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Intercept at constant angular speed

Storyboard

Objects can intersect when they coincide in angle at the same moment. To achieve this, they must move from their respective initial angles with angular velocities that allow them to coincide in angle and time at the end of the journey.

>Model

ID:(1450, 0)



Mechanisms

Iframe

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Code
Concept
Angle and time when intercepting
Angles and travel durations

Mechanisms

Angle and time when interceptingAngles and travel durationsIntercept

ID:(15411, 0)



Concept of intercept

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In the case of an intersection, two bodies are moving in such a way that they will meet at angle of intersection (\theta) at time a intersection time (t).

To achieve this, each body:

• Begins its displacement at the initial time of first object (t_1) at the initial angle of the first body (\theta_1) with a angular velocity of body 1 (\omega_1).
• Begins its displacement at the initial time of second object (t_2) at the initial angle of the second body (\theta_2) with a angular velocity of body 2 (\omega_2).

These conditions must be met to achieve the intersection.

Thus, the angle over time diagrams can be overlaid as shown in the following representation:

ID:(15517, 0)



Angles and travel durations

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In the case of an intersection or collision between two objects, it's common for the angular velocity of body 1 (\omega_1) and the angular velocity of body 2 (\omega_2) to be configured such that they coincide.

This means that the angle traveled by the first body (\Delta\theta_1) and the travel time of first object (\Delta t_1) must result in a angular velocity of body 1 (\omega_1),

\omega_1 \equiv\displaystyle\frac{ \Delta\theta_1 }{ \Delta t_1 }



so that, with the angle traveled by the second body (\Delta\theta_2) and the travel time of second object (\Delta t_2), we get a angular velocity of body 2 (\omega_2),

\omega_2 \equiv\displaystyle\frac{ \Delta\theta_2 }{ \Delta t_2 }



so that they finally coincide in time and space (position):

ID:(15516, 0)



Angle and time when intercepting

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In the case of a movement where two objects intersect, such as the angle of intersection (\theta) and the intersection time (t), it is common for both. Therefore, if for the first object, the initial time of first object (t_1) and the initial angle of the first body (\theta_1) with the angular velocity of body 1 (\omega_1) fulfill:

\theta = \theta_1 + \omega_1 ( t - t_1 )



and for the second object, the initial time of second object (t_2) and the initial angle of the second body (\theta_2) with the angular velocity of body 2 (\omega_2) fulfill:

\theta = \theta_2 + \omega_2 ( t - t_2 )



which is represented as:

ID:(15518, 0)



Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
r
r
Radius
m

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
\theta
theta
Angle of intersection
rad
\Delta\theta_1
Dtheta_1
Angle traveled by the first body
rad
\Delta\theta_2
Dtheta_2
Angle traveled by the second body
rad
\omega_1
omega_1
Angular velocity of body 1
rad/s
\omega_2
omega_2
Angular velocity of body 2
rad/s
\Delta\theta
Dtheta
Difference of Angles
rad
\theta_1
theta_1
Initial angle of the first body
rad
\theta_2
theta_2
Initial angle of the second body
rad
t_1
t_1
Initial time of first object
s
t_2
t_2
Initial time of second object
s
t
t
Intersection time
s
v_1
v_1
Speed of the first object
m/s
v_2
v_2
Speed of the second object
m/s
\Delta t_1
Dt_1
Travel time of first object
s
\Delta t_2
Dt_2
Travel time of second object
s

Calculations


First, select the equation: to , then, select the variable: to
Dt_1 = t - t_1 Dt_2 = t - t_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used
Dt_1 = t - t_1 Dt_2 = t - t_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2




Equations

#
Equation

\Delta t_1 \equiv t - t_1

Dt = t - t_0


\Delta t_2 \equiv t - t_2

Dt = t - t_0


\Delta\theta_1 = \theta - \theta_1

Dtheta = theta - theta_0


\Delta\theta_2 = \theta - \theta_2

Dtheta = theta - theta_0


\omega_1 \equiv\displaystyle\frac{ \Delta\theta_1 }{ \Delta t_1 }

omega_m = Dtheta / Dt


\omega_2 \equiv\displaystyle\frac{ \Delta\theta_2 }{ \Delta t_2 }

omega_m = Dtheta / Dt


\theta = \theta_1 + \omega_1 ( t - t_1 )

theta = theta_0 + omega_0 * ( t - t_0 )


