>Model
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$y=\sinh(x)=\displaystyle\frac{1}{2}(e^x-e^{-x})$
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$y=\cosh(x)=\displaystyle\frac{1}{2}(e^x+e^{-x})$
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$y=\tanh(x)=\displaystyle\frac{e^x-e^{-x}}{e^x+e^{-x}}$
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$y=\sinh^{-1}(x)=\ln(x+\sqrt{x^2+1})$
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$y=\cosh^{-1}(x)=\ln(x+\sqrt{x^2-1})$
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$y=\tanh^{-1}(x)=\displaystyle\frac{1}{2}\ln\left(\displaystyle\frac{1+x}{1-x}\right)$
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