Example of application of the method

Description

If we consider the internal energy $U(V,S)$, it depends on two variables:

• The volume $V$
• The entropy $S$

Therefore, its variation can be expressed using the relationship:

$ df = \left(\displaystyle\frac{\partial f }{\partial x }\right)_ y dx + \left(\displaystyle\frac{\partial f }{\partial y }\right)_ x dy $



in the form:

$dU = \left(\displaystyle\frac{\partial U }{\partial V }\right)_ S dV + \left(\displaystyle\frac{\partial U }{\partial S }\right)_ V dS$



According to the first law of thermodynamics, we know that the variation of internal energy $dU$ is equal to:

$ df = \left(\displaystyle\frac{\partial f }{\partial x }\right)_ y dx + \left(\displaystyle\frac{\partial f }{\partial y }\right)_ x dy $



From this, we can conclude that the slopes are the pressure $p$:

$\left(\displaystyle\frac{\partial U }{\partial V }\right)_ S = -p$



and the temperature $T$:

$\left(\displaystyle\frac{\partial U }{\partial S }\right)_ V = T$


ID:(12389, 0)


Ejemplo de potencial termodinámico

Description

To establish the relationships, thermodynamic potentials are introduced, which are potential energies that include or exclude certain forms of energy in a system, such as the energy associated with work $pV$ and the energy associated with entropy $TS$, which cannot be used to perform work.

In the case of enthalpy $H$, it corresponds to the internal energy of the system, which includes the movement of particles, but also incorporates the energy required to form the system, i.e., the work $pV$ done to establish it. Therefore, it is defined as:

$$


ID:(12390, 0)


Forma de trabajar en termodinámica

Description

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$\Gamma$
Gamma
Adiabatic lapse rate
K/Pa
$\rho$
rho
Densidad
kg/m^3
$df$
df
Diferencial de la función termodinámica
-
$dx$
dx
Diferencial de la primera variable termodinámica
-
$dy$
dy
Diferencial de la segunda variable termodinámica
-
$H$
H
Entalpía
J
$h$
h
Entalpía molar
J/kg
$f$
f
Función termodinámica
-
$M_m$
M_m
Masa molar
kg/mol
$g$
g
Molar Gibbs free energy
J/kg
$\mu$
mu
Pendiente de la salinidad
J/kg
$g_x$
g_x
Primera derivada de la energía libre de Gibbs molar
J/kg
$x$
x
Primera variable termodinámica
-
$g_{xy}$
g_xy
Segunda derivada de la energía libre de Gibbs molar
J/kg
$y$
y
Segunda variable termodinámica
-
$c_p$
c_p
Specific heat at constant pressure
J/kg K
$T$
T
Temperature
K
$k_T$
k_T
Thermic dilatation coefficient
1/K
$dh$
dh
Variación de la entalpía molar
J/kg
$ds$
ds
Variación de la entropía
J/K mol
$dp$
dp
Variación de la presión
Pa
$di$
di
Variación de la salinidad
-
$Dh_s$
Dh_s
Variation of molar enthalpy with entropy
K
$Dh_p$
Dh_p
Variation of molar enthalpy with pressure
m^3/kg
$Dh_i$
Dh_i
Variation of molar enthalpy with salinity
J/mol
$Ds_T$
Ds_T
Variation of molar entropy with temperature
J/K mol
$\Delta\alpha$
Dalpha
Variation of specific volume
m^3/kg
$DT_p$
DT_p
Variation of temperature with pressure
K/Pa
$\alpha$
alpha
Volumen especifico
m^3/kg

Calculations


First, select the equation:   to ,  then, select the variable:   to 

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

 Variable   Given   Calculate   Target :   Equation   To be used



Equations

If we compare the differentiation of enthalpy

$ dh = \left(\displaystyle\frac{\partial h }{\partial s }\right)_{ p , i } ds + \left(\displaystyle\frac{\partial h }{\partial p }\right)_{ p , i } dp + \left(\displaystyle\frac{\partial h }{\partial i }\right)_{ p , s } di $



with its variation

$ dh =T ds + \alpha dp + \mu di$



we can conclude that

$ T = \displaystyle\frac{\partial h }{\partial S }$


(ID 12394)

If we compare the differentiation of the enthalpy

$ dh = \left(\displaystyle\frac{\partial h }{\partial s }\right)_{ p , i } ds + \left(\displaystyle\frac{\partial h }{\partial p }\right)_{ p , i } dp + \left(\displaystyle\frac{\partial h }{\partial i }\right)_{ p , s } di $



with its variation

$ dh =T ds + \alpha dp + \mu di$



we can conclude that

$ \alpha = \displaystyle\frac{\partial h }{\partial p } $

(ID 12395)

If we compare the differentiation of the enthalpy

$ dh = \left(\displaystyle\frac{\partial h }{\partial s }\right)_{ p , i } ds + \left(\displaystyle\frac{\partial h }{\partial p }\right)_{ p , i } dp + \left(\displaystyle\frac{\partial h }{\partial i }\right)_{ p , s } di $



with its variation

$ dh =T ds + \alpha dp + \mu di$



we can conclude that

$ \mu = \displaystyle\frac{\partial h }{\partial i }$

.

