Nernst Potential
Storyboard
If a potential is applied to a membrane this will lead to a polarization in which the positive charges move to the negative plate and the negative charges to the positive plate. The difference in concentration however leads to a diffusion that tempts to match the distribution. Nernst's potential is the limit potential over which the applied potential exceeds the tendency to diffuse by polarizing the membrane. For potentials smaller than Nernst's potential, diffusion tends to depolarize the membrane.
ID:(820, 0)
Nernst Potential
Description
If a potential is applied to a membrane this will lead to a polarization in which the positive charges move to the negative plate and the negative charges to the positive plate. The difference in concentration however leads to a diffusion that tempts to match the distribution. Nernst's potential is the limit potential over which the applied potential exceeds the tendency to diffuse by polarizing the membrane. For potentials smaller than Nernst's potential, diffusion tends to depolarize the membrane.
Variables
Calculations
Calculations
Equations
None
(ID 3221)
None
(ID 3222)
None
(ID 3883)
None
(ID 3884)
Examples
If a potential difference
so with
y
with what
| $ j =- \kappa \displaystyle\frac{ dV }{ dx }$ |
(ID 3877)
In the case of ion conduction, conductivity must include the sign of the charge, which is entered with the number of charges
| $ \kappa =\displaystyle\frac{ z }{ \mid z \mid } \mu_e c $ |
where
(ID 3876)
The flow density
| $ j =\displaystyle\frac{ I }{ S }$ |
(ID 3221)
The electron current is the
that is
equation/druyd>
(ID 3222)
The diffusion leads to the difference in concentrations
| $ j =- D \displaystyle\frac{ dc }{ dx }$ |
where
(ID 3878)
The diffusion constant
| $ D =\displaystyle\frac{ \mu_e R_C T }{\mid z \mid F }$ |
(ID 3879)
If there is more than one type of ion, the actual concentration of the ions must be estimated, that is, add the concentrations weighted by the number of charges they have
| $c_m=\sum_i\mid z_i\mid c_i$ |
where
(ID 3883)
In case of a type of load
| $ c_m =\mid z_1 \mid c_1 $ |
where
(ID 3884)
In case of two types of charges
| $ c_m = \mid z_1\mid c_1 + \mid z_2\mid c_2 $ |
where
(ID 3885)
In case of three types of charges
| $ c_m = \mid z_1\mid c_1 + \mid z_2\mid c_2 + \mid z_3\mid c_3 $ |
where
(ID 3886)
The equilibrium condition occurs when the flow due to the potential difference is equal to the flow due to the diffusion. That is why you have to
for what you have
| $ dV =\displaystyle\frac{ R_C T }{ z F }\displaystyle\frac{ dc }{ c }$ |
(ID 3880)
If the potential difference is integrated, the relationship of the potential difference corresponding to the limit in which the electric field is compensated with the Diffusion can be established:
| $ V_m =-\displaystyle\frac{ R_C T }{ F }\ln\displaystyle\frac{ c_1 }{ c_2 }$ |
where
(ID 3881)
ID:(820, 0)
