Killing Cancer

Description

ID:(1491, 0)


DNA chain

Description

ID:(2702, 0)


Damage by Ionizing Radiation

Description

ID:(1492, 0)


Direct Method

Description

ID:(240, 0)


oncology005

Description


![oncology005](showImage.php)

oncology005

ID:(7374, 0)


Indirect Method

Description

ID:(241, 0)


oncology006

Description


![oncology006](showImage.php)

oncology006

ID:(7375, 0)


oncology016

Description


![oncology016](showImage.php)

oncology016

ID:(7385, 0)


oncology017

Description


![oncology017](showImage.php)

oncology017

ID:(7386, 0)


oncology018

Description


![oncology018](showImage.php)

oncology018

ID:(7387, 0)


Probability to Impact the Core

Description

ID:(239, 0)


Probability to Impact Chromosome

Description

ID:(847, 0)


Probability to Impact DNA

Description

ID:(848, 0)


Probability of DNA Damage

Description

ID:(849, 0)


Types of DNA Damage

Description

ID:(1722, 0)


Electron LET

Description

ID:(1503, 0)


Examples of LET

Description

ID:(1486, 0)


Situation in Tissue

Description

ID:(1502, 0)


Survival of Cells

Description

ID:(2708, 0)


Daño mediante Radiación Ionizante

Description

Variables

Symbol
Text
Variable
Value
Units
Calculate
MKS Value
MKS Units

Calculations


First, select the equation:   to ,  then, select the variable:   to 

Symbol
Equation
Solved
Translated

Calculations

Symbol
Equation
Solved
Translated

 Variable   Given   Calculate   Target :   Equation   To be used



Equations


Examples

(ID 2702)


![oncology005](showImage.php)

oncology005

(ID 7374)


![oncology006](showImage.php)

oncology006

(ID 7375)


![oncology016](showImage.php)

oncology016

(ID 7385)


![oncology017](showImage.php)

oncology017

(ID 7386)


![oncology018](showImage.php)

oncology018

(ID 7387)

(ID 1503)

El camino medio que recorre una part cula por una esfera se puede calcular primero considerando el camino medio en un disco de radio $r$ en el plano $y-z$ lo que es

$\bar{r}_2=\displaystyle\frac{2\int_0^r\sqrt{r^2-z`2}dz}{\int_0^r dz}=\displaystyle\frac{\pi r}{2}$

para luego promediar este valor en el eje $x$ considerando que la cantidad de puntos es proporcional a la altura de la esfera por lo que

$\bar{r}_3=\displaystyle\frac{\int_0^r\sqrt{r^2-x^2}\displaystylefrac{\sqrt{r^2-x^2}\pi}{2}dx}{\int_0^r \sqrt{r^2-x^2}dx}=\displaystyle\frac{\pi r^2}{2}=\displaystyle\frac{4}{3\pi}r$

lo que equivale a aproximadamente $42\%$ del radio $r$.

(ID 7400)


ID:(734, 0)