(ID 12396)

The adiabatic lapse rate, given by

$ \Gamma \equiv \displaystyle\frac{\partial T }{\partial p }$



can be expressed in terms of enthalpy using the relationship

$ T = \displaystyle\frac{\partial h }{\partial S }$



and the relationship

$ \alpha = \displaystyle\frac{\partial h }{\partial p } $



as

$\Gamma =\displaystyle\frac{\partial T}{\partial p}=\displaystyle\frac{\partial}{\partial p}\displaystyle\frac{\partial h}{\partial s}=\displaystyle\frac{\partial}{\partial s}\displaystyle\frac{\partial h}{\partial p}=\displaystyle\frac{\partial \alpha}{\partial s}$




therefore, the adiabatic lapse rate is

$ \Gamma = \displaystyle\frac{ \alpha }{ c_p }$


(ID 12398)

Since the heat capacity at constant pressure is defined through enthalpy as

$c_p=\left(\displaystyle\frac{\partial h }{\partial T }\right)_{ p , i }$



we have

$ T = \displaystyle\frac{\partial h }{\partial S }$



which implies

$c_p=\displaystyle\frac{\partial h}{\partial T}=\displaystyle\frac{\partial h}{\partial s}\displaystyle\frac{\partial s}{\partial T}=T\displaystyle\frac{\partial s}{\partial T}$



thus, we have the relationship

$ \left(\displaystyle\frac{\partial s }{\partial T }\right)_{ p , i } = \displaystyle\frac{ c_p }{ T }$


(ID 12399)

With the adiabatic lapse rate given by

$ \Gamma = \displaystyle\frac{ \alpha }{ c_p }$



we have

$ \left(\displaystyle\frac{\partial s }{\partial T }\right)_{ p , i } = \displaystyle\frac{ c_p }{ T }$



that the adiabatic lapse rate can be written as

$\Gamma=\displaystyle\frac{\partial \alpha }{\partial s }=\displaystyle\frac{\partial \alpha }{\partial T }\displaystyle\frac{\partial T }{\partial s }=\displaystyle\frac{ T }{ c_p }\displaystyle\frac{\partial \alpha }{\partial T }$



we have

$ \Gamma = \displaystyle\frac{ T }{ c_p } \displaystyle\frac{ \partial \alpha }{ \partial T } $


(ID 12400)

With the definition of the specific volume

$ \alpha = \displaystyle\frac{1}{ \rho }$



and the relationship for thermal expansion given by

$ k_T =\displaystyle\frac{1}{ \alpha_T }\left(\displaystyle\frac{ \partial\alpha_T }{ \partial T }\right)_{ p , i }$



the derivative of the specific volume with respect to the adiabatic lapse rate, expressed as

$ \Gamma = \displaystyle\frac{ T }{ c_p } \displaystyle\frac{ \partial \alpha }{ \partial T } $



can be expressed as

$ \Gamma = \displaystyle\frac{ T }{ c_p }\displaystyle\frac{ k_T }{ \rho }$


(ID 12401)


Examples

Thermodynamics is the science of 'small steps', where one explores the behavior of a physical system by making variations on known functions f. To do this:

- The dependence of a function on parameters (e.g., $x$ and $y$) is determined, that is, $f(x, y)$.
- Each of these parameters is varied (e.g., $dx$ and $dy$), and the corresponding slope of the variation is identified.
- The aim is to find the relationship between the slope and the already established relationships within thermodynamics.

Mathematically, this is expressed as :

$ df = \left(\displaystyle\frac{\partial f }{\partial x }\right)_ y dx + \left(\displaystyle\frac{\partial f }{\partial y }\right)_ x dy $



The expression

$D_{x, y}f\equiv\left(\displaystyle\frac{\partial f }{\partial x }\right)_ y$



represents the slope in the x-direction with the other variables held constant (in this case, y). It is read as 'partial derivative of f with respect to x, with y held constant'.

(ID 12388)

In order to calculate the various parameters, it is necessary to be able to differentiate the Gibbs potential, which corresponds to the slopes of this function with respect to pressure or temperature.

In general, the Gibbs potential factors, denoted as $g_x$, are defined with $x$ representing the variable and $g$ representing the molar Gibbs free energy, as follows:

$ g_x =\displaystyle\frac{\partial g }{\partial x }$


(ID 12356)

For the calculation of various parameters, it is necessary to be able to take second-order derivatives of the Gibbs potential, which corresponds to the curvatures of this function with respect to pressure and/or temperature.

