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Simple beam, circular profile
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When deforming a simple beam, that is, a homogeneous beam with a constant cross-sectional shape, a torque is generated in each of its elements, causing it to bend. The deformation can be caused by a torque applied at its ends, at an intermediate point, and/or by a load applied on the beam, including its own weight. The final outcome will depend on the boundary conditions, which can be either fixed or free.
ID:(2094, 0)
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Variable
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MKS Value
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to 
, then, select the variable: 
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to , then, select the variable: to
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Symbol
Equation
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Translated
Calculations
Symbol
Equation
Solved
Translated
Variable 
Given Calculate 
Target : Equation To be used 
Equations
#
Equation
$ I_c = \displaystyle\frac{1}{4} \pi ( R_2 ^4 - R_1 ^4)$
I_c = pi *( R_2 ^4 - R_1 ^4)/4
ID:(15875, 0)
Moment of inertia, circular profile
Equation
Parameters
Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
Variables
Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
Calculations
First, select the equation: to , then, select the variable: to
to , then, select the variable: to
Calculations
Symbol
Equation
Solved
Translated
Calculations
Symbol
Equation
Solved
Translated
Variable Given Calculate Target : Equation To be used Equations
#
Equation
$ I_c = \displaystyle\frac{1}{4} \pi ( R_2 ^4 - R_1 ^4)$
I_c = pi *( R_2 ^4 - R_1 ^4)/4
ID:(15880, 0)