Internal Energy

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The internal energy of a system consists of kinetic energy and potential energy. Kinetic energy is associated with heat and can be linked to the oscillations of atoms around their equilibrium points. On the other hand, potential energy is associated with the work that the system is capable of performing.

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Mechanisms

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Internal energy is the total energy contained within a thermodynamic system due to the kinetic and potential energies of its molecules. It includes the energy from molecular motion (translational, rotational, and vibrational) and the energy from intermolecular interactions and chemical bonds. Internal energy is a state function, meaning it depends only on the current state of the system, not on how the system reached that state. Changes in internal energy occur when heat is added to or removed from the system or when work is done on or by the system. This concept is fundamental in thermodynamics, describing energy changes in processes such as isothermal, adiabatic, isobaric, and isochoric processes. Internal energy helps determine equilibrium states and system stability, as systems tend to move towards states with lower internal energy. It provides a comprehensive measure of all microscopic forms of energy within a system, essential for understanding energy transformations in various processes.

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Concept

Mechanisms

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Kinetic energy

Concept

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Translational kinetic energy: This energy is associated with the linear motion of the particles in the system. The higher the translational velocity of the particles, the greater their translational kinetic energy.

Rotational kinetic energy: Some particles, such as atoms or molecules, can rotate around an axis. This rotation is associated with the rotational kinetic energy, which depends on the mass and angular velocity of the particles.

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Link energy

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Potential energy of binding: This energy is related to the interaction forces between the particles of the system. For example, in a solid, the binding energy is due to the attractive forces between neighboring atoms or molecules.

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Chemical energy

Concept

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Excitation energy: Some systems can undergo changes in their energy state, such as when electrons in an atom or molecule are excited. The energy associated with these excited states is known as excitation energy.

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Excitation energy

Concept

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Chemical energy (electrical energy): In chemical systems, chemical reactions can release or absorb energy. This energy is known as chemical energy and is related to the chemical bonds present in molecules.

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Internal energy

Concept

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The internal energy is the total energy possessed by the particles that make up a system. These energies include:

• Translational kinetic energy: This energy is associated with the linear motion of the particles in the system. The higher the translational velocity of the particles, the greater their translational kinetic energy.

• Rotational kinetic energy: Some particles, such as atoms or molecules, can rotate around an axis. This rotation is associated with the rotational kinetic energy, which depends on the mass and angular velocity of the particles.

• Potential energy of binding: This energy is related to the interaction forces between the particles of the system. For example, in a solid, the binding energy is due to the attractive forces between neighboring atoms or molecules.

• Chemical energy (electrical energy): In chemical systems, chemical reactions can release or absorb energy. This energy is known as chemical energy and is related to the chemical bonds present in molecules.

• Excitation energy: Some systems can undergo changes in their energy state, such as when electrons in an atom or molecule are excited. The energy associated with these excited states is known as excitation energy.

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Model

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Parameters

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$m_i$
m_i
Inertial Mass
kg
$K_r$
K_r
Kinetic energy of rotation
J
$I$
I
Moment of inertia for axis that does not pass through the CM
kg m^2
$V$
V
Potential Energy
J
$E$
E
Total Energy
J
$K$
K
Total Kinetic Energy
J
$K_t$
K_t
Translational Kinetic Energy
J

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$\omega$
omega
Angular Speed
rad/s
$v$
v
Speed
m/s

Calculations


First, select the equation: to , then, select the variable: to

Calculations

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

Variable Given Calculate Target : Equation To be used




Equations

#
Equation

$ E = K + V $

E = K + V


$ K = K_t + K_r $

K = K_t + K_r


$ K_r =\displaystyle\frac{1}{2} I \omega ^2$

K_r = I * omega ^2/2


$ K_t =\displaystyle\frac{1}{2} m_i v ^2$

K_t = m_i * v ^2/2

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Translational Kinetic Energy

Equation

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In the case of studying translational motion, the definition of energy