In general, the factors of the Gibbs potential are defined as follows:

$ g_{xy} =\displaystyle\frac{\partial^2 g }{\partial x \partial y }$


(ID 12357)

If we consider the internal energy $U(V,S)$, it depends on two variables:

• The volume $V$
• The entropy $S$

Therefore, its variation can be expressed using the relationship:

$ df = \left(\displaystyle\frac{\partial f }{\partial x }\right)_ y dx + \left(\displaystyle\frac{\partial f }{\partial y }\right)_ x dy $



in the form:

$dU = \left(\displaystyle\frac{\partial U }{\partial V }\right)_ S dV + \left(\displaystyle\frac{\partial U }{\partial S }\right)_ V dS$



According to the first law of thermodynamics, we know that the variation of internal energy $dU$ is equal to:

$ df = \left(\displaystyle\frac{\partial f }{\partial x }\right)_ y dx + \left(\displaystyle\frac{\partial f }{\partial y }\right)_ x dy $



From this, we can conclude that the slopes are the pressure $p$:

$\left(\displaystyle\frac{\partial U }{\partial V }\right)_ S = -p$



and the temperature $T$:

$\left(\displaystyle\frac{\partial U }{\partial S }\right)_ V = T$


(ID 12389)

To establish the relationships, thermodynamic potentials are introduced, which are potential energies that include or exclude certain forms of energy in a system, such as the energy associated with work $pV$ and the energy associated with entropy $TS$, which cannot be used to perform work.

In the case of enthalpy $H$, it corresponds to the internal energy of the system, which includes the movement of particles, but also incorporates the energy required to form the system, i.e., the work $pV$ done to establish it. Therefore, it is defined as:

$$


(ID 12390)

In addition to the thermodynamic potential itself, its molar version can be defined by simply dividing its magnitude by the molar mass. In the case of enthalpy $H$, this is defined as

$ h = \displaystyle\frac{ H }{ M_{mol} }$



where $M_m$ is the molar mass.

(ID 12391)

The enthalpy depends on the pressure $p$, entropy $h$, and in our case, also on the salt concentration $i$. Therefore, the respective differences $dh$, $dp$, and $di$ must satisfy:

$ dh = \left(\displaystyle\frac{\partial h }{\partial s }\right)_{ p , i } ds + \left(\displaystyle\frac{\partial h }{\partial p }\right)_{ p , i } dp + \left(\displaystyle\frac{\partial h }{\partial i }\right)_{ p , s } di $


(ID 12392)

It has been determined that the molar enthalpy $h$ varies as a function of molar entropy $s$, pressure $p$, and salinity $i$ as follows:

$ dh =T ds + \alpha dp + \mu di$


(ID 12393)

The slope of the molar enthalpy $h$ with respect to entropy is equal to the temperature $T$:

$ T = \displaystyle\frac{\partial h }{\partial S }$


(ID 12394)

The slope of the molar enthalpy $h$ with respect to entropy is equal to the pressure $p$:

$ \alpha = \displaystyle\frac{\partial h }{\partial p } $


(ID 12395)

The slope of the molar enthalpy $h$ with respect to entropy is equal to salinity $s$:

$ \mu = \displaystyle\frac{\partial h }{\partial i }$


(ID 12396)

The stability of seawater is characterized by the so-called adiabatic lapse rate, which is directly related to the problem of temperature and salinity gradients that can destabilize the marine water column.

The adiabatic lapse rate is defined as:

$ \Gamma \equiv \displaystyle\frac{\partial T }{\partial p }$


(ID 12397)

The adiabatic lapse rate can be calculated using the effective volume $\alpha$ and the specific heat at constant pressure $c_p$ as follows:

$ \Gamma = \displaystyle\frac{ \alpha }{ c_p }$



(ID 12398)

The molar entropy varies with temperature according to the following relationship:

$ \left(\displaystyle\frac{\partial s }{\partial T }\right)_{ p , i } = \displaystyle\frac{ c_p }{ T }$


(ID 12399)

The adiabatic lapse rate can be calculated using the equation:

$ \Gamma = \displaystyle\frac{ T }{ c_p } \displaystyle\frac{ \partial \alpha }{ \partial T } $



where $T$ is the temperature, $c_p$ is the specific heat capacity at constant pressure, and $\partial\alpha/\partial T$ is the variation of the relative volume with respect to temperature.

(ID 12400)

The adiabatic lapse rate can be calculated using the temperature $T$, the specific heat capacity at constant pressure $c_p$, the thermal expansion coefficient $k_T$, and the density $\rho$, as follows:

$ \Gamma = \displaystyle\frac{ T }{ c_p }\displaystyle\frac{ k_T }{ \rho }$


(ID 12401)


ID:(1650, 0)