\theta = \theta_2 + \omega_2 ( t - t_2 )

theta = theta_0 + omega_0 * ( t - t_0 )


v_1 = r \omega_1

v = r * omega


v_2 = r \omega_2

v = r * omega

ID:(15422, 0)



Angle Difference (1)

Equation

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To describe the rotation of an object, we need to determine the angle variation (\Delta\theta). This is achieved by subtracting the initial Angle (\theta_0) from the angle (\theta), which is reached by the object during its rotation:

\Delta\theta = \theta - \theta_1

\Delta\theta = \theta - \theta_0

\theta
\theta
Angle of intersection
rad
10307
\Delta\theta
Difference of Angles
rad
5299
\theta_0
\theta_1
Initial angle of the first body
rad
10308
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

ID:(3680, 1)



Angle Difference (2)

Equation

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To describe the rotation of an object, we need to determine the angle variation (\Delta\theta). This is achieved by subtracting the initial Angle (\theta_0) from the angle (\theta), which is reached by the object during its rotation:

\Delta\theta = \theta - \theta_2

\Delta\theta = \theta - \theta_0

\theta
\theta
Angle of intersection
rad
10307
\Delta\theta
Difference of Angles
rad
5299
\theta_0
\theta_2
Initial angle of the second body
rad
10309
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

ID:(3680, 2)



Elapsed time (1)

Equation

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To describe the motion of an object, we need to calculate the time elapsed (\Delta t). This magnitude is obtained by measuring the start Time (t_0) and the the time (t) of said motion. The duration is determined by subtracting the initial time from the final time:

\Delta t_1 \equiv t - t_1

\Delta t \equiv t - t_0

t_0
t_1
Initial time of first object
s
10252
t
t
Intersection time
s
10259
\Delta t
\Delta t_1
Travel time of first object
s
10256
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

ID:(4353, 1)



Elapsed time (2)

Equation

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To describe the motion of an object, we need to calculate the time elapsed (\Delta t). This magnitude is obtained by measuring the start Time (t_0) and the the time (t) of said motion. The duration is determined by subtracting the initial time from the final time:

\Delta t_2 \equiv t - t_2

\Delta t \equiv t - t_0

t_0
t_2
Initial time of second object
s
10253
t
t
Intersection time
s
10259
\Delta t
\Delta t_2
Travel time of second object
s
10257
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

ID:(4353, 2)



Angle for constant angular velocity (1)

Equation

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In the case where the angular velocity is constant, the mean angular velocity (\bar{\omega}) coincides with the value of the initial Angular Speed (\omega_0), so

\bar{\omega} = \omega_0



In this scenario, we can calculate the angle traveled as a function of time by recalling that it is associated with the difference between the current and initial angles, as well as the current and initial time. Therefore, the angle (\theta) is equal to the initial Angle (\theta_0), the initial Angular Speed (\omega_0), the time (t), and the start Time (t_0) as shown below:

\theta = \theta_1 + \omega_1 ( t - t_1 )

\theta = \theta_0 + \omega_0 ( t - t_0 )

\theta
\theta
Angle of intersection
rad
10307
\theta_0
\theta_1
Initial angle of the first body
rad
10308
\omega_0
\omega_1
Angular velocity of body 1
rad/s
10312
t_0
t_1
Initial time of first object
s
10252
t
t
Intersection time
s
10259
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

In the case where the initial Angular Speed (\omega_0) is equal to the mean angular velocity (\bar{\omega}),

\bar{\omega} = \omega_0



Therefore, with the difference of Angles (\Delta\theta), which is equal to the angle (\theta) divided by the initial Angle (\theta_0), we obtain:

\Delta\theta = \theta - \theta_0



And with the time elapsed (\Delta t), which is equal to the time (t) divided by the start Time (t_0), we obtain:

\Delta t \equiv t - t_0



We can rewrite the equation for the mean angular velocity (\bar{\omega}) as:

\bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }



This can be expressed as:

\omega_0 = \omega = \displaystyle\frac{\Delta\theta}{\Delta t} = \displaystyle\frac{\theta - \theta_0}{t - t_0}



Solving for it, we get:

\theta = \theta_0 + \omega_0 ( t - t_0 )

The equation represents a straight line in angle-time space.

