Series Resistance

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When several resistors are connected in series, the current is the same in all resistors due to the conservation of loads. Therefore, in each resistance a potential drop equal to the electrical resistance multiplied by the current is experienced and whose sum must be the total potential difference. Therefore, the total resistance of a series of resistors is equal to the sum of these.

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Series resistance (Diagram)

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The diagram representing resistors connected in series has the following form:

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Series resistance

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Al conectarse resistencias R_i en serie en cada una ocurrirá una caída de potencial \Delta\varphi_i cuya suma será igual a la diferencia de potencial total\\n\\n

$\Delta\varphi=\displaystyle\sum_i \Delta\varphi_i$

\\n\\nComo la corriente I es igual en todas las resistencias la ley de Ohm en la i-esima resistencia será\\n\\n

$\Delta\varphi_i=R_i I$

\\n\\nSi se reemplaza esta expresión en la suma de las diferencias de potencial se obtiene\\n\\n

$\Delta\varphi=\displaystyle\sum_i R_iI$



por lo que la resistencia en serie se calcula como la suma de las resistencias individuales con :

$ R_s =\displaystyle\sum_ i R_i $

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Sum of resistors in series (2)

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Since the sum of series resistors is

$ R_s =\displaystyle\sum_ i R_i $



You have to in the case of two resistors:

$ R_s = R_1 + R_2 $

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Sum of resistors in series (3)

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Since the sum of series resistors is

$ R_s =\displaystyle\sum_ i R_i $



You have to in the case of three resistors:

$ R_s = R_1 + R_2 + R_3 $

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Sum of resistors in series (4)

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Since the sum of series resistors is

$ R_s =\displaystyle\sum_ i R_i $



it is necessary that in the case of four resistances:

$ R_s = R_1 + R_2 + R_3 + R_4 $

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Sum of resistors in series (5)

Equation

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Since the sum of series resistors is

$ R_s =\displaystyle\sum_ i R_i $



You have to in the case of five resistors:

$ R_s = R_1 + R_2 + R_3 + R_4 + R_5 $

ID:(3857, 0)



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