Diffraction in an Opening
Storyboard
If the light passes through a circular hole, it is observed on a screen that there is a characteristic diffraction pattern around the center beam and the wavelength of light around the central beam.
ID:(1382, 0)
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First, select the equation: to , then, select the variable: to
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Variable Given Calculate Target : Equation To be used
Equations
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Equation
$ \lambda =\displaystyle\frac{1}{1.22} D \sin \theta_1 $
lambda = D *sin( theta_1 )/1.22
$ \lambda =\displaystyle\frac{1}{2.23} D \sin \theta_2 $
lambda = D *sin( theta_2 )/2.23
$ \lambda =\displaystyle\frac{1}{3.24} D \sin \theta_3 $
lambda = D *sin( theta_3 )/3.24
ID:(16087, 0)
First line diffraction in opening
Equation
$ \lambda =\displaystyle\frac{1}{1.22} D \sin \theta_1 $ |
ID:(10951, 0)
Second line diffraction in opening
Equation
$ \lambda =\displaystyle\frac{1}{2.23} D \sin \theta_2 $ |
ID:(10952, 0)
Third line diffraction in opening
Equation
$ \lambda =\displaystyle\frac{1}{3.24} D \sin \theta_3 $ |
ID:(10953, 0)
0
Video
Video: Difracción en una Apertura