ID:(1023, 1)



Angle for constant angular velocity (2)

Equation

>Top, >Model


In the case where the angular velocity is constant, the mean angular velocity (\bar{\omega}) coincides with the value of the initial Angular Speed (\omega_0), so

\bar{\omega} = \omega_0



In this scenario, we can calculate the angle traveled as a function of time by recalling that it is associated with the difference between the current and initial angles, as well as the current and initial time. Therefore, the angle (\theta) is equal to the initial Angle (\theta_0), the initial Angular Speed (\omega_0), the time (t), and the start Time (t_0) as shown below:

\theta = \theta_2 + \omega_2 ( t - t_2 )

\theta = \theta_0 + \omega_0 ( t - t_0 )

\theta
\theta
Angle of intersection
rad
10307
\theta_0
\theta_2
Initial angle of the second body
rad
10309
\omega_0
\omega_2
Angular velocity of body 2
rad/s
10313
t_0
t_2
Initial time of second object
s
10253
t
t
Intersection time
s
10259
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

In the case where the initial Angular Speed (\omega_0) is equal to the mean angular velocity (\bar{\omega}),

\bar{\omega} = \omega_0



Therefore, with the difference of Angles (\Delta\theta), which is equal to the angle (\theta) divided by the initial Angle (\theta_0), we obtain:

\Delta\theta = \theta - \theta_0



And with the time elapsed (\Delta t), which is equal to the time (t) divided by the start Time (t_0), we obtain:

\Delta t \equiv t - t_0



We can rewrite the equation for the mean angular velocity (\bar{\omega}) as:

\bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }



This can be expressed as:

\omega_0 = \omega = \displaystyle\frac{\Delta\theta}{\Delta t} = \displaystyle\frac{\theta - \theta_0}{t - t_0}



Solving for it, we get:

\theta = \theta_0 + \omega_0 ( t - t_0 )

The equation represents a straight line in angle-time space.

ID:(1023, 2)



Mean angular speed (1)

Equation

>Top, >Model


To estimate the displacement of an object, it's necessary to know its the angular Speed (\omega) as a function of the time (t). Therefore, the the mean angular velocity (\bar{\omega}) is introduced, defined as the ratio between the angle variation (\Delta\theta) and the time elapsed (\Delta t).

To measure this, a system like the one shown in the image can be used:



To determine the average angular velocity, a reflective element is placed on the axis or on a disk with several reflective elements, and the passage is recorded to estimate the length of the arc \Delta s and the angle associated with the radius r. Then the time difference when the mark passes in front of the sensor is recorded as \Delta t. The average angular velocity is determined by dividing the angle traveled by the time elapsed.



The equation that describes the average angular velocity is:

\omega_1 \equiv\displaystyle\frac{ \Delta\theta_1 }{ \Delta t_1 }

\bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }

\Delta\theta
\Delta\theta_1
Angle traveled by the first body
rad
10310
\bar{\omega}
\omega_1
Angular velocity of body 1
rad/s
10312
\Delta t
\Delta t_1
Travel time of first object
s
10256
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

The definition of the mean angular velocity (\bar{\omega}) is considered as the angle variation (\Delta\theta),

\Delta\theta = \theta - \theta_0



and the time elapsed (\Delta t),

\Delta t \equiv t - t_0



The relationship between both is defined as the mean angular velocity (\bar{\omega}):

\bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }



It should be noted that the average velocity is an estimation of the actual angular velocity. The main problem is that:

If the angular velocity varies during the elapsed time, the value of the average angular velocity can be very different from the average angular velocity.



Therefore, the key is:

Determine the velocity in a sufficiently short elapsed time to minimize its variation.

ID:(3679, 1)



Mean angular speed (2)

Equation

>Top, >Model


To estimate the displacement of an object, it's necessary to know its the angular Speed (\omega) as a function of the time (t). Therefore, the the mean angular velocity (\bar{\omega}) is introduced, defined as the ratio between the angle variation (\Delta\theta) and the time elapsed (\Delta t).

To measure this, a system like the one shown in the image can be used:



To determine the average angular velocity, a reflective element is placed on the axis or on a disk with several reflective elements, and the passage is recorded to estimate the length of the arc \Delta s and the angle associated with the radius r. Then the time difference when the mark passes in front of the sensor is recorded as \Delta t. The average angular velocity is determined by dividing the angle traveled by the time elapsed.