$ dW = \vec{F} \cdot d\vec{s} $



is applied to Newton's second law

$ F = m_i a $



resulting in the expression

$ K_t =\displaystyle\frac{1}{2} m_i v ^2$

$m_i$
Inertial Mass
$kg$
6290
$v$
Speed
$m/s$
6029
$K_t$
Translational Kinetic Energy
$J$
5288

The energy required for an object to transition from velocity $v_1$ to velocity $v_2$ can be calculated using the definition with

$ dW = \vec{F} \cdot d\vec{s} $



Using the second law of Newton, this expression can be rewritten as

$\Delta W = m a \Delta s = m\displaystyle\frac{\Delta v}{\Delta t}\Delta s$



Employing the definition of velocity with

$ \bar{v} \equiv\displaystyle\frac{ \Delta s }{ \Delta t }$



we obtain

$\Delta W = m\displaystyle\frac{\Delta v}{\Delta t}\Delta s = m v \Delta v$



where the difference in velocities is

$\Delta v = v_2 - v_1$



Furthermore, the velocity itself can be approximated by the average velocity

$v = \displaystyle\frac{v_1 + v_2}{2}$



Using both expressions, we arrive at

$\Delta W = m v \Delta v = m(v_2 - v_1)\displaystyle\frac{(v_1 + v_2)}{2} = \displaystyle\frac{m}{2}(v_2^2 - v_1^2)$



Thus, the change in energy is given by

$\Delta W = \displaystyle\frac{m}{2}v_2^2 - \displaystyle\frac{m}{2}v_1^2$



In this way, we can define kinetic energy

$ K_t =\displaystyle\frac{1}{2} m_i v ^2$

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Kinetic Energy of Rotation

Equation

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In the case being studied of translational motion, the definition of energy

$ \Delta W = T \Delta\theta $



is applied to Newton's second law

$ T = I \alpha $



resulting in the expression

$ K_r =\displaystyle\frac{1}{2} I \omega ^2$

$\omega$
Angular Speed
$rad/s$
6068
$K_r$
Kinetic energy of rotation
$J$
5289
$I$
Moment of inertia for axis that does not pass through the CM
$kg m^2$
5315

The energy required for an object to change its angular velocity from $\omega_1$ to $\omega_2$ can be calculated using the definition

$ \Delta W = T \Delta\theta $



Applying Newton's second law, this expression can be rewritten as

$\Delta W=I \alpha \Delta\theta=I\displaystyle\frac{\Delta\omega}{\Delta t}\Delta\theta$



Using the definition of angular velocity

$ \bar{\omega} \equiv\displaystyle\frac{ \Delta\theta }{ \Delta t }$



we get

$\Delta W=I\displaystyle\frac{\Delta\omega}{\Delta t}\Delta\theta=I \omega \Delta\omega$



The difference in angular velocities is

$\Delta\omega=\omega_2-\omega_1$



On the other hand, angular velocity itself can be approximated with the average angular velocity

$\omega=\displaystyle\frac{\omega_1+\omega_2}{2}$



Using both expressions, we obtain the equation

$\Delta W=I \omega \Delta \omega=I(\omega_2-\omega_1)\displaystyle\frac{(\omega_1+\omega_2)}{2}=\displaystyle\frac{I}{2}(\omega_2^2-\omega_1^2)$



Thus, the change in energy is given by

$\Delta W=\displaystyle\frac{I}{2}\omega_2^2-\displaystyle\frac{I}{2}\omega_1^2$



This allows us to define kinetic energy as

$ K_r =\displaystyle\frac{1}{2} I \omega ^2$

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Total Kinetic Energy

Equation

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Kinetic energy can be of translation and/or rotation. Therefore, the total kinetic energy is the sum of both:

$ K = K_t + K_r $

$K_r$
Kinetic energy of rotation
$J$
5289
$K$
Total Kinetic Energy
$J$
5314
$K_t$
Translational Kinetic Energy
$J$
5288

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Total Energy

Equation

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The total energy corresponds to the sum of the total kinetic energy and the potential energy:

$ E = K + V $

$V$
Potential Energy
$J$
4981
$E$
Total Energy
$J$
5290
$K$
Total Kinetic Energy
$J$
5314

ID:(3687, 0)