Ejemplo de Energías

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ID:(686, 0)


Ejemplo de Energías

Description

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units
$x$
x
Elongation of the Spring
m
$m_g$
m_g
Gravitational mass
kg
$h_1$
h_1
Height 1
m
$h_2$
h_2
Height 2
m
$z$
z
Height above Floor
m
$k$
k
Hooke Constant
N/m
$M$
M
Mass
kg
$s_1$
s_1
Position 1
m
$s_2$
s_2
Position 2
m
$V$
V
Potential Energy
J

Calculations


First, select the equation:   to ,  then, select the variable:   to 

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

 Variable   Given   Calculate   Target :   Equation   To be used



Equations

As the gravitational force is

$ F_g = m_g g $



with $m$ representing the mass. To move this mass from a height $h_1$ to a height $h_2$, a distance of

$ V = m g ( h_2 - h_1 )$



is covered. Therefore, the energy

$ dW = \vec{F} \cdot d\vec{s} $



with $\Delta s=\Delta h$ gives us the variation in potential energy:

$\Delta W = F\Delta s=mg\Delta h=mg(h_2-h_1)=U_2-U_1=\Delta V$



thus, the gravitational potential energy is

$ V = - m_g g z $


(ID 3245)

En el caso el stico (resorte) la fuerza es

$$



con k la constante del resorte y x la elongaci n/compresi n del resorte. La variaci n de la energ a potencial es

$ dW = \vec{F} \cdot d\vec{s} $

\\n\\nLa diferencia\\n\\n

$\Delta x = x_2 - x_1$

\\n\\ncorresponde al camino recorrido por lo que\\n\\n

$\Delta W=k,x,\Delta x=k(x_2-x_1)\displaystyle\frac{(x_1+x_2)}{2}=\displaystyle\frac{k}{2}(x_2^2-x_1^2)$



y con ello la energ a potencial el stica es

$ V =\displaystyle\frac{1}{2} k x ^2$


(ID 3246)

When an object moves from a height $h_1$ to a height $h_2$, it covers the difference in height

$h = h_2 - h_1$



thus, the potential energy

$ V = - m_g g z $



becomes equal to

$ V = m g ( h_2 - h_1 )$


(ID 7111)


Examples

At the surface of the planet, the gravitational force is

$ F_g = m_g g $



and the energy

$ dW = \vec{F} \cdot d\vec{s} $



can be shown to be

$ V = - m_g g z $


(ID 3245)

To lift an object from height $h_1$ to a height $h_2$, energy is required, which we will call gravitational potential energy

$ V = - m_g g z $



and which is proportional to the gained height:

$ V = m g ( h_2 - h_1 )$


(ID 7111)

The elongation $\Delta x$ of a spring is calculated as the difference between its original position $x_1$ and its current position $x_2$, which is expressed as

$ V =\displaystyle\frac{1}{2} k ( x_2 ^2- x_1 ^2)$



It is commonly defined that if a spring is stretched, the elongation is positive, and if it is compressed, it is negative.

(ID 7112)

En el caso el stico (resorte) la fuerza es

$$



la energ a

$ dW = \vec{F} \cdot d\vec{s} $



se puede mostrar que en este caso es

$ V =\displaystyle\frac{1}{2} k x ^2$

(ID 3246)


ID:(686, 0)