The Carnot Cycle

Storyboard

The Carnot cycle is a generic cycle in the pressure-volume space that shows how in principle a thermodynamic machine can be built that converts heat flow into mechanical work.

>Model

ID:(1488, 0)



The Carnot Cycle

Description

The Carnot cycle is a generic cycle in the pressure-volume space that shows how in principle a thermodynamic machine can be built that converts heat flow into mechanical work.

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$Q_C$
Q_C
Absorbed heat
J
$W$
W
Effective work
J
$\eta$
eta
Efficiency
-
$Q_H$
Q_H
Heat supplied
J
$S_H$
S_H
High entropy
J
$T_H$
T_H
High temperature
K
$S_C$
S_C
Low entropy
J/K
$T_C$
T_C
Low temperature
K

Calculations


First, select the equation:   to ,  then, select the variable:   to 

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

 Variable   Given   Calculate   Target :   Equation   To be used



Equations

The efficiency ($\eta$) is a function of the heat supplied ($Q_H$) and the absorbed heat ($Q_C$), given by:

$ \eta = 1-\displaystyle\frac{ Q_C }{ Q_H } $



We can express the heat supplied ($Q_H$) in terms of the low temperature ($T_C$), the low entropy ($S_C$), and the high entropy ($S_H$) as:

$ Q_C = T_C ( S_H - S_C ) $



And using the high temperature ($T_H$) as:

$ Q_H = T_H ( S_H - S_C ) $



If we substitute these expressions, we get:

$ \eta = 1 - \displaystyle\frac{ T_C }{ T_H } $

(ID 11136)

Since the effective work ($W$) is equal to the integral along a closed path in the space of the absolute temperature ($T$) and the entropy ($S$), we have:

$ W = \displaystyle\oint T dS$



Consulting the temperature-entropy graph, we can see that the absorbed heat the heat supplied ($Q_H$) is equal to the high temperature ($T_H$) due to the difference in entropy, i.e., the high entropy ($S_H$) and the low entropy ($S_C$):

$ Q_H = T_H ( S_H - S_C ) $

(ID 11137)

As the effective work ($W$) is equal to the integral along a closed path in the the absolute temperature ($T$) and the entropy ($S$) space, we have:

$ W = \displaystyle\oint T dS$



Consulting the temperature-entropy graph, we can see that the absorbed heat the absorbed heat ($Q_C$) is equal to the low temperature ($T_C$) due to the difference in entropy, i.e., the high entropy ($S_H$) and the low entropy ($S_C$):

$ Q_C = T_C ( S_H - S_C ) $

(ID 11138)

Since the efficiency ($\eta$) with the effective work ($W$) and the heat supplied ($Q_H$) is

$ \eta \equiv \displaystyle\frac{ W }{ Q_H } $



it can be replaced with the effective work ($W$) which, along with the heat supplied ($Q_H$) and the absorbed heat ($Q_C$), results in

$ W = Q_H - Q_C $



yielding the following relationship:

$ \eta = 1-\displaystyle\frac{ Q_C }{ Q_H } $

(ID 11155)


Examples


ID:(1488, 0)