The equation that describes the average angular velocity is:

\omega_2 \equiv\displaystyle\frac{ \Delta\theta_2 }{ \Delta t_2 }

\bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }

\Delta\theta
\Delta\theta_2
Angle traveled by the second body
rad
10311
\bar{\omega}
\omega_2
Angular velocity of body 2
rad/s
10313
\Delta t
\Delta t_2
Travel time of second object
s
10257
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2

The definition of the mean angular velocity (\bar{\omega}) is considered as the angle variation (\Delta\theta),

\Delta\theta = \theta - \theta_0



and the time elapsed (\Delta t),

\Delta t \equiv t - t_0



The relationship between both is defined as the mean angular velocity (\bar{\omega}):

\bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }



It should be noted that the average velocity is an estimation of the actual angular velocity. The main problem is that:

If the angular velocity varies during the elapsed time, the value of the average angular velocity can be very different from the average angular velocity.



Therefore, the key is:

Determine the velocity in a sufficiently short elapsed time to minimize its variation.

ID:(3679, 2)



Speed and angular speed (1)

Equation

>Top, >Model


If we divide the relationship between the distance traveled in a time (\Delta s) and the radius (r) by the angle variation (\Delta\theta),

\Delta s=r \Delta\theta



and then divide it by the time elapsed (\Delta t), we obtain the relationship that allows us to calculate the speed (v) along the orbit, known as the tangential velocity, which is associated with the angular Speed (\omega):

v_1 = r \omega_1

v = r \omega

\omega
\omega_1
Angular velocity of body 1
rad/s
10312
r
Radius
m
9894
v
v_1
Speed of the first object
m/s
10248
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2


As the mean Speed (\bar{v}) is with the distance traveled in a time (\Delta s) and the time elapsed (\Delta t), equal to

\bar{v} \equiv\displaystyle\frac{ \Delta s }{ \Delta t }



and with the distance traveled in a time (\Delta s) expressed as an arc of a circle, and the radius (r) and the angle variation (\Delta\theta) are

\Delta s=r \Delta\theta



and the definition of the mean angular velocity (\bar{\omega}) is

\bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }



then,

v=\displaystyle\frac{\Delta s}{\Delta t}=r\displaystyle\frac{\Delta\theta}{\Delta t}=r\omega



Since the relationship is general, it can be applied for instantaneous values, resulting in

v = r \omega

.

ID:(3233, 1)



Speed and angular speed (2)

Equation

>Top, >Model


If we divide the relationship between the distance traveled in a time (\Delta s) and the radius (r) by the angle variation (\Delta\theta),

\Delta s=r \Delta\theta



and then divide it by the time elapsed (\Delta t), we obtain the relationship that allows us to calculate the speed (v) along the orbit, known as the tangential velocity, which is associated with the angular Speed (\omega):

v_2 = r \omega_2

v = r \omega

\omega
\omega_2
Angular velocity of body 2
rad/s
10313
r
Radius
m
9894
v
v_2
Speed of the second object
m/s
10249
theta = theta_1 + omega_1 * ( t - t_1 ) theta = theta_2 + omega_2 * ( t - t_2 ) v_1 = r * omega_1 v_2 = r * omega_2 omega_1 = Dtheta_1 / Dt_1 omega_2 = Dtheta_2 / Dt_2 Dtheta_1 = theta - theta_1 Dtheta_2 = theta - theta_2 Dt_1 = t - t_1 Dt_2 = t - t_2 thetaDtheta_1Dtheta_2omega_1omega_2Dthetatheta_1theta_2t_1t_2trv_1v_2Dt_1Dt_2


As the mean Speed (\bar{v}) is with the distance traveled in a time (\Delta s) and the time elapsed (\Delta t), equal to

\bar{v} \equiv\displaystyle\frac{ \Delta s }{ \Delta t }



and with the distance traveled in a time (\Delta s) expressed as an arc of a circle, and the radius (r) and the angle variation (\Delta\theta) are

\Delta s=r \Delta\theta



and the definition of the mean angular velocity (\bar{\omega}) is

\bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }



then,

v=\displaystyle\frac{\Delta s}{\Delta t}=r\displaystyle\frac{\Delta\theta}{\Delta t}=r\omega



Since the relationship is general, it can be applied for instantaneous values, resulting in

v = r \omega

.

ID:(3233, 2)