

When the pressure ($p$) behaves as an ideal gas, satisfying the volume ($V$), the number of moles ($n$), the absolute temperature ($T$), and the universal gas constant ($R$), the ideal gas equation:

$ p V = n R T $



and the definition of the molar concentration ($c_m$):

$ c_m \equiv\displaystyle\frac{ n }{ V }$



lead to the following relationship:

$ p = c_m R T $

ID:(4479, 2)



Relative humidity, concentration

Equation

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The relationship between the concentration of water vapor molecules ($c_v$) and saturated water vapor concentration ($c_s$) is referred to as the relative humidity ($RH$). In other words, when a relative humidity of 100% is reached, the existing concentration will be equal to the saturated concentration.

$ RH =\displaystyle\frac{ c_v }{ c_s }$

$c_v$
Concentration of water vapor molecules
$mol/m^3$
4950
$RH$
Relative humidity
$-$
4951
$c_s$
Saturated water vapor concentration
$mol/m^3$
4952

ID:(3175, 0)