Druyd:Knowledge

Electric conduction in liquids

Storyboard

In a liquid it is ions and not electrons that lead to current conduction. In this case the resistance is given by the mobility of the ions within the liquid and the resistance must be calculated based on the concentrations of all the components.

>Model

ID:(1509, 0)

Electric conduction in liquids

Model

Variables

Symbol

Text

Variable

Value

Units

Calculate

MKS Value

MKS Units

$Q_i$

Q_i

Charge of the ion i

$c_i$

c_i

Concentration of ions i

mol/m^3

$G$

Conductance

$\kappa_e$

kappa_e

Conductivity

1/Ohm m

$\kappa_i$

kappa_i

Conductivity ions of type i

1/Ohm m

$L$

Conductor length

$m_i$

m_i

Mass of the ion i

$\Lambda_i$

Lambda_i

Molar conductivity ions of type i

m^2/Ohm mol

$R$

Resistance

Ohm

$\rho_e$

rho_e

Resistivity

Ohm m

$S$

Section of Conductors

m^2

$\tau_i$

tau_i

Time between collisions ion i

Calculations

Equation

Number

First, select the equation:

, then, select the variable:

Symbol

Equation

Solved

Translated

Calculations

Symbol

Equation

Solved

Translated

Variable

Given

Calculate

Target :

Equation

To be used

Equations

$ R = \rho_e \displaystyle\frac{ L }{ S }$

R = rho_e * L / S

(ID 3841)

$ G =\displaystyle\frac{1}{ R }$

G =1/ R

(ID 3847)

$ \rho_e =\displaystyle\frac{1}{ \kappa_e } $

rho_e = 1/ kappa_e

(ID 3848)

$ \kappa_e =\displaystyle\sum_i \Lambda_i c_i $

kappa_e =@SUM( Lambda_i * c_i , i )

None

(ID 3849)

$ \Lambda_i =\displaystyle\frac{ Q_i ^2 \tau_i }{2 m_i } $

Lambda_i = Q_i ^2* tau_i /(2 * m_i )

(ID 11817)

$ \kappa_i = \Lambda_i c_i $

kappa_i = Lambda_i * c_i

(ID 11818)

Examples

ID:(1509